1 và 13/15 . (0,5) mũ 2 .3 +(8/15-1 và 19/60) : 1 và 23/24
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( Hỗn số có thể viết thành a + b/c ( đối với hỗn số âm thì không). VD: \(1\frac{1}{2}=1+\frac{1}{2}\)) mà chỗ và là chỉ hỗn số phải chứ, xem đầu bài mk viết như vậy có đúng không nha bn, nếu ko thì nhắn tin cho mk, để mk sửa nhé!
\(B=1+[\frac{13}{15.\left(0,5\right)^2.3}+\left(\frac{8}{15-1}+\frac{19}{60}\right):1]+\frac{23}{24}\)
\(B=1+\left[\frac{13}{11,25}+\left(\frac{4}{7}+\frac{19}{60}\right)\right]+\frac{23}{24}\)
\(B=1+\left[\frac{52}{45}+\frac{373}{420}\right]+\frac{23}{24}\)
\(B=1+2+\frac{11}{252}+\frac{23}{24}\)
\(B=3+1+\frac{1}{504}\)
\(B=4+\frac{1}{504}\)
\(B=4\frac{1}{504}\)
Giải:
a) \(\left(9\dfrac{4}{9}+5\dfrac{2}{3}\right)-5\dfrac{1}{2}\)
\(=\left(\dfrac{85}{9}+\dfrac{17}{3}\right)-\dfrac{11}{2}\)
\(=\dfrac{136}{9}-\dfrac{11}{2}\)
\(=\dfrac{173}{18}\)
b) \(\dfrac{13}{9}.\dfrac{15}{4}-\dfrac{13}{9}.\dfrac{7}{4}-\dfrac{13}{9}.\dfrac{5}{4}\)
\(=\dfrac{13}{9}.\left(\dfrac{15}{4}-\dfrac{7}{4}-\dfrac{5}{4}\right)\)
\(=\dfrac{13}{9}.\dfrac{3}{4}\)
\(=\dfrac{13}{12}\)
c) \(\dfrac{2}{3}+\dfrac{5}{8}-\dfrac{-1}{3}+0,375\)
\(=\left(\dfrac{2}{3}-\dfrac{-1}{3}\right)+\left(\dfrac{5}{8}+\dfrac{3}{8}\right)\)
\(=1+1\)
\(=2\)
d) \(75\%-3\dfrac{1}{2}+1,5:\dfrac{10}{7}\)
\(=\dfrac{3}{4}+\dfrac{7}{2}+\dfrac{3}{2}:\dfrac{10}{7}\)
\(=\dfrac{3}{4}+\dfrac{7}{2}+\dfrac{21}{20}\)
\(=\dfrac{53}{10}\)
e) \(1\dfrac{13}{15}.\left(0,5\right)^2.3+\left(\dfrac{8}{15}-1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
\(=\dfrac{28}{15}.\dfrac{1}{4}.3+\left(\dfrac{8}{15}-\dfrac{79}{60}\right):\dfrac{47}{24}\)
\(=\dfrac{7}{5}+\dfrac{-47}{60}:\dfrac{47}{24}\)
\(=\dfrac{7}{5}+\dfrac{-2}{5}\)
\(=1\)
Giải:
\(1\dfrac{13}{15}.\left(0,5\right)^2.3+\left(\dfrac{8}{15}-1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
\(=\dfrac{28}{15}.\dfrac{1}{4}.3+\left(\dfrac{8}{15}-\dfrac{79}{60}\right):\dfrac{47}{24}\)
\(=\dfrac{7}{5}+\left(-\dfrac{47}{60}\right).\dfrac{24}{47}\)
\(=\dfrac{7}{5}+\left(-\dfrac{2}{5}\right)\)
\(=\dfrac{7}{5}-\dfrac{2}{5}\)
\(=1\)
Vậy ...
\(1\dfrac{13}{15}\cdot\left(0,5\right)^2+3\cdot\left(\dfrac{8}{15}+1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
\(=\dfrac{28}{15}\cdot\dfrac{1}{4}+3\cdot\left(\dfrac{8}{15}+\dfrac{79}{60}\right):\dfrac{47}{24}\)
\(=\dfrac{7}{15}+3\cdot\dfrac{37}{20}\cdot\dfrac{24}{47}\)
\(=\dfrac{7}{15}+\dfrac{666}{235}=\dfrac{2327}{705}\)
\(1\dfrac{13}{15}.\left(0,5\right)^2+3.\left(\dfrac{8}{15}+1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
\(=\dfrac{28}{15}.\dfrac{1}{4}+3.\left(\dfrac{8}{15}+\dfrac{79}{60}\right):\dfrac{47}{24}\)
\(=\dfrac{7}{15}+3.\dfrac{37}{20}:\dfrac{47}{24}\)
\(=\dfrac{7}{15}+\dfrac{666}{235}\)
\(=\dfrac{2327}{705}\)
1\(\dfrac{13}{15}.\left(0,5\right)^2.3+\left(\dfrac{8}{15}-1\dfrac{19}{60}\right):1\dfrac{23}{24}\)
\(\dfrac{28}{25}.\dfrac{1}{4}.3+\left(\dfrac{8}{15}-\dfrac{79}{60}\right):\dfrac{47}{24}\)
= \(\dfrac{118}{100}.\dfrac{25}{100}.3+\left(-\dfrac{47}{60}\right):\dfrac{47}{24}\)
= \(\dfrac{177}{200}+-\dfrac{2}{5}\)
= \(\dfrac{177}{200}+-\dfrac{80}{200}=\dfrac{97}{200}\)
mẹ mua về một chai dầu .sau khi dùng 1