1,4 x 15/49 + 4/5+ 2/3:21/5.
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\(\left(-\frac{x}{5}+\frac{2}{3}\right):\frac{11}{5}=\frac{5}{21}+\frac{3}{7}\)
\(-\frac{x}{5}+\frac{2}{3}=\frac{68}{77}\times\frac{11}{5}\)
\(-\frac{x}{5}=\frac{68}{35}-\frac{2}{3}\)
\(-\frac{x}{5}=\frac{134}{105}\)
=>105(-x)=134*5
=>-105x=670
=>x=\(-\frac{134}{21}\)
a: \(=\dfrac{7}{5}\cdot\dfrac{15}{49}-\dfrac{12+10}{15}:\dfrac{11}{5}\)
\(=\dfrac{3}{7}-\dfrac{22}{15}\cdot\dfrac{5}{11}=\dfrac{3}{7}-\dfrac{2}{3}=\dfrac{9-14}{21}=\dfrac{-5}{21}\)
b: =>2,8x-32=-60
=>2,8x=-28
hay x=-10
\(1,4x\frac{15}{49}-\left(\frac{4}{5}+\frac{2}{3}\right):2\frac{1}{5}\)
\(=\frac{3}{7}-\frac{22}{15}:2\frac{1}{5}\)
\(=\frac{3}{7}-\frac{2}{3}=-\frac{5}{21}\)
học tốt ~~~
\(1,4\times\frac{15}{49}-\left(\frac{4}{5}+\frac{2}{3}\right)\div2\frac{1}{5}\)
\(=\frac{14}{10}\times\frac{15}{49}-\frac{22}{15}\div\frac{11}{5}\)
\(=\frac{7}{5}\times\frac{15}{49}-\frac{22\times5}{15\times11}\)
\(=\frac{7\times15}{5\times49}-\frac{22\times5}{15\times11}\)
\(=\frac{7\times7\times3\times5}{5\times7\times7}-\frac{11\times2\times5}{3\times5\times11}\)
\(=3-\frac{2}{3}\)
\(=\frac{7}{3}\)
Giải:
B=1,4 .15/49 - (4/5+2/3) :2 1/5
B=7/5.15/49 - 22/15 : 11/5
B=3/7 - 2/3
B=-5/21
Chúc bạn học tốt!
(x/-5+2/3);11/5-1,4.15/49=|-5|/21
(x/-5+2/3);11/5-1,4.15/49=5/21
(x/-5+2/3);11/5-21/49=5/21
(x/-5+2/3);11/5=5/21+21/49
(x/-5+2/3);11/5=35/147+63/147
(x/-5+2/3);11/5=35+63/147
(x/-5+2/3);11/5=98/147
x/-5+2/3=98/147.11/5
x/-5+2/3=98.11/147.5
x/-5+2/3=1078/735
x/-5+2/3=154/105
x/-5=154/105-2/3
x/-5=154/105-70/105
x/-5=154-70/105
x/-5=84/105
x/-5=-4/-5
suy ra x=-4
1,4 x 15/49 + 4/5 + 2/3 : 21/5
= 3/7 + 4/5 + 10/63
= 3/7 + 10/63 + 4/5
= 37/63 + 4/5
= 437/315