Tìm x biết 2x = 2 + 2 + 22 + . . . + 230
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a, 36:(x–5) = 2 2
(x–5) = 9
x = 14
b, [3.(70–x)+5]:2 = 46
[3.(70–x)+5] = 92
70–x = 29
x = 41
c, 450:[41–(2x–5)] = 3 2 .5
41–(2x–5) = 10
2x–5 = 31
2x = 36
x = 18
d, 230+[ 2 4 +(x–5)] = 315. 2018 0
16+(x–5) = 315–230
x–5 = 85–16
x = 69+5
x = 74
e, 2 x + 2 x + 1 = 48
2 x .(2+1) = 48
2 x = 16 = 2 4
x = 4
f, 3 x + 2 + 3 x = 2430
3 x . 3 2 + 1 = 2430
3 x = 2430:10 = 243 = 3 5
x = 5
\(1,\\ \left(x-7\right)^{x+1}-\left(x-7\right)^{x+11}=0\\ \Leftrightarrow\left(x-7\right)^{x+1}\left[1-\left(x-7\right)^{10}\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}\left(x-7\right)^{x+1}=0\\\left(x-7\right)^{10}=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x-7=0\\x-7=1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=7\\x=8\end{matrix}\right.\)
\(2,\\ a,\left|2x-3\right|>5\Leftrightarrow\left[{}\begin{matrix}2x-3< -5\\2x-3>5\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x< -1\\x>4\end{matrix}\right.\\ b,\left|3x-1\right|\le7\Leftrightarrow\left[{}\begin{matrix}3x-1\le7\\1-3x\le7\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x\le\dfrac{8}{3}\\x\ge-2\end{matrix}\right.\\ c,\cdot x< -\dfrac{3}{2}\\ \Leftrightarrow5-3x+\left(-2x-3\right)=7\Leftrightarrow2-5x=7\Leftrightarrow x=-1\left(ktm\right)\\ \cdot-\dfrac{3}{2}\le x\le\dfrac{5}{3}\\ \Leftrightarrow\left(5-3x\right)+\left(2x+3\right)=7\Leftrightarrow8-x=7\Leftrightarrow x=1\left(tm\right)\\ \cdot x>\dfrac{5}{3}\\ \Leftrightarrow\left(3x-5\right)+\left(2x+3\right)=7\Leftrightarrow5x-2=7\Leftrightarrow x=\dfrac{9}{5}\left(tm\right)\\ \Leftrightarrow S=\left\{1;\dfrac{9}{5}\right\}\)
Ta có : (2x + 3)2 - (2x + 1)(2x - 1) = 22
=> 4x2 + 12x + 9 - 4x2 + 1 = 22
=> 12x + 10 = 22
=> 12x = 12
=> x = 1
Vậy x = 1
\(\left(2x+3\right)^2-\left(2x+1\right)\left(2x-1\right)=22\)
\(\Leftrightarrow\left(2x+3\right)^2-\left(4x^2-1\right)=22\)
\(\Leftrightarrow\left(2x+3\right)^2-4x^2+1=22\)
\(\Leftrightarrow\left(2x+3-2x\right)\left(2x+3+2x\right)=21\)
\(\Leftrightarrow3.\left(4x+3\right)=21\)
\(\Leftrightarrow4x+3=7\)
\(\Leftrightarrow4x=4\)
\(\Leftrightarrow x=1\)
Vậy \(x=1\)
a/ \(\left(2x+3\right)^2-\left(2x+1\right)\left(2x-1\right)=22\)
<=> \(\left(2x+3\right)^2-\left(4x^2-1\right)=22\)
<=> \(\left(2x+3\right)^2-4x^2+1=22\)
<=> \(\left(2x+3-2x\right)\left(2x+3+2x\right)=21\)
<=> \(3\left(4x+3\right)=21\)
<=> \(4x+3=7\)
<=> \(4x=4\)
<=> \(x=1\)
......................?
mik ko biết
mong bn thông cảm
nha ................
a) 22 + (2x -13) = 83 => 2x -13 = 61 => x = 37.
b) 51 - (-12 + 3x) = 27 => 63 - 3x = 27 => x = 12.
c) - (2x + 2) + 21 = - 23 => 2x + 2 = 44 => x = 21.
d) 25 - (25 - x) = 0 => 25 - 25 + x = 0 => x = 0.
Tìm x ∈ N
a) 2x chia hết cho 12 ⇒ 2x ∈ B(12)
2x chia hết cho 30 ⇒ 2x ∈ B(30)
Mà x có hai chữ số ⇒ 10 ≤ x ≤ 99
\(\Rightarrow2x\in BC\left(12;30\right)\)
Mà: \(B\left(12\right)=\left\{0;12;24;36;48;60;72;84;96;108;...\right\}\)
\(B\left(30\right)=\left\{0;30;60;90;120;...\right\}\)
\(\Rightarrow BC\left(12;30\right)=\left\{0;60;...\right\}\)
\(\Rightarrow2x=60\)
\(\Rightarrow x=\dfrac{60}{2}\\ \Rightarrow x=30\)
b) \(9^{x+2}-9^{x+1}+9^x=657\)
\(\Rightarrow9^x\cdot\left(9^2-9+1\right)=957\)
\(\Rightarrow9^x\cdot\left(81-8\right)=657\)
\(\Rightarrow9^x\cdot73=657\)
\(\Rightarrow9^x=9\)
\(\Rightarrow9^x=9^1\)
\(\Rightarrow x=1\)
bạn có thể giải giùm mk bài tính nhanh đc ko??? Mk đang cần gấp á. Cảm ơn bạn nhiều nha!
a/ 2/3.x+1/2=1/10
nên:2/3x=1/10-1/2
nên:2/3x=-2/5
suy ra :x=-2/5:2/3
vậy x=-3/5
a. 2/3x+1/2=1/10
2/3x=1/10-1/2
2/3x=-2/5
x=-2/5:2/3
x=-3/5
b.(7/2-2x).4/3=22/3
(7/2-2x).=22/3:4/3
7/2-2x=11/2
2x=7/2-11/2
2x=-2
x=-1
nho k cho minh voi nhe
2 + 2 + 22 + . . . + 230
=22+22+...+230
=22.2+......+230
=23+23+....+230
=23.2+24+......+230
=24+24+.........+230
..........
.........
=229+229+230
=230+230
=230.2
=231
thay vào ta có 2 + 2 + 22 + . . . + 230=2x =231
=>x=31
vậy..............