Question

[Kiệt A]

Giúp Mình Với

Answer 1

[Đoàn Đức Hà]

Bài 1: 

a) \(3\left(2x-5\right)=4x-7\Leftrightarrow6x-15=4x-7\Leftrightarrow2x=8\Leftrightarrow x=4\).

c) \(\frac{4}{x+2}+\frac{5}{x-2}=\frac{x-6}{x^2-4}\)(ĐK: \(x\ne\pm2\))

\(\Leftrightarrow\frac{4\left(x-2\right)+5\left(x+2\right)}{\left(x+2\right)\left(x-2\right)}=\frac{x-6}{\left(x+2\right)\left(x-2\right)}\)

\(\Rightarrow9x+2=x-6\)

\(\Leftrightarrow x=-1\left(tm\right)\)

Answer 2

[Đoàn Đức Hà]

Bài 2: \(\frac{15-4x}{5}< \frac{x+7}{3}\)

\(\Leftrightarrow\frac{-4}{5}x-\frac{x}{3}< \frac{7}{3}-\frac{15}{5}\)

\(\Leftrightarrow\frac{-17}{15}x< -\frac{2}{3}\)

\(\Leftrightarrow x>\frac{10}{17}\).