tìm x biết : 9 cộng x / 13 - x bằng 5 phần 6
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\(9+\frac{x}{13}-x=\frac{5}{6}\)
\(\Leftrightarrow\frac{x}{13}-x=\frac{5}{6}-9\)
\(\Leftrightarrow x\left(\frac{1}{13}-1\right)=\frac{5}{6}-\frac{54}{6}\)
\(\Leftrightarrow\frac{-12}{13}x=\frac{-50}{6}\)
\(\Leftrightarrow x=\frac{-50}{6}\div\frac{-12}{13}\)
\(\Leftrightarrow x=\frac{50}{6}\times\frac{13}{12}\)
\(\Leftrightarrow x=\frac{650}{72}=\frac{325}{36}\)
\(9+\frac{x}{13}-x=\frac{5}{6}\)
\(\Rightarrow9+\frac{x}{13}-\frac{13x}{13}=\frac{5}{6}\)
\(\Rightarrow9+\frac{x-13x}{13}=\frac{5}{6}\)
\(\Rightarrow\frac{x-13x}{13}=\frac{5}{6}-9\)
\(\Rightarrow\frac{x-13x}{13}=-\frac{49}{6}\)
\(\Rightarrow x-13x=-\frac{49}{6}\cdot13=-\frac{637}{6}\)
\(\Rightarrow-12x=-\frac{637}{6}\)
\(\Rightarrow x=-\frac{637}{6}:(-12)=\frac{637}{72}\)
\(\frac{9+x}{13-x}=\frac{5}{6}\)
\(\Leftrightarrow6\left(9+x\right)=5\left(13-x\right)\)
\(\Leftrightarrow54+6x=65-5x\)
\(\Leftrightarrow54-65=-5x-6x\)
\(\Leftrightarrow-11=-11x\)
\(\Leftrightarrow x=\frac{11}{11}\)
\(\Leftrightarrow x=1\)
\(\frac{9+x}{13-x}=\frac{5}{6}\)
\(\Rightarrow\text{ }6\left(9+x\right)=5\left(13-x\right)\)
\(\Rightarrow\text{ }54+6x=65-5x\)
\(\Rightarrow\text{ }54-65=-5x-6x\)
\(\Rightarrow\text{ }-11=-11x\)
\(\Rightarrow\text{ }x=-11\text{ : }\left(-11\right)\)
\(\Rightarrow\text{ }x=1\)
\(\frac{9+x}{13-x}=\frac{5}{6}\Rightarrow6\left(9+x\right)=5\left(13-x\right)\)
\(\Leftrightarrow11x=11\Leftrightarrow x=1\)
Ta có : \(\frac{9-x}{13-x}=\frac{5}{6}\)
\(\Leftrightarrow\left(9-x\right).6=5.\left(13-x\right)\)
\(\Leftrightarrow54-6x=65-5x\)
\(\Leftrightarrow6x-5x=54-65\)
\(\Leftrightarrow-1x=-11\)
\(\Leftrightarrow x=-11\)
Vậy x = -11