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A,248x(36+62)-148x(62+36)
B,107x195+107x175-107x150
C,(2020x99+2020)-(2019x101-2019)
Giúp mik ạ
`@` `\text {Ans}`
`\downarrow`
`A,`
`248 \times (36 + 62) - 148 \times (62 + 36)`
`= (36+62) \times (248 - 148)`
`= 98 \times 100`
`= 9800`
`B,`
`107 \times 195 + 107 \times 175 - 107 \times 150`
`= 107 \times (195 + 175 - 150)`
`= 107 \times 220`
`= 23540`
`C,`
`(2020 \times 99 + 2020) - (2019 \times 101 - 2019)`
`= 2020 \times (99+1) - 2019 \times (101-1)`
`= 2020 \times 100 - 2019 \times 100`
`= 100 \times (2020 - 2019)`
`= 100 \times 1`
`= 100`
A. 248x(36+62)-148x(62+36)
=(36+62)x(248-148)
=98x100
=9800
B.107x195+107x175-107x150
=107x(195+175-150)
=107x220
=23540
C.(2020x99+2020)-(2019x101-2019)
=(2020x(99+1))-(2019x(101-1))
=(2020x100)-(2019x100)
=202000-201900
=100
`@` `\text {Ans}`
`\downarrow`
`A,`
`248 \times (36 + 62) - 148 \times (62 + 36)`
`= (36+62) \times (248 - 148)`
`= 98 \times 100`
`= 9800`
`B,`
`107 \times 195 + 107 \times 175 - 107 \times 150`
`= 107 \times (195 + 175 - 150)`
`= 107 \times 220`
`= 23540`
`C,`
`(2020 \times 99 + 2020) - (2019 \times 101 - 2019)`
`= 2020 \times (99+1) - 2019 \times (101-1)`
`= 2020 \times 100 - 2019 \times 100`
`= 100 \times (2020 - 2019)`
`= 100 \times 1`
`= 100`
A. 248x(36+62)-148x(62+36)
=(36+62)x(248-148)
=98x100
=9800
B.107x195+107x175-107x150
=107x(195+175-150)
=107x220
=23540
C.(2020x99+2020)-(2019x101-2019)
=(2020x(99+1))-(2019x(101-1))
=(2020x100)-(2019x100)
=202000-201900
=100