Question

[Trần Long]

 

Answer 1

[Toru]

\(A=x(x-1)-x+13\\=x^2-x-x+13\\=(x^2-2x+1)+12\\=(x-1)^2+12\)

Ta thấy: \(\left(x-1\right)^2\ge0\forall x\)

\(\Rightarrow\left(x-1\right)^2+12\ge12\forall x\Rightarrow A\ge12\forall x\)

Dấu \("="\) xảy ra khi: \(x-1=0\Leftrightarrow x=1\)

Vậy \(Min_A=12\) tại \(x=1\).