[11x8 -100x12]:[4x 5x6x7x8x9x10]=
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
5x6x7x8x9x10=25200
1+2+3+4+5=15
25200+15=25215
![](https://rs.olm.vn/images/avt/0.png?1311)
= 1,5 x 2,9 + 0,5 x 21 + 0,01 x 12 - 2
= 4,35 + 10,5 + 0,12 - 2
= 12,97
![](https://rs.olm.vn/images/avt/0.png?1311)
125 - 56 + 98 x 0,4 - 100 x 12
= 69 + 39,2 - 1200
= 108,2 - 1200 = - 1091,8.
125-56+98x0,4-100x12=125-56+(98x0,4)-(100x12)
=125-56+39,2-1200
=69+39,2
=108,2-1200
=-1091,8
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{9}{11}\)x 8 = \(\frac{9}{11}\)x \(\frac{8}{1}\)= \(\frac{72}{11}\)
`HT`
TSP
9/11x8=9x8/11=72/11
Đáp án là : 72/11
còn 1 cách tính nữa:
9/11x8=9/11x8/11=72/11
@@@@@@@@@@@@
HT~
![](https://rs.olm.vn/images/avt/0.png?1311)
(792x0,25+792x0,75)x(11x8-800+0,1-8)
=[792x(0,25+0,75)]x(88-800+0,1-8)
=792x1x(-719,9)
=792x1x(-719,9)
=-570160,8
Cái này là toán lớp 5 à . Bạn chỉnh lại đề đi cái có cả số âm mà
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a,4/5x2/9+1/5x2/9
=2/9*(4/5+1/5)
=2/9*1
=2/9
b)7/8:1/5-3/8:1/5
=(7/8-3/8):1/5
=1/2:1/5
=5/2
c)6/11x8/9+5/11x8/9
=(6/11+5/11)*8/9
=1*8/9
=8/9
d)11/12:2/3-3/12:2/3
=(11/12-3/12):2/3
=2/3:2/3
=1
MK sẽ giúp bn
a)\(\frac{4}{5}x\frac{2}{9}+\frac{1}{5}x\frac{2}{9}\)
\(=\left(\frac{4}{5}+\frac{1}{5}\right)x\frac{2}{9}\)
\(=1x\frac{2}{9}\)
\(=\frac{2}{9}\)
b)\(\frac{7}{8}:\frac{1}{5}-\frac{3}{8}:\frac{1}{5}\)
\(=\left(\frac{7}{8}-\frac{3}{8}\right):\frac{1}{5}\)
\(=\frac{5}{8}:\frac{1}{5}\)
\(=\frac{25}{8}\)
c)\(\frac{6}{11}x\frac{8}{9}+\frac{5}{11}x\frac{8}{9}\)
\(=\left(\frac{6}{11}+\frac{5}{11}\right)x\frac{8}{9}\)
\(=\frac{8}{9}x1\)
\(=\frac{8}{9}\)
d)\(\frac{11}{12}:\frac{2}{3}-\frac{3}{12}:\frac{2}{3}\)
\(=\left(\frac{11}{12}-\frac{3}{12}\right):\frac{2}{3}\)
\(=\frac{2}{3}:\frac{2}{3}\)
\(=1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) ( 11 x 8 - 100 + 12 ) : ( 4 x 5 x 6 x 7 x 8 x 9 x 10 )
= ( 88 +12 - 100 ) : ( 4 x 5 x 6 x 7 x 8 x 9 x 10 )
= ( 100 - 100 ) : ( 4 x 5 x 6 x 7 x 8 x 9 x 10 )
= 0 : ( 4 x 5 x 6 x 7 x 8 x 9 x 10 )
= 0
b) ( 132 x 6 - 66 x 12 ) x ( 132 x 6 + 66 )
= ( 11 x 12 x 6 - 66 x 12 ) x ( 132 x 6 + 66)
= ( 66x 12 - 66 x 12 ) x ( 132 x 6 + 66 )
= 0 x ( 132 x 6 + 66)
= 0
c) Có: (100 - 2) : 1 + 1 = 99 ( số)
100 - 99 + 98 - 97 + 96 - 95 + ... + 4 - 3 + 2
= ( 100 - 99 ) + ( 98 - 97) + ( 96 - 95) + ... + ( 4 - 3) + 2 ( 49 cặp 2 số, thừa số 2 )
= 1 + 1 + 1 + ... + 1 + 2 ( 49 số 1)
= 49+2
= 51
\(\left[88-1200\right]:\left[20x10x42x72\right]\)
\(=\frac{88-1200}{\text{604800}}=\frac{88}{\text{604800}}-\frac{1200}{\text{604800}}\)