Question

[Nguyễn Thị Gia Linh]

GIÚP MK VỚI

Answer 1

[『Kuroba ム Tsuki Ryoo ︵²ᵏ⁷』]

`@` `\text {Ans}`

`\downarrow`

`1)`

\(A=\dfrac{5}{7}+\dfrac{3}{4}+\dfrac{1}{5}+\dfrac{2}{7}+\dfrac{1}{4}\)

`=`\(\left(\dfrac{5}{7}+\dfrac{2}{7}\right)+\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\dfrac{1}{5}\)

`=`\(1+1+\dfrac{1}{5}=\dfrac{11}{5}\)

Vậy, `A=`\(\dfrac{11}{5}\)

`2)`

\(B=4\dfrac{4}{9}\div\dfrac{8}{3}+\dfrac{2}{3}\div2\dfrac{2}{3}\)

`=`\(\dfrac{40}{9}\times\dfrac{3}{8}+\dfrac{2}{3}\times\dfrac{3}{8}\)

`=`\(\dfrac{3}{8}\times\left(\dfrac{40}{9}+\dfrac{2}{3}\right)\)

`=`\(\dfrac{3}{8}\times\dfrac{46}{9}=\dfrac{23}{12}\)

Vậy, `B =`\(\dfrac{23}{12}\)

`3)`

\(C=\dfrac{2}{15}\times\dfrac{13}{27}+\dfrac{2}{15}\times\dfrac{14}{27}\)

`=`\(\dfrac{2}{15}\times\left(\dfrac{13}{27}+\dfrac{14}{27}\right)\)

`=`\(\dfrac{2}{15}\times1=\dfrac{2}{15}\)

Vậy, `C=`\(\dfrac{2}{15}\)

`4)`

\(D=40,35+112,37-18,35+17,63\)

`=`\(\left(40,35-18,35\right)+\left(112,37+17,63\right)\)

`= 22+130`

`= 152`

Vậy, `D = 152.`