(7x-11)^3=2^5.5^2+100
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(7x - 11)^3 = 2^ 5 .5^2+200 = 1000
(7x - 11)^3 = 10^ 3
=> 7x - 11 = 10
=> 7x = 21 =>
x = 3
(7x-11)^3=2^5.5^2+200
(7x-11)^3=1000
7x-11 =10
7x =10+11
7x =21
x =21:7
x =3
\(\left(7x-11\right)^3=2^5.5^2+200\)
\(\Leftrightarrow\left(7x-11\right)^3=1000\)
\(\Leftrightarrow7x-11=10\)
\(\Leftrightarrow7x=21\)
\(\Leftrightarrow x=3\)
\(\left(7x-11\right)^3=2^5.5^2+200\)
\(\Rightarrow\left(7x-11\right)^3=32.25+200\)
\(\Rightarrow\left(7x-11\right)^3=800+200\)
\(\Rightarrow\left(7x-11\right)^3=1000=10^3\)
\(\Rightarrow7x-11=10\)
\(\Rightarrow7x=21\)
\(\Rightarrow x=3\)
Ta có: \(\left(7x-11\right)^3=2^5+5^2+200=1000\)
\(\Rightarrow\left(7x-11\right)^3=10^3\)
\(\Rightarrow7x-11=10\)
\(\Rightarrow7x=21\)
\(\Rightarrow x=3\)
Trả lời:
\(\left(7x-11\right)^3=2^5.5^2+200\)
\(\Leftrightarrow\left(7x-11\right)^3=32.25+200\)
\(\Leftrightarrow\left(7x-11\right)^3=800+200\)
\(\Leftrightarrow\left(7x-11\right)^3=1000\)
\(\Leftrightarrow7x-11=10\)
\(\Leftrightarrow7x=21\)
\(\Leftrightarrow x=3\)
Vậy\(x=3\)
Hok tốt!
Good girl
\(\Leftrightarrow\left(7x-11\right)^3=32\cdot25+200=1000\)
=>7x-11=10
=>x=3
(7x-11)3=25.52+200
(7x-11)3=1000
(7x-11)3=103
7x-11=10
7x=10+11
7x=21
x=21:7
x=3
( 7x - 11 ) 3 = 32 . 25 + 200
( 7x - 11 ) 3 = 800 + 200
( 7x - 11 ) 3 = 1000
( 7x - 11 ) 3 = 103
7x - 11 = 10
7x = 10 + 11
7x = 21
x = 21 : 7
x = 3
(7x−11)3 = 25 . 52 + 200
(7x−11)3 = 32 . 25 + 200
(7x−11)3 = 1000
(7x−11)3 = 103
7x−11 = 10
7x = 10 + 11
7x = 21
x = 21 : 7
x = 3
(7x-11)3=25.52+200
(7x-11)3=32.25+200
(7x-11)3=800+200
(7x-11)3=1000
(7x-11)3=103
=> 7x-11=10
7x=10+11
7x=21
x=21/7
x=3
(7x-11)3 = 25.52+ 23.52
(7x-11)3 = 23.52( 22+1)
(7x-11)3 = 23.53=(2.5)3
7x-11=10
x=3
`@` `\text {Ans}`
`\downarrow`
`(7x - 11)^2 = 2^5 * 5^2 + 100?`
`=> (7x - 11)^2 = 32*25 + 100`
`=> (7x - 11)^2 = 800 + 100`
`=> (7x - 11)^2 = 900`
`=> (7x - 11)^2 = (+-30)^2`
`=>`\(\left[{}\begin{matrix}7x-11=30\\7x-11=-30\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}7x=41\\7x=-19\end{matrix}\right.\)
`=>`\(\left[{}\begin{matrix}x=\dfrac{41}{7}\\x=-\dfrac{19}{7}\end{matrix}\right.\)
Vậy, `x \in`\(\left\{\dfrac{41}{7};-\dfrac{19}{7}\right\}\)