Các bạn giải giúp mình nha:
- \(\frac{-5}{7}\)\(=\frac{70}{x-3}\)
- \(2.3^x-5=7\)
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1
\(2.3^x-5=7\)
\(2.3^x\) \(=7-5\)
\(3^x\) \(=2:2\)
\(3^x\) \(=1\)
\(x\) \(=0\)
2x/5 - 1 = 1/7 : -1/5
2x/5 - 1 = -5/7
2x / 5 = -5/7 + 1
2x / 5 =2/7
=> 7( 2x ) = 2.5
=> 14x = 10
=> x = 10 : 14
=> x = 5/7
\(\frac{-1}{5}\times\left(\frac{2x}{5}-1\right)=\frac{1}{7}\)
\(\frac{2x}{5}-1=\frac{1}{7}\div\left(-\frac{1}{5}\right)\)
\(\frac{2x}{5}-1=\frac{1}{7}\times\left(-5\right)\)
\(\frac{2x}{5}-1=-\frac{5}{7}\)
\(\frac{2x}{5}=-\frac{5}{7}+1\)
\(\frac{2x}{5}=\frac{-5+7}{7}\)
\(\frac{2x}{5}=\frac{2}{7}\)
\(x=\frac{2}{7}\div\frac{2}{5}\)
\(x=\frac{2}{7}\times\frac{5}{2}\)
\(x=\frac{5}{7}\)
\(\frac{x}{2}-\left(\frac{3}{5}x-\frac{13}{5}\right)=-\left(\frac{7}{5}+\frac{7}{10}x\right)\)
\(\Rightarrow\frac{5x-6x+26+14+7x}{10}=0\Rightarrow6x+40=0\Rightarrow x=-\frac{20}{3}\)
1) \(\left|x-\frac{3}{5}\right|< \frac{1}{3}\)
\(\Rightarrow\orbr{\begin{cases}x-\frac{3}{5}< \frac{1}{3}\\x-\frac{3}{5}< -\frac{1}{3}\end{cases}}\Rightarrow\orbr{\begin{cases}x< \frac{1}{3}+\frac{3}{5}\\x< \frac{-1}{3}+\frac{3}{5}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x< \frac{5}{15}+\frac{9}{15}\\x< \frac{-5}{15}+\frac{9}{15}\end{cases}}\Rightarrow\orbr{\begin{cases}x< \frac{14}{15}\\x< \frac{4}{15}\end{cases}}\)
vay \(\orbr{\begin{cases}x< \frac{14}{15}\\x< \frac{4}{15}\end{cases}}\)
2) \(\left|x+\frac{11}{2}\right|>\left|-5,5\right|\)
\(\left|x+\frac{11}{2}\right|>5,5\)
\(\Rightarrow\orbr{\begin{cases}x+\frac{11}{2}>\frac{11}{2}\\x+\frac{11}{2}>-\frac{11}{2}\end{cases}}\Rightarrow\orbr{\begin{cases}x>\frac{11}{2}-\frac{11}{2}\\x>\frac{-11}{2}-\frac{11}{2}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x>0\\x>-11\end{cases}}\)
vay \(\orbr{\begin{cases}x>0\\x>-11\end{cases}}\)
3) \(\frac{2}{5}< \left|x-\frac{7}{5}\right|< \frac{3}{5}\)
\(\Rightarrow\left|x-\frac{7}{5}\right|>\frac{2}{5}\) va \(\left|x-\frac{7}{5}\right|< \frac{3}{5}\)
\(\Rightarrow\orbr{\begin{cases}x-\frac{7}{5}>\frac{2}{5}\\x-\frac{7}{5}>\frac{-2}{5}\end{cases}}\Rightarrow\orbr{\begin{cases}x>\frac{2}{5}+\frac{7}{5}\\x>\frac{-2}{5}+\frac{7}{5}\end{cases}}\)va \(\orbr{\begin{cases}x-\frac{7}{5}< \frac{3}{5}\\x-\frac{7}{5}< \frac{-3}{5}\end{cases}}\Rightarrow\orbr{\begin{cases}x< \frac{3}{5}+\frac{7}{5}\\x< \frac{-3}{5}+\frac{7}{5}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x>\frac{9}{5}\\x>1\end{cases}}\)va \(\orbr{\begin{cases}x< 2\\x< \frac{4}{5}\end{cases}}\)
vay ....
Ta có: \(\frac{4}{7}< \frac{x}{10}< \frac{5}{7}\)
Ta lại có: \(\frac{8}{14}< \frac{x}{14}< \frac{x}{10}< \frac{10}{14}\)
\(\Rightarrow\frac{8}{14}< \frac{9}{14}< \frac{9}{10}< \frac{10}{14}\)
Vậy giá trị của x là 9.
Ta có:
\(\frac{4}{7}< \frac{x}{10}< \frac{5}{7}\)
\(\Rightarrow\frac{40}{70}< \frac{7x}{70}< \frac{50}{70}\)
\(\Rightarrow40< 7x< 50\)
Vì \(7x⋮7\)
\(\Rightarrow7x\in\left\{42;49\right\}\)
\(\Rightarrow x\in\left\{6;7\right\}\)
Vậy: x = 6 hoặc x = 7
\(x=\frac{2}{3}:\frac{-7}{5}\)
\(x=\frac{2}{3}.\frac{5}{-7}\)
\(x=\frac{2.5}{3.\left(-7\right)}\)
\(x=\frac{10}{-21}\)
1. Vì -5/7=70/x-3 =>-5.(x-3)=70.7
=>5x-15=490
=>5x=505
=>x=101
2. Vì 2.3^x-5=7
=>2.3^x=12
=>3^x=6
Sai đề rồi bạn ơi! ^.^
1. \(\Leftrightarrow\)-5*(x-3) = 70*7
\(\Leftrightarrow\)-5x + 15 = 490
\(\Leftrightarrow\)-5x = 435
\(\Leftrightarrow\)x = -87
2. 2*3x -5 =7
\(\Leftrightarrow\)2*3x = 12
\(\Leftrightarrow\)3x = 6
\(\Leftrightarrow\)x = 2
( Bài 2 em xem lại coi có sai đề không nha. Không có cái nào mà 3x = 6 hết, chỉ có 3x=6 thôi nha)