Question

[o0o Hoàng Tử Lạnh Lùng o0o]

Tính giá trị biểu thức

A=1+2-3-4+5+6-7-8+...(2018 số hạng)

B=1.99+2.98+3.97+...+99.1+98.2

Answer 1

[tran huyen trang]

a bn tự lm nha mk lm đỡ bn phần b

b=1.99+1.98+3.97+...+98.2+99.1

= 1.99+2.(99-1)+3.(99-2)+...+98.(99-97)+99.(99-98)

= 1.99+2.99-1.2+3.99-2.3+...98.99-97.98+99.99-99.98

=(1.99+2.99+3.99+...+98.99+99.99)-(1.2+2.3+...+98.99)

=99.(1+2+3+...+98+99)-(1.2+2.3+...+98.99)

=99.4950-(1.2+2.3+...+98.99)

=490050-(1.2+2.3+...+98.99)

b=1.2+2.3+...+98.99

3b=1.2.3+2.3.3+...+98.99.3

3b=1.2.3+2.3.(4-1)+...+98.99.(100-97)

3b=1.2.3+2.3.4+2.3.1+...+98.99.100+98.00.97

3b=490050-(98.99.100):3

b=490050-323400

b=166650

tk mk nha

Answer 2

[Việt Hoàng ( Tiếng Anh + Toán )]

=1.99+2.(99-1)+3.(99-2)+...+98.(99-97)+99(99-98)

=99.(1+2+3+4+...+98+99)-(2+2.3+3.4+...+97.98+98.99)

=99.(1+99).99/2-98.99.100/3

=99.50.99-98.33.100

=490050-323400

=166650