\(12+9\frac{6}{12}=?\)
k mk nha
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2\(\frac{2}{12}\)+ X = \(\frac{5}{7}\)+ \(\frac{8}{12}\)
\(\frac{13}{6}\)+ X=\(\frac{29}{21}\)
X= \(\frac{29}{21}\)- \(\frac{13}{6}\)
X=\(\frac{-11}{14}\)
\(|2^2_{12}\)\(+x=\frac{5}{7}+\frac{8}{12}\)
\(2+x=\frac{5}{7}+\frac{1}{2}\)
\(2+x=\frac{17}{14}\)
\(x=\frac{17}{14}-2\)
\(x=\frac{-11}{14}\)
(-14)-(-57)-18-(-14)+57-18=-43-18=-61
(-32)-14-12=(-32)-12-14=-44-14=-58
30+12+(-20)+(-12)=30+12-20-12=(30-20)+(12-12)=10
(-2)-(3-9)=(-2)-(-6)=(-2)+6=4
6-(-5-11)=6-(-16)=6+16=22
(-4)-(-2)-9=-4+2-9=-11
(-14)-(-57)-18=25
(-32)-14-12=-58
30+12+(-20)+(-12)=10
(-2)-(3-9)=4
6-(-5-11)=22
(-4)-(-2)-9=-11
\(89+\frac{2}{12}=89+\frac{1}{6}=\frac{534}{6}+\frac{1}{6}=\frac{534+1}{6}=\frac{535}{6}\)
AI THẤY ĐÚNG NHỚ ỦNG HỘ NHA
\(89+\frac{2}{12}=\frac{535}{6}\)
Tk cho mình nha vì mình đang bị âm điểm
= 2x4/3x4 + 3x3/4x3 +3/12=8/12+9/12+3/12=8+9+3/12=20/12=5/3
-1/5 . (9/8 + 16/32 - 12/46) - 9/17
= -1/5 . (9/8 + 1/2 - 6/23) - 9/17
= -1/5 . (9/8 + 4/8 - 6/23) - 9/17
= -1/5 . (13/8 - 6/23) - 9/17
= -1/5 . 251/184 - 9/17
= -251/920 - 9/17
= -4267/15640 - 8280/15640
= -12547/15640
\(9\frac{5}{34}-12+5\)
\(9\frac{5}{34}=\frac{311}{34}\)
\(\Rightarrow9\frac{5}{34}-12+5\)
\(=\frac{311}{34}-12+5\)
\(=-\frac{97}{34}+5\)
\(=\frac{73}{34}\)
\(\frac{2^{12}.3^{12}+6^9}{4^6.3^{12}+6^{11}}\)
= \(\frac{2^{12}.3^{12}+6^9}{2^{12}.3^{12}+6^{11}}\)
= \(\frac{6^{12}+6^9}{6^{12}+6^{11}}\)
= \(\frac{6^9\left(6^3+1\right)}{6^9\left(6^3+6^2\right)}\)
= \(\frac{217}{252}\)
= \(\frac{31}{36}\)
Hk tốt
\(\frac{2^{12}\times3^{12}+6^9}{4^6\times3^{12}+6^{11}}=\frac{2^{12}\times3^{12}+6^9}{\left(2^2\right)^6\times3^{12}+6^{11}}\)
\(=\frac{2^{12}\times3^{12}+6^9}{2^{12}\times3^{12}+6^{11}}=\frac{6^{12}+6^9}{6^{12}+6^{11}}\)
\(=\frac{6^9\left(6^3+1\right)}{6^9\left(6^3+6^2\right)}=\frac{6^3+1}{6^3+6^2}\)
\(=1+\frac{1}{36}=\frac{37}{36}\)
\(12+9\frac{6}{12}\)
\(=12+9\frac{1}{2}\)
\(=12+9+\frac{1}{2}\)
\(=21+\frac{1}{2}\)
\(=21\frac{1}{2}\)
\(12+9\frac{6}{12}\)
\(=12+\frac{114}{12}\)
\(=12+9,5\)
\(=21,5\)
Vậy \(12+9\frac{6}{12}=21,5\)