Rút gọn biểu thức:
(x+y-7)^2 -2(x+y-7)(y-6)+(y-6)^2
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a) Ta có: \(\left(3x-2\right)^2+2\left(3x-2\right)\left(3x+2\right)+\left(3x+2\right)^2\)
\(=\left(3x-2+3x+2\right)^2\)
\(=36x^2\)(1)
Thay \(x=-\dfrac{1}{3}\) vào biểu thức (1), ta được:
\(36\cdot\left(-\dfrac{1}{3}\right)^2=36\cdot\dfrac{1}{9}=4\)
b) Sửa đề: \(\left(x+y-7\right)^2-2\cdot\left(x+y-7\right)\left(y-6\right)+\left(y-6\right)^2\)
Ta có: \(\left(x+y-7\right)^2-2\cdot\left(x+y-7\right)\left(y-6\right)+\left(y-6\right)^2\)
\(=\left(x+y-7-y+6\right)^2\)
\(=\left(x-1\right)^2=100^2=10000\)
5: \(=\dfrac{1}{x-y}\cdot x^3\cdot\left(x-y\right)^2=x^3\left(x-y\right)\)
1b.=2((x+y)+(x+y)(x-y)+(x-y))=2(x2-y2+x+y+x-y)=2(x2-y2+2x)=2x2-2y2+4x
2a.=4xy+4xy+2y=8xy+2y=2y(4x+1)
b.=(3x)2+2.3x.y+y2-(2z)2=(3x+y)2-(2z)2=(3x+y-2z)(3x+y+2z)
c.=x2-x-7x+7=x(x-1)-7(x-1)=(x-1)(x-7)
\(\left(x+y\right)^2+2\left(x+y\right)\left(x-y\right)+\left(x-y\right)^2\)
\(=\left(x+y+x-y\right)^2\)
\(=\left(2x\right)^2\)
\(=4x^2\)
hk tốt
^^
a) Cách 1:
\(6(y - x) - 2(x - y)\)
\( = 6y - 6x - 2x + 2y\)
\( = 8y - 8x\)
Cách 2:
\(6(y - x) - 2(x - y)\\= 6(y-x)+2(y-x)\\=(6+2).(y-x)\\=8.(y-x)\\=8y-8x\)
b) \(3{x^2} + x - 4x - 5{x^2}\)
\( = (3{x^2} - 5{x^2}) + (x - 4x)\)
\( = - 2{x^2} - 3x\)
\(\dfrac{x^2+x-6}{x^2-9}=\dfrac{\left(x+3\right)\left(x-2\right)}{\left(x+3\right)\left(x-3\right)}=\dfrac{x-2}{x-3}\)
Đề này đúng ra là tính nhé.
a. (3x-2)^2 +(3x+2)^2 + 2(9x^2) - 4 tại x= -1/3
Câu a sai đề nữa nè
Ta có:
\((3x-2)^2 + (3x+2)^2 + 2(9x^2-4) \)
\(= (9x^2 - 6x+4) + (9x^2+6x+4) + 2(9x^2 - 4)\)
\(= 2(9x^2+4) + 2(9x^2 -4) = 2.2.9x^2 \)
\(=36\cdot\dfrac{1}{9}=4\)
b. (x + y-7)^2 - 2(x+y -7)(y-6) + (y-6)^2 tại x= 101
Ta có:
\((x + y-7)^2 - 2(x+y -7)(y-6) + (y-6)^2\)
\(= [(x+y-7) - (y-6)]^2\)
\(= (x - 1)^2 \)
\(=100^2=10000\)
c.4x^2 - 20x +27 tại 52,5
Ta có:
\(4x^2 - 20x +27\)
\(=(2x)^2 -2.2x.5 + 25 + 2 \)
\(=(2x-5)^2 + 2 \)
\(=100^2+2=10002\)
Ta có: \(A=\left(x-y-1\right)^3-\left(x-y+1\right)^3+6\left(x-y\right)^2\)
\(=\left(x-y-1-x+y-1\right)\left[\left(x-y-1\right)^2+\left(x-y-1\right)\left(x-y+1\right)+\left(x-y+1\right)^2\right]+6\left(x-y\right)^2\)
\(=-2\cdot\left[3\left(x-y\right)^2+1\right]+6\left(x-y\right)^2\)
\(=-6\left(x-y\right)^2+6\left(x-y\right)^2-2\)
=-2
\(\dfrac{1}{y-x}\cdot\sqrt{x^6\left(x-y\right)^2}\)
\(\dfrac{1}{y-x}\cdot x^3\cdot\left(x-y\right)\)
\(=-x^3\)
\(\left(x+y-7\right)^2-2\left(x+y-7\right)\left(y-6\right)+\left(y-6\right)^2\)
\(=\left(x+y-7-y+6\right)^2\)
\(=\left(x-1\right)^2=x^2-2x+1\)
Bn lm chi tiết dk??