Tìm x:
(x + 3 ) + ( x + 7 ) + ( x + 11 ) + .......... + ( x + 79 ) = 1720
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(x + 3) + (x + 7) + (x + 11) + ... + (x + 79) = 860
=> x + 3 + x + 7 + x + 11 + ... + x + 79 = 860
=> (x + x + x + ... + x) + (3 + 7 + 11 + ... + 79) = 860
=> 20x + (79 + 3).20 : 2 = 860
=> 20x + 82.20 : 2 = 860
=> 20x + 82.10 = 860
=> 20x + 820 = 860
=> 20x = 40
=> x = 2
vậy_
#)Giải :
\(\left(x+3\right)+\left(x+7\right)+...+\left(x+79\right)=860\)
\(\left(x+x+...+x\right)+\left(3+7+...+79\right)=860\)(trong mỗi ngoặc có 20 số hạng)
\(x\times20+\frac{\left(79+3\right)\times20}{2}=860\)
\(x\times20+820=860\)
\(x\times20=860-820\)
\(x\times20=40\)
\(x=40\div20\)
\(x=2\)
(x+3)+(x+7)+(x+11)+...+(x+79)=860
(x+x+x+...+x) + (3+7+11+...+79)=860
Số lượng số hạng x là:
(79 - 3):4 + 1= 20(số hạng) (10 cặp số hạng)
Ta tiếp tục tính:
(x+x+x+...+x) + (3+7+11+...+79)=860
\(20\times X+\left(79+3\right)\times10=860\\ 20\times X+820=860\\ 20\times X=860-820=40\\ X=\dfrac{40}{20}=2\)
Vậy: X=2
Theo đề bài: (X+3)+(X+7)+(X+11)+...........+(X+79)=860
X.20+(3+7+11+.........+79)=86
SSH: (79-3):4+1:2=10 (cặp)
SC:79+3=82
3+7+11+.....+79=10.82=820
X.20+820=860
X.20 =860-820=40
X =40:20
X =2
Đ/S;X=2
\(\left(x+3\right)+\left(x+7\right)+\left(x+11\right)+...+\left(x+79\right)=860\)
\(\Leftrightarrow20x+\left(3+7+11+...+79\right)=860\)
\(\Leftrightarrow20x+20.\frac{79+3}{2}=860\)
\(\Leftrightarrow20x+820=860\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
(x+x+....+x)+(3+7+11+.....+79)=860
20x+820=860
20x=860-820
20x=40
x=40:20
x=2
Fan tf thì kb nha
a) Dãy số có số số hạng là: (79 - 3) : 4 + 1 = 20
Tổng của dãy số là: (20 : 2) x (79 + 3) = 820
b) (x + 3) + (x + 7) + (x +11) +...+ (x + 79) = 860
(x + x + x +...+ x) + (3 + 7 + 11 +...+ 79) = 860
x x 20 + 820 = 860
x x 20 = 860 - 820
x x 20 = 40
x = 40 : 20
x = 2
a) \(x+5=20-\left(12-7\right)\)
\(\Rightarrow x+5=20-5\)
\(\Rightarrow x+5=15\)
\(\Rightarrow x=15-5\)
\(\Rightarrow x=10\)
b) \(15-\left(3+2x\right)=2^2\)
\(\Rightarrow3+2x=15-4\)
\(\Rightarrow3+2x=11\)
\(\Rightarrow2x=11-3\)
\(\Rightarrow2x=8\)
\(\Rightarrow x=\dfrac{8}{2}\)
\(\Rightarrow x=4\)
c) \(-11-\left(19-x\right)=50\)
\(\Rightarrow19-x=-11-50\)
\(\Rightarrow19-x=-61\)
\(\Rightarrow x=61+19\)
\(\Rightarrow x=80\)
d) \(159-\left(25-x\right)=43\)
\(\Rightarrow25-x=159-43\)
\(\Rightarrow25-x=116\)
\(\Rightarrow x=25-116\)
\(\Rightarrow x=-91\)
e) \(\left(79-x\right)-43=-\left(17-52\right)\)
\(\Rightarrow\left(79-x\right)-43=52-17\)
\(\Rightarrow79-x-43=35\)
\(\Rightarrow36-x=35\)
\(\Rightarrow x=1\)
f) \(\left(7+x\right)-\left(21-13\right)=32\)
\(\Rightarrow7+x-8=32\)
\(\Rightarrow x-1=32\)
\(\Rightarrow x=32+1\)
\(\Rightarrow x=33\)
g) \(-x+20=-15+8+13\)
\(\Rightarrow-x+20=6\)
\(\Rightarrow x=20-6\)
\(\Rightarrow x=14\)
h) \(-\left(-x+13-142\right)+18=55\)
\(\Rightarrow x-13+142+18=55\)
\(\Rightarrow x+147=55\)
\(\Rightarrow x=55-147\)
\(\Rightarrow x=-92\)
a) 49 x ( X – 21 ) = 441 e) X : (12 + 13) = 7
X – 21 = 441:49 X : 25 = 7
X – 21 = 9 X = 7 x 25
X = 21 + 9 X = 175
X = 30
b) 53 x 31 x X = 4929 g) 429 : ( X + 31) = 11
31 x X = 4929 : 53 X + 31 = 429 : 11
31 x X = 93 X + 31 = 39
X = 93 : 31 ’ X = 39 – 31
X = 3 X = 8
c) 61 x (126 : X ) = 1281 h) 1 615 : (X x 19) = 17
126 : X = 1281 : 61 X x 19 = 1 615 : 17
126 : X = 21 X x 19 = 95
X = 126 : 21 X = 95 : 19
X = 6 X = 5
d) 79 x ( X : 23 ) = 316 i) 420 : ( X : 39 ) = 105
X : 23 = 316 : 79 X : 39 = 420 : 105
X : 23 = 4 X : 39 = 4
X = 4 x 23 X = 4 x 39
X = 92 X = 156
1: \(\Leftrightarrow\left(\dfrac{x+1}{85}+1\right)+\left(\dfrac{x+3}{83}+1\right)=\left(\dfrac{x+5}{81}+1\right)+\left(\dfrac{x+7}{79}+1\right)\)
=>x+86=0
=>x=-86
2: \(\Leftrightarrow\left(\dfrac{x-1}{2015}+1\right)-\left(\dfrac{x+3}{2011}+1\right)=\left(\dfrac{x+7}{2007}+1\right)-\left(\dfrac{x+11}{2003}+1\right)\)
=>x+2014=0
=>x=-2014
3: \(\Leftrightarrow3\left(x+4\right)-2\left(x-3\right)=4x\)
=>4x=3x+12-2x+6
=>4x=x+18
=>3x=18
=>x=6
4: \(\Leftrightarrow15x-5\left(x+1\right)=3\left(2x+1\right)\)
=>15x-5x-5=6x+3
=>10x-5=6x+3
=>4x=8
=>x=2
5: \(\Leftrightarrow2\left(2x-7\right)+5\left(x+11\right)=-40\)
=>4x-14+5x+55=-40
=>9x+41=-40
=>x=-9
x . 20 + ( 3 + 7 + 11 + ... + 79 ) = 1720
x . 20 + 820 = 1720
x . 20 = 1720 - 820
x . 20 = 900
x = 900 : 20
x = 45
(x + 3 ) + ( x + 7 ) + ( x + 11 ) + .......... + ( x + 79 ) = 1720
x . 20 + ( 3 + 7 + 11 + ... + 79 ) = 1720
x . 20 + 820 = 1720
x . 20 = 1720 - 820
x . 20 = 900
x = 900 : 20
x = 45