\(\frac{4.5.7+9.10.11}{27.30.33+12.15.21}\)X \(\frac{54}{3}\)
help me !
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\(\frac{\frac{3}{67}.\left(17\frac{21}{56}-13\frac{21}{45}\right):\left(\frac{3}{5.22}+\frac{54}{44.65}+\frac{18}{65.72}\right)}{29^3:100-29^3:0,47}\)
\(=\frac{\frac{3}{67}\left(\frac{139}{8}-\frac{202}{15}\right):\left(\frac{3}{110}+\frac{54}{2860}+\frac{18}{4680}\right)}{29^3.\frac{1}{100}-29^3.\frac{47}{100}}\)
\(=\frac{\frac{3}{67}.\frac{469}{120}:\frac{1}{20}}{29^3\left(\frac{1}{100}-\frac{47}{100}\right)}\)
\(=\frac{\frac{7}{40}.20}{29^3.\left(-\frac{23}{50}\right)}\).
\(=\frac{\frac{7}{2}}{-11218,94}\)
\(=-\frac{175}{560947}\)
\(\frac{3+6+9+...+54}{4+8+12+...+72}\) = \(\frac{3.\left(1+2+3+...+18\right)}{4.\left(1+2+3+...+18\right)}\)=\(\frac{3}{4}\)
\(\frac{3+6+9+......+54}{4+8+12+......+72}\)
<=>( 3+6+9+.........+54) : ( 4+8+12+...........+ 72)
= ! < ( 54- 3 ):3 +1 > x ( 54+3 ) : 2 ! : ! <( 72-4): 4 +1 > x ( 72+4) : 2 > !
= 513 : 684
= 0.75
CHÚC BẠN HỌC GIỎI!
x . \(\frac{1}{2}\)- x.\(\frac{2}{3}\) + x.\(\frac{3}{4}\)- x. \(\frac{5}{6}\) = \(\frac{5}{6}\) -\(\frac{3}{4}\) + \(\frac{2}{3}\) -\(\frac{1}{2}\)
x . \(\frac{1}{2}\)- x.\(\frac{2}{3}\) + x.\(\frac{3}{4}\)- x. \(\frac{5}{6}\) = \(\frac{10}{12}\)-\(\frac{9}{12}\)+\(\frac{8}{12}\)-\(\frac{6}{12}\)
=>x.(1/2-2/3+3/4)=1/4
=>x.7/12=1/4
=>x=1/4:7/12
=>x=1/4.12/7
=>x=3/7
a, <=> 7(37-x)=3(x+13)
<=> x =22
b, <=> (x+1)(x-1)=15
<=> x^2-1=15 <=> x^2=16 <=> x= +_4
+) Xét \(\frac{x-2}{5}=\frac{x-4}{3}\)
\(\Rightarrow3x-6=5x-20\)
\(\Rightarrow-2x=-14\)
\(\Rightarrow x=7\)
\(\Rightarrow\frac{x-4}{3}=\frac{7-4}{3}=1\)
+) Xét \(\frac{y-3}{4}=1\Rightarrow y-3=4\Rightarrow y=7\)
Vậy x = y = 7
Ta có:
\(\frac{x+3}{3}=\frac{27}{x-3}\)
\(\Rightarrow\left(x+3\right)\left(x-3\right)=27.3\)
\(\Leftrightarrow x^2-9=27.3\)
\(\Leftrightarrow x^2-9=81\)
\(\Leftrightarrow x^2=81+9\)
\(\Leftrightarrow x^2=90\)
\(\Leftrightarrow x=\sqrt{90}=3\sqrt{10}\)
Cái đoạn(x+3)(x-3)=x2-9 là mình dùng hằng đẳng thức của lớp 8
\(\frac{x}{3}=\frac{2}{3}+\frac{-1}{7}\)
\(\frac{x}{3}=\frac{11}{21}\)
\(x=\frac{11.3}{21}\)(Áp dụng công thức \(\frac{a}{b}=\frac{c}{d}\)khi \(a.d=b.c\))
\(\Rightarrow x=\frac{11}{7}\)
~Học tốt~
\(\frac{x}{3}=\frac{2}{3}+\frac{-1}{7}\)
\(\frac{x}{3}=\frac{2.7+\left(-1\right).3}{21}\)
\(\frac{x}{3}=\frac{11}{21}\)
\(\Leftrightarrow21x=33\)
\(\Leftrightarrow x=\frac{33}{21}=\frac{11}{7}\)
\(\frac{3}{4}-\left(x+\frac{1}{2}\right)=\frac{4}{5}\)
\(\Rightarrow x+\frac{1}{2}=\frac{3}{4}-\frac{4}{5}\)
\(\Rightarrow x+\frac{1}{2}=-\frac{1}{20}\)
\(\Rightarrow x=-\frac{1}{20}-\frac{1}{2}\)
\(\Rightarrow x=\frac{-11}{20}\)
2/81 bạn nhé
Ta có:
\(\frac{4.5.7+9.10.11}{27.30.33+12.15.21}=\frac{2^2.5.7+3^2.2.5.11}{3^3.2.3.5.3.11+2^2.3.3.5.3.7}=\frac{2.5.\left(2.7+3^2.11\right)}{3^5.2.5.11+2^2.3^3.5.7}\)
\(=\frac{2.5.\left(2.7+3^2.11\right)}{3^3.2.5.\left(3^2.11+2.7\right)}=\frac{1}{3^3}=\frac{1}{27}\)
\(\Rightarrow\frac{1}{27}\times\frac{54}{3}=\frac{2}{3}\)
Vậy giá trị của biểu thức là \(\frac{2}{3}\)