a)(x+13):5=12
b)23.(42-x)=23
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x-(57-(42+(-23-x)=13-47+25-23-x
x-57-42-23-x=13-47+25-23-x
x-122-x=-32-x
x-x-122=-32-x
-32-x=-122
x=-32-(-122)
x=90
Vậy x=90
\(x-(57-(42+(-23-x)=13-47+25-13-x\)
\(\Rightarrow x-57-42+\left(-23\right)-x=13-47+25-23-x\)
\(\Rightarrow x-x+x=13-47+25-23+23+42+57\)
\(\Rightarrow x=90\)
\(a.\dfrac{12+x}{42}=\dfrac{35}{42}\Leftrightarrow12+x=35\Leftrightarrow x=23\)
\(b.\dfrac{25-x}{40}=\dfrac{3}{8}\Leftrightarrow\dfrac{25-x}{40}=\dfrac{15}{40}\Leftrightarrow25-x=15\Leftrightarrow x=10\)
\(c.\dfrac{13+x}{20}=\dfrac{3}{4}\Leftrightarrow\dfrac{13+x}{20}=\dfrac{15}{20}\Leftrightarrow13+x=15\Leftrightarrow x=2\)
\(d.\dfrac{23-x}{25}=\dfrac{20}{25}\Leftrightarrow23-x=20\Leftrightarrow x=3\)
a,\(\frac{1}{5}\times\frac{2}{9}\div\frac{1}{15}\)
\(=\frac{1}{5}\times\frac{2}{9}\times15\)
\(=\left(\frac{1}{5}\times15\right)\times\frac{2}{9}\)
\(=3\times\frac{2}{9}\)
\(=\frac{2}{3}\)
b\(\frac{4}{15}\times\frac{7}{15}\times\frac{5}{4}\)
\(=\left(\frac{4}{15}\times\frac{5}{4}\right)\times\frac{7}{15}\)
\(=\frac{1}{3}\times\frac{7}{15}\)
\(=\frac{7}{45}\)
c,\(\frac{21}{23}\times\frac{5}{11}\times\frac{44}{?}\)
d,\(26\times\frac{13}{42}\div13\)
\(=\left(26\div13\right)\times\frac{13}{42}\)
\(=2\times\frac{13}{42}\)
\(=\frac{13}{21}\)
a)=>x=13+3/5=68/5.
Vậy x = 68/5
b)=>x/6=5/7+-23/42
=>x/6=1/6
=>x=1
Vậy x=1
còn lại tự làm nha😆😆😆😆😆
a) x-3/5=13
suy ra x=13+3/5
suy ra x=68/5
suy ra x=13.6
b)x/6=5/7+23/-42
suy ra x/6=1/6
suy ra x=1
d) x+11/12=2/5
suy ra x=2/5-11/12
suy ra x=-31/60
\(x-\left\{57-\left[42+\left(-23-x\right)\right]\right\}=13-\left\{47+\left[25-\left(32-x\right)\right]\right\}\)
=>\(x-\left\{57-42+23+x\right\}=13-47-25+32-x\)
=>\(x-\left(x+38\right)=-27-x\)
=>\(-27-x=-38\)
=>x+27=38
=>\(x=38-27=11\)
\(x-\left\{57-\left[42+\left(-23-x\right)\right]\right\}=13-\left\{47+\left[25-\left(32-x\right)\right]\right\}\)
\(\Leftrightarrow x-57+42-23-x=13-47-25+32-x\)
\(\Leftrightarrow x-x-57+42-23=-27-x\)
\(\Leftrightarrow-57+42-23=-27-x\)
\(\Leftrightarrow-38=-27-x\)
\(\Leftrightarrow x=\left(-27\right)-\left(-38\right)\)
\(\Leftrightarrow x=11\)
Vậy \(x=11\) là giá trị cần tìm
\(x-\left(57-\left(42+\left(-23-x\right)\right)\right)=13-\left(47+\left(25-\left(32-x\right)\right)\right)\)
\(\Leftrightarrow\) \(x-\left(57-\left(42-23-x\right)\right)=13-\left(47+\left(25-32+x\right)\right)\)
\(\Leftrightarrow\) \(x-\left(57-42+23+x\right)=13-\left(47+25-32+x\right)\)
\(\Leftrightarrow\) \(x-57+42-23-x=13-47-25+32-x\)
\(\Leftrightarrow\) \(-38=-27-x\) \(\Leftrightarrow\) \(-x=-38+27=-11\Leftrightarrow x=11\)
vậy \(x=11\)
a) \(\left(x+13\right):5=12\)
\(\Rightarrow x+13=12\cdot5\)
\(\Rightarrow x+13=60\)
\(\Rightarrow x=60-13\)
\(\Rightarrow x=47\)
b) \(23\cdot\left(42-x\right)=23\)
\(\Rightarrow42-x=23:23\)
\(\Rightarrow42-x=1\)
\(\Rightarrow x=42-1\)
\(\Rightarrow x=41\)