Tính giá trị các biểu thức sau:
a) \({\log _6}9 + {\log _6}4\);
b) \({\log _5}2 - {\log _5}50\);
c) \({\log _3}\sqrt 5 - \frac{1}{2}{\log _3}15\).
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a: \(log_{\dfrac{1}{4}}8=log_{2^{-2}}2^3=\dfrac{-3}{2}\cdot log_22=-\dfrac{3}{2}\)
b: \(log_45\cdot log_56\cdot log_68\)
\(=log_45\cdot\dfrac{log_46}{log_45}\cdot\dfrac{log_48}{log_46}\)
\(=log_48=log_{2^2}2^3=\dfrac{3}{2}\)
\(a,A=log_23\cdot log_34\cdot log_45\cdot log_56\cdot log_67\cdot log_78\\ =log_28\\ =log_22^3\\ =3\\ b,B=log_22\cdot log_24...log_22^n\\ =log_22\cdot log_22^2...log_22^n\\ =1\cdot2\cdot...\cdot n\\ =n!\)
a: \(log_49=\dfrac{log9}{log4}=\dfrac{log3^2}{log2^2}=\dfrac{2\cdot log3}{2\cdot log2}=\dfrac{log3}{log2}=\dfrac{b}{a}\)
b: \(log_612=\dfrac{log12}{log6}=\dfrac{log2^2+log3}{log2+log3}=\dfrac{2\cdot log2+log3}{log2+log3}\)
\(=\dfrac{2a+b}{a+b}\)
c: \(log_56=\dfrac{log6}{log5}=\dfrac{log\left(2\cdot3\right)}{log\left(\dfrac{10}{2}\right)}=\dfrac{log2+log3}{log10-log2}\)
\(=\dfrac{a+b}{1-a}\)
a, ĐK: \(4x+4>0\Rightarrow x>-1\)
\(log_6\left(4x+4\right)=2\\ \Leftrightarrow4x+4=36\\ \Leftrightarrow4x=32\\ \Leftrightarrow x=8\left(tm\right)\)
Vậy x = 8.
b, ĐK: \(x-2>0\Rightarrow x>2\)
\(log_3x-log_3\left(x-2\right)=1\\ \Leftrightarrow log_3\left(x^2-2x\right)=1\\ \Leftrightarrow x^2-2x-3=0\\ \Leftrightarrow\left(x-3\right)\left(x+1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=3\left(tm\right)\\x=-1\left(ktm\right)\end{matrix}\right.\)
Vậy x = 3.
a) \(log_29\cdot log_34=4\)
b) \(log_{25}\cdot\dfrac{1}{\sqrt{5}}=-\dfrac{1}{4}\)
c) \(log_23\cdot log_9\sqrt{5}\cdot log_54=\dfrac{1}{2}\)
a) \(log_216=4\)
b) \(log_3\dfrac{1}{27}=-3\)
c) \(log1000=3\)
d) \(9^{log_312}=144\)
a: \(log_22^{-13}=-13\)
b: \(lne^{\sqrt{2}}=\sqrt{2}\)
c: \(log_816-log_82=log_8\left(\dfrac{16}{2}\right)=log_88=1\)
c: \(log_26\cdot log_68=log_28=3\)
a) \(\log_4\sqrt[5]{16}=\log_4\left(4^2\right)^{\dfrac{1}{5}}=\log_44^{\dfrac{2}{5}}=\dfrac{2}{5}\log_44=\dfrac{2}{5}.1=\dfrac{2}{5}\)
b) \(36^{\log_68}=\left(6^2\right)^{\log_68}=6^{2\log_68}=6^{\log_68^2}=8^2=64\)
a: \(log_4\sqrt[5]{16}=log_4\sqrt[5]{4^2}=\dfrac{2}{5}\)
b: \(36^{log_68}=6\cdot^{2\cdot log_68}=8^2=64\)
\(log_65=\dfrac{1}{log_56}=\dfrac{1}{log_52+log_53}=\dfrac{1}{a+b}\)
=>Chọn B
a) \(log_69+log_64=log_636=2\)
b) \(log_52-log_550=log_5\left(2:50\right)=-2\)
c) \(log_3\sqrt{5}-\dfrac{1}{2}log_550=-1,0479\)