650 = xx
tìm x
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x+650+10=650+90
x+650+10=740
x+650=740-10
x+650=730
x=730-650
x=80
ai k mik mik k lại
thề luôn
\(\frac{1}{3}.x+650\%x-x=-6\)
\(x.\left(\frac{1}{3}+650\%-1\right)=-6\)
\(\frac{35}{6}.x=-6\)
\(x=-6:\frac{35}{6}\)
\(x=-\frac{36}{35}\)
~ Thiên Mã ~
\(\frac{1}{3}x+650\%x-x=-6\)
\(\frac{1}{3}x+\frac{13}{2}x-x=-6\)
\(x\left(\frac{1}{3}+\frac{13}{2}-1\right)=-6\)
\(x\left(\frac{2}{6}+\frac{39}{6}-\frac{6}{6}\right)=-6\)
\(x\frac{35}{6}=-6\)
\(x=-6.\frac{35}{6}\)
\(x=-35\)
\(\Rightarrow x=-35\)
\(\frac{1}{3}x+650\%\cdot x-x=\left(-6\right)\)
\(\Rightarrow\frac{1}{3}x+6,5\cdot x-x=\left(-6\right)\)
\(\Rightarrow x\left(\frac{1}{3}+6,5-1\right)=\left(-6\right)\)
\(\Rightarrow x\left(\frac{1}{3}+\frac{13}{2}-1\right)=\left(-6\right)\)
\(\Rightarrow x\left(\frac{2}{6}+\frac{39}{6}-\frac{6}{6}\right)=\left(-6\right)\)
\(\Rightarrow x\left(\frac{2+39-6}{6}\right)=\left(-6\right)\)
\(\Rightarrow x\cdot\frac{35}{6}=\left(-6\right)\)
\(\Rightarrow x=\left(-6\right):\frac{35}{6}\)
\(\Rightarrow x=-\frac{36}{35}\)
5x + 5x+3 = 630 (5x + 5x+3 = 650 là sai nhang bạn)
=> 5x . (1 + 53) = 630
=> 5x . 126 = 630 => 5x =5 => x=1
5x + 5x +2 = 650
5x + 5x . 52 = 650
5x .( 1 +25 ) = 650
5x .26 = 650
5x = 650 / 26 =25
5x = 52
nên x=2
cả 2 "x"luôn nhé