Giup e với ah
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Khách
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VN
0
11 tháng 12 2021
\(1,=\dfrac{x+3-x}{x\left(x+3\right)}=\dfrac{3}{x\left(x+3\right)}\\ 2,=\dfrac{20x+2x-10}{2x-5}=\dfrac{22x-10}{2x-5}\\ 3,=\dfrac{x+5+x-7+x-4}{x-2}=\dfrac{3\left(x-2\right)}{x-2}=3\\ 4,=\dfrac{x^2+3x-x^2-2x-1}{x\left(x-1\right)\left(x+1\right)}=\dfrac{x-1}{x\left(x-1\right)\left(x+1\right)}=\dfrac{1}{x\left(x+1\right)}\\ 5,=\dfrac{3xy+y^3-3xy-x^3}{x^2y^2}=\dfrac{y^3-x^3}{x^2y^2}\\ 6,=\dfrac{x^2-xy}{\left(x-y\right)\left(x+y\right)}=\dfrac{x\left(x-y\right)}{\left(x-y\right)\left(x+y\right)}=\dfrac{x}{x+y}\)
\(7,=\dfrac{x^2+6x-2x+4}{x\left(x+2\right)\left(x-2\right)}=\dfrac{\left(x+2\right)^2}{x\left(x+2\right)\left(x-2\right)}=\dfrac{x+2}{x\left(x-2\right)}\\ 8,=\dfrac{4x^2+8x+3x-6-32}{\left(x-2\right)\left(x+2\right)}=\dfrac{4x^2+11x-38}{\left(x-2\right)\left(x+2\right)}=\dfrac{\left(x-2\right)\left(4x+19\right)}{\left(x-2\right)\left(x+2\right)}=\dfrac{4x+19}{x+2}\\ 9,=\dfrac{-5x-1-25x^2+15x}{x\left(5x-1\right)\left(5x+1\right)}=\dfrac{-\left(5x-1\right)^2}{x\left(5x-1\right)\left(5x+1\right)}=\dfrac{1-5x}{x\left(5x+1\right)}\\ 10,=\dfrac{1}{x}-\dfrac{1}{x+1}+\dfrac{1}{x+1}-\dfrac{1}{x+2}+...+\dfrac{1}{x-4}-\dfrac{1}{x+5}+\dfrac{1}{x+5}=\dfrac{1}{x}\)
giúp e với ah
HT
21
5 tháng 5 2021
Câu 10:
(1) CH3COOH + Na -> CH3COONa + 1/2 H2
(2) CH3COOH + NaOH -> CH3COONa + H2O
(3) CH3COOH + C2H5OH \(⇌\) CH3COOC2H5 + H2O (đk trên mũi tên phản ứng là H+ và nhiệt độ)
DT
2
SV
Sinh Viên NEU
CTVVIP
29 tháng 6
1 Unless she is lazy, she can pass the exam
2 Unless she takes some exercises, he will be healthy
3 Unless you study hard, you won't pass the exam
4 Unless you are impatient, you won't make mistakes
5 Unless he gets my mail, he won't send the information we need
SV
Sinh Viên NEU
CTVVIP
29 tháng 6
6 Unless she travels to London, she will not visit the museum
7 Unless I get the money, I won't buy a mobile phone
8 Unless you make trouble, I will not send you to the principal
9 Unless I have enough time this evening, I will not watch a movie
10 Unless he has money, he will not lend me what I need
1/(1.4) + 1/(4.7) + 1/(7.10) + ... + 1/[x.(x + 3)] = 125/376
1/3 . (1 - 1/4 + 1/4 - 1/7 + 1/7 - 1/10 + ... + 1/x - 1/(x + 3) = 125/376
1/3 . [1 - 1/(x + 3)] = 125/376
1 - 1/(x + 3) = 375/376
1/(x + 3) = 1 - 375/376
1/(x + 3) = 1/376
x + 3 = 376
x = 376 - 3
x = 373