\(\frac{x-3}{x-2}+\frac{x-2}{x-4}=3\frac{1}{5}\)
M.n giúp mình với mai mình phải nộp rồi
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
R
31 tháng 7 2019
Trả lời
x:(1/2+1/3+1/6)=2019
x:6/6 =2019
x:1 =2019
=>x =2019.1
=>x =2019
Học tốt !
31 tháng 7 2019
x : (\(\frac{1}{2}\)+ \(\frac{1}{3}\)+ \(\frac{1}{6}\)) = 2019
x : 1 = 2019
x = 2019
12 tháng 6 2018
1. a) \(\frac{3}{4}-\frac{-1}{2}+\frac{1}{3}=\frac{3}{4}+\frac{1}{2}+\frac{1}{3}=\frac{9}{12}+\frac{6}{12}+\frac{4}{12}=\frac{19}{12}\)
b) \(5\frac{5}{27}+\frac{7}{23}+\frac{1}{2}-\frac{5}{27}+\frac{16}{23}\)
\(=\frac{140}{27}-\frac{5}{27}+\frac{7}{23}+\frac{16}{23}+\frac{1}{2}\)
\(=\frac{135}{27}+\frac{23}{23}+\frac{1}{2}\)
\(=5+1+0,5=6,5\)
2) a) 1/2 + 2/3x = 1/4
=> 2/3x = 1/4 - 1/2
=> 2/3x = -1/4
=> x = -1/4 : 2/3
=> x = -3/8
b) 3/5 + 2/5 : x = 3 1/2
=> 3/5 + 2/5 : x = 7/2
=> 2/5 : x = 7/2 - 3/5
=> 2/5 : x = 29/10
=> x = 2/5 : 29/10
=> x = 4/29
c) x+4/2004 + x+3/2005 = x+2/2006 + x+1/2007
=> x+4/2004 + 1 + x+3/2005 + 1 = x+2/2006 + 1 + x+1/2007 + 1
=> x+2008/2004 + x+2008/2005 = x+2008/2006 + x+2008/2007
=> x+2008/2004 + x+2008/2005 - x+2008/2006 - x+2008/2007 = 0
=> (x+2008). (1/2004 + 1/2005 - 1/2006 - 1/2007) = 0
Vì 1/2004 + 1/2005 - 1/2006 - 1/2007 khác 0
Nên x + 2008 = 0 <=> x = -2008
Vậy x = -2008
12 tháng 6 2018
1,a,\(\frac{3}{4}-\frac{-1}{2}+\frac{1}{3}=\frac{3}{4}+\frac{2}{4}+\frac{1}{3}=\frac{5}{4}+\frac{1}{3}=\frac{15}{12}+\frac{4}{12}=\frac{19}{12}\)
b, \(5\frac{5}{27}+\frac{7}{23}+\frac{1}{2}-\frac{5}{27}+\frac{16}{23}=\frac{140}{27}-\frac{5}{27}+\frac{7}{23}+\frac{16}{23}+\frac{1}{2}=\frac{135}{27}+\frac{23}{23}+\frac{1}{2}=5+1+\frac{1}{2}=\frac{13}{2}\)2,a,\(\frac{1}{2}+\frac{2}{3}.x=\frac{1}{4}\)
<=>\(\frac{2}{3}.x=-\frac{1}{2}\)
<=>\(x=-\frac{3}{4}\)
b,\(\frac{3}{5}+\frac{2}{5}\div x=3\frac{1}{2}\)
<=>\(\frac{2}{5x}=\frac{29}{10}\)
<=>\(x=\frac{29}{4}\)
c,\(\frac{x+4}{2004}+\frac{x+3}{2005}=\frac{x+2}{2006}+\frac{x+1}{2007}\)
<=> \(\frac{x+4}{2004}+1+\frac{x+3}{2005}+1=\frac{x+2}{2006}+1+\frac{x+1}{2007}+1\)
<=>\(\frac{x+2008}{2004}+\frac{x+2008}{2005}=\frac{x+2008}{2006}+\frac{x+2008}{2007}\)
<=>\(\left(x+2008\right)\left(\frac{1}{2004}+\frac{1}{2005}-\frac{1}{2006}-\frac{1}{2007}\right)\)=0
<=>x+2008=0 vì cái ngoặc còn lại\(\ne0\)
<=>x=-2008
Vậy x=-2008
Bạn nhớ tk cho mình vì mình đã chăm chỉ làm hết bài bạn hỏi nha!
