120 - 2 x X + 5 x X = 360
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7.x + 2.x = 927
\(\Leftrightarrow\)( 7 + 2).x =927
\(\Leftrightarrow\)9.x = 927
\(\Leftrightarrow\)x = 927 : 9
\(\Leftrightarrow\)x = 103
Vậy x = 103
3(x-2)+150=240
\(\Leftrightarrow\)3(x-2)=240-150
\(\Leftrightarrow\)3(x-2)=90
\(\Leftrightarrow\)x-2=90:3
\(\Leftrightarrow\)x-2=30
\(\Leftrightarrow\)x=30+2
\(\Leftrightarrow\)x=32
Vậy x=32
( x + 13 ) : 5 = 120
\(\Leftrightarrow\)x + 13 = 120 \(\times\)5
\(\Leftrightarrow\)x + 13 = 600
\(\Leftrightarrow\)x = 600 - 13
\(\Leftrightarrow\)x = 587
Vậy x = 587
360:(x-7)=90
\(\Leftrightarrow\)x-7=360:90
\(\Leftrightarrow\)x-7=40
\(\Leftrightarrow\)x=40+7
\(\Leftrightarrow\)x=47
Vậy x=47
7.x + 2.x = 927
x.(7 + 2) = 927
x.9 = 927
x = 927 : 9
x = 103
Vậy x = 103
3(x - 2) + 150 = 240
3(x - 2) = 240 - 150
3.(x - 2) = 90
x - 2 = 90 : 3 = 30
x = 30 + 2 = 32
Vậy x = 32
(x + 13) : 5 = 120
x + 13 = 120 x 5 = 600
x = 600 - 13 = 587
Vậy x = 587
360:(x - 7) = 90
x - 7 = 360 : 90 = 4
x = 4 + 7 = 11
Vậy x = 11
Ủng hộ mk nha !!! ^_^
a,[120-12*5]:6
=[120-60]:6
=60:6
=10
b,494-[75+35:5]*2
=494-[75+7]*2
=494-82*2
=494-164
=330
c,1/4+[3/4:1/2]*5/6
=1/4+3/2*5/6
=1/4+5/4
=3/3
d,[360-15*6]:5
=[360-90]:5
=270:5
=54
a) (120-12*5):6= (120-60):6=60:6=10
b) 494-(75+35:5)*2= 494-(75+7)*2=494-82*2=494-164=330
c)1/4+(3/4:1/2)*5/6=1/4+3/2*5/6=1/4+5/4=6/4=3/2
d)(360-15*6):5=(360-90):5=270:5=54
Bài 1:
a: UCLN(150;1200)=150
UC(150;1200)=Ư(150)={1;2;3;5;6;10;15;25;30;50;75;150}
b: UCLN(120;160;40)=40
ƯC(120;160;40)=Ư(40)={1;2;4;5;8;10;20;40}
Bài 2:
\(\Leftrightarrow x\inƯC\left(360;930;450\right)\)
\(\Leftrightarrow x\inƯ\left(90\right)\)
mà x>30
nên \(x\in\left\{45;90\right\}\)
\(12\left(x+5\right)+2x=130\\\Leftrightarrow 12x+60+2x=130\\ \Leftrightarrow14x=70\\ \Leftrightarrow x=5\\ ----\\ 23\left(x-5\right)-12x=138\\ \Leftrightarrow23x-115-12x=138\\ \Leftrightarrow23x-12x=138+115\\ \Leftrightarrow11x=253\\ \Leftrightarrow x=\dfrac{253}{11}=23\\ ----\\ 360-12x+23\left(x-5\right)=278\\ \Leftrightarrow360-12x+23x-115=278\\ \Leftrightarrow-12x+23x=278+115-360\\ \Leftrightarrow11x=33\\ \Leftrightarrow x=\dfrac{33}{11}=3\)
\(6\left(x+3\right)+3\left(x-5\right)=278\\ \Leftrightarrow6x+18-3x-15=278\\ \Leftrightarrow6x-3x=278+15-18\\ \Leftrightarrow3x=275\\ \Leftrightarrow x=\dfrac{275}{3}\\ ---\\ \left(7-x\right)\left(3x-90\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}7-x=0\\3x-90=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=30\end{matrix}\right.\)
a, 70=2.5.10; 90=2.32.5
=> ƯCLN(70;90)=2.5=10 => ƯC(70;90)=Ư(10)={1;2;5;10}
b, 180=22.32.5 ; 235= 47.5; 120=23.3.5
=> ƯCLN(180;235;120)= 5 => ƯC(180;235;120)=Ư(5)={1;5}
Mình xét ước tự nhiên thui ha
Trên là bài 1, dưới này là bài 2!
a, 480 và 720 đều chia hết cho x
480=25.3.5; 720= 24.32.5
=> ƯCLN(480;720)=24.3.5=240
=> x=ƯCLN(480;720)=240
b, 240 và 360 đều chia hết cho x
240=24.3.5; 360=23.32.5
=>ƯCLN(240;360)=23.3.5=120
x=ƯCLN(240;360)=120
C1:\(a,360:\left(3.5\right)\)
\(=360:15\)
\(=24\)
C2:\(\left(360:3\right):5\)
\(=120:5\)
\(=24\)
C1:\(b,1440:\left(2.5\right)\)
\(=1440:10\)
\(=144\)
C2:\(\left(1440:2\right):5\)
\(=720:5\)
\(=144\)
ĐẶT \(\frac{x}{2}=\frac{y}{5}=k\)
=>\(\hept{\begin{cases}x=2k\\y=5k\end{cases}}\)
Ta có xy=360
(=)2k.5k=360
(=)10\(k^2\)=360
(=)\(k^2=36\)
=>\(\orbr{\begin{cases}k=6\\k=-6\end{cases}}\)
*Với k=6=>\(\hept{\begin{cases}x=12\\y=30\end{cases}}\)
*Với k=-6=>\(\hept{\begin{cases}x=-12\\y=-30\end{cases}}\)
=>3x+120=360
=>3x=240
=>x=80
120-2.x+5.x=360
=>3x+120=360
=>3x=240
=>x=80
-Chú thích dấu x=.