12+3-14=
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Lời giải:
\(\frac{-3}{14}+\frac{-12}{25}.\frac{-3}{14}+(\frac{-3}{14})^1\\
=\frac{-3}{14}+\frac{-12}{25}.\frac{-3}{14}+\frac{-3}{14}\\
=\frac{-3}{14}(1+\frac{-12}{25}+1)=\frac{-3}{14}.\frac{38}{25}=\frac{-57}{175}\)
[-7/12].5/14+9/14.[-7/12]-(-3/4)
= -7/12. ( 5/14 + 9/14) + 3/4
=-7/12. 1 + 3/4
= -7/12+ 3/4
=1/6
(-12)+(-9)+(-3)+(-8)
= - ( 12 + 9 + 3 + 8 )
= - 32
(-14)+(-7)+(-12)+(-21)
= - ( 14 + 7 + 12 + 21 )
= -54
(-3)+(-11)+(-14)+(-2)
= - ( 3 + 11 + 14 + 2 )
= -30
1: =1-1+5-5+7-7+8-8=0
2: =14-23+5+14-5+23+17
=28+17=45
3: =12-12+9-9+14-44-3=-33
4: =22-8-8-12+4
=22-16-8
=-2
Bài \(1\)
\(1)\) \(1-5+7-8+4-1+5-7+8\)
\(=(1-1)+(5-5)+(7-7)+(8-8)\)
\(=0+0+0+0\)
\(=0\)
\(2)\) \(14-23+(5+14)-(5-23)+17\)
\(=14-23+5+14-5+23+17\)
\(=(14+14)+(23-23)+(5-5)+17\)
\(=28+17\)
\(=45\)
\(3)\) \(12-44+9-3+14-19-9-12\)
\(=(12-12)+(9-9)+(14-44)+3\)
\(=-30+3\)
\(=-33\)
\(4)\) \(22-(4-8+12)+(-8-12+4)\)
\(=22-4+8-12-8-12+4\)
\(=22+(4+4)+(8-8)+(-12-12)\)
\(=22-24\)
\(=-2\)
12/36 = 12 :12 / 36 : 12 = 1/3
14/28 = 14 : 14 / 28 : 14 = 1/2
\(\left[\left(3^{14}\times69+3^{14}\times12\right):3^{16}-7\right]:2^4\)
\(=\left[3^{14}\left(69+12\right):3^{16}-7\right]:2^4\)
\(=\left[3^{14}.81:3^{16}-7\right]:2^4\)
\(=\left[3^{14}.3^4:3^{16}-7\right]:2^4\)
\(=\left[3^2-7\right]:2^4\)
\(=2:2^4\)
\(=\dfrac{2}{16}=\dfrac{1}{8}\)
\(\left[\left(3^{14}.69+3^{14}.12\right):3^{16}-7\right]:2^4\\ =\left[3^{14}.\left(69+12\right):3^{16}-7\right]:2^4\\ =\left[3^{14}.81:3^{16}-7\right]:2^4\\ =\left[3^{14}.3^4:3^{16}-7\right]:2^4\\ =\left(3^2-7\right):2^4=2:2^4=\dfrac{1}{2^3}=\dfrac{1}{8}\)
(-2/11+ 3/12 +-4/13 +5/14) : (-4/11 + 6/12+ -8/13 +10/14)0000000000000000000000000000000000000= 0
a.3-(-12+3)+x=x-(-12-10)
<=> 3+9+x=x+22
<=>x-x=22-3-9
<=> 0x=10
b,2-x=14-(x+4)
<=>2-x=14-x-4)
<=>x-x=14-4-2
<=>0x=8
c.x-12=14+(6-x)
<=>x-12=14+6-x
<=>x+x=14+6+12
<=>0x=32
=1
Bằng 1