29 tháng 9 2019
\(\frac{2x-2}{4}=\frac{3y-6}{9}=\frac{-z+3}{-4}=\frac{2x-2+3y-6-z+3}{9}=\frac{56-5}{9}\)\(=\frac{17}{3}\)
\(\Rightarrow x=\frac{37}{3},y=19,z=\frac{77}{3}\)
HN
29 tháng 9 2019
\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\); \(2x+3y-z=56\)
\(\Leftrightarrow\frac{2x-2}{4}=\frac{3y-6}{9}=\frac{z-3}{4};2x+3y-z=56\)
Áp dụng tính chất của dãy tỉ số bằng nhau ta có:
\(\frac{2x-2}{4}=\frac{3y-6}{9}=\frac{z-3}{4}=\frac{2x-2+3y-6-z+3}{4+9-4}=\frac{56-2-6+3}{9}=\frac{51}{9}=\frac{17}{3}\)
\(\Leftrightarrow x=\frac{37}{3};y=19;z=\frac{77}{3}\)
Vậy \(x=\frac{37}{3};y=19;z=\frac{77}{3}\)
11 tháng 3 2018
b, |5x-3| >= 7
=> 5x-3 < = -7 hoặc 5x-3 >= 7
=> x < = -4/5 hoặc x >= 2
Vậy ..........
Tk mk nha
DP
21 tháng 7 2017
\(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+....+\frac{1}{x\left(x+1\right)}=\frac{215}{216}\)
\(\Leftrightarrow1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+.....+\frac{1}{x}-\frac{1}{x+1}=\frac{215}{216}\)
\(\Leftrightarrow1-\frac{1}{x+1}=\frac{215}{216}\)
\(\Leftrightarrow\frac{1}{x+1}=1-\frac{215}{216}\)
\(\Leftrightarrow\frac{1}{x+1}=\frac{1}{216}\)
\(\Leftrightarrow x=216-1=215\)
22 tháng 4 2020
\(a/\frac{7}{9}-\frac{x}{3}=\frac{1}{9}\)
\(\Rightarrow\frac{x}{3}=\frac{7}{9}-\frac{1}{9}\)
\(\Rightarrow\frac{x}{3}=\frac{2}{3}\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
\(b/\frac{1}{x}-\frac{-2}{15}=\frac{7}{15}\)
\(\Rightarrow\frac{1}{x}=\frac{7}{15}+\frac{-2}{15}\)
\(\Rightarrow\frac{1}{x}=\frac{1}{3}\)
\(\Rightarrow x=3\)
Vậy \(x=3\)
\(c/\frac{-11}{14}-\frac{-4}{x}=\frac{-3}{14}\)
\(\Rightarrow\frac{-4}{x}=\frac{-11}{14}-\frac{-3}{14}\)
\(\Rightarrow\frac{-4}{x}=\frac{-4}{7}\)
\(\Rightarrow x=7\)
Vậy \(x=7\)
\(d/\frac{x}{21}-\frac{2}{3}=\frac{5}{21}\)
\(\Rightarrow\frac{x}{21}=\frac{5}{21}+\frac{2}{3}\)
\(\Rightarrow\frac{x}{21}=\frac{19}{21}\)
\(\Rightarrow x=19\)
Vậy \(x=19\)
#Mạt Mạt#
\(\frac{x-3}{x-2}+\frac{x-2}{x-4}=3\frac{1}{5}\)
\(=\frac{x-3}{x-2}+\frac{x-2}{x-4}=\frac{16}{5}\)
\(\Rightarrow5\left(x-3\right)\left(x-4\right)+5\left(x-2\right)\left(x-2\right)=16\left(x-2\right)\left(x-4\right)\)
\(\Leftrightarrow5x^2-35x+60+5x^2-20x+20=16x^2-96x+128\)
\(\Leftrightarrow10x^2-55x+80=16x^2-96x+128\)
\(\Leftrightarrow-6x^2+41x-48=0\)
......
\(\frac{x-3}{x-2}+\frac{x-2}{x-4}=3\frac{1}{5}\)
\(\Leftrightarrow\frac{x-3}{x-2}+\frac{x-2}{x-4}=\frac{16}{5}\)
\(\Leftrightarrow\frac{5\left(x-3\right)\left(x-4\right)+5\left(x-2\right)^2}{5\left(x-2\right)\left(x-4\right)}=\frac{16.\left(x-2\right)\left(x-4\right)}{5\left(x-2\right)\left(x-4\right)}\)
\(\Rightarrow5x^2-20x-15x+60+5x^2-20x+20=16x^2-64x-32x+128\)
\(\Leftrightarrow10x^2-55x+80=16x^2-96x+128\)
\(\Leftrightarrow6x^2-41x+48=0\)
\(\Leftrightarrow x=\frac{16}{3};x=\frac{3}{2}\)