Question

[Lizy]

`1-27x^3`

`x-3^3 +27`

`27x^3 +27x^2 +9x+1`

`(x^6)/27 - (x^4 y)/3 +x^2 y-y^3`

Phân tích thành nhân tử

Answer 1

[Toru]

\(1-27x^3\)

\(=1-\left(3x\right)^3\)

\(=\left(1-3x\right)\left(1+3x+9x^2\right)\)

\(---\)

\(x-3^3+27\)

\(=x-27+27=x\) 

\(---\)

\(27x^3+27x^2+9x+1\)

\(=\left(3x\right)^3+3\cdot\left(3x\right)^2\cdot1+3\cdot3x\cdot1^2+1^3\)

\(=\left(3x+1\right)^3\)

\(---\)

\(\dfrac{x^6}{27}-\dfrac{x^4y}{3}+x^2y^2-y^3\) (sửa đề)

\(=\left(\dfrac{x^2}{3}\right)^3-3\cdot\left(\dfrac{x^2}{3}\right)^2\cdot y+3\cdot\dfrac{x^2}{3}\cdot y^2-y^3\)

 \(=\left(\dfrac{x^2}{3}-y\right)^3\)

#Ayumu

Answer 2

[Tieen Ddat dax quay trow lai]

1-27x\(^3\)

=(1-3x)(1+3x+9x\(^2\)