Rút gọn thân số
39/52 =
45/48 =
75/90 =
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\(\frac{39}{75}=\frac{39:3}{75:3}=\frac{13}{25}\)
\(\frac{48}{78}=\frac{48:6}{78:6}=\frac{8}{13}\)
\(\frac{120}{90}=\frac{120:30}{90:30}=\frac{4}{3}\)
_HT_
\(\dfrac{48}{78}=\dfrac{48:6}{78:6}=\dfrac{8}{13}\)
\(\dfrac{39}{75}=\dfrac{39:3}{75:3}=\dfrac{13}{25}\)
\(\dfrac{120}{90}=\dfrac{120:30}{90:30}=\dfrac{4}{3}\)
\(\dfrac{14}{21}=\dfrac{7\cdot2}{7\cdot3}=\dfrac{2}{3}\)
\(\dfrac{-36}{48}=\dfrac{-12\cdot3}{12\cdot4}=-\dfrac{3}{4}\)
\(\dfrac{28}{-52}=\dfrac{7\cdot4}{-4\cdot13}=-\dfrac{7}{13}\)
\(\dfrac{-54}{-90}=\dfrac{-18\cdot3}{-18\cdot5}=\dfrac{3}{5}\)
\(\dfrac{14}{21}\) =\(\dfrac{2}{3}\)
\(\dfrac{-36}{48}\) =\(\dfrac{3}{4}\)
\(\dfrac{28}{-52}\)=\(\dfrac{7}{-13}\)
\(\dfrac{-54}{-90}\) =\(\dfrac{6}{9}=\dfrac{2}{3}\)
14/21=2/3; -36/48=-2/3
28/-52=-7/13; -54/-90=3/5
-21/39=-7/13
-21/39=-7/13=-14/26=-21/39=-28/52=-35/65=-42/78=-48/91
`14/21=2/3`
`(-36)/48=-3/4`
`28/(-52)=-7/13`
`(-54)/(-90)=3/5`
`(-21)/39=-7/13`
\(A=\sqrt{12}+2\sqrt{27}+3\sqrt{45}-9\sqrt{48}\)
\(=2\sqrt{3}+6\sqrt{3}+9\sqrt{5}-36\sqrt{3}\)
\(=9\sqrt{5}-28\sqrt{3}\)
\(B=\left(\sqrt{48}-2\sqrt{75}+\sqrt{108}-\sqrt{147}\right):\sqrt{3}\)
\(=4-2\cdot5+6-7\)
\(=4-10+6-7\)
=-7
A=\(\sqrt{12}\)+2\(\sqrt{27}\)+3\(\sqrt{45}\) -9\(\sqrt{48}\)
=\(\sqrt{4.3}\) +2\(\sqrt{9.3}\)+3\(\sqrt{9.5}\) -9\(\sqrt{16.3}\)
=2\(\sqrt{3}\) +6\(\sqrt{3}\)+9\(\sqrt{5}\) -36\(\sqrt{3}\)
=\(\sqrt{3}\)(2+6-36) + 9\(\sqrt{5}\)
=9\(\sqrt{5}\)- 28\(\sqrt{3}\)
(45*46+47*48)*(51*52-49*48)*(45*128-90*64)*(1995*1996+1997*1998) = 0
(45·46+47·48)·(51·52−49·48)·(45·128−90·64)·(1995·1996+1997·1998)
=(45·46+47·48)·(51·52−49·48)·(45·2·64−90·64)·(1995·1996+1997·1998)
=(45·46+47·48)·(51·52−49·48)·(90·64−90·64)·(1995·1996+1997·1998)
=(45·46+47·48)·(51·52−49·48)·0·(1995·1996+1997·1998)
=0
(39:13)/(52:13)=3/4
(45:3)/(48:3)=15/16
(75:15)/(90/15)=5/6
\(\dfrac{39}{52}=\dfrac{3\times13}{4\times13}=\dfrac{3}{4}\)
\(\dfrac{45}{48}=\dfrac{3\times15}{3\times16}=\dfrac{15}{16}\)
\(\dfrac{75}{90}=\dfrac{15\times5}{15\times6}=\dfrac{5}{6}\)