Question

[Bảo Trân]

  

Answer 1

[Gia Huy]

a)

+) \(n_{iron}=\dfrac{28}{56}=0,5\left(mol\right)\)

Số nguyên tử iron: \(0,5.6.10^{23}=3.10^{23}\)(nguyên tử)

+) \(n_{copper}=\dfrac{6,4}{64}=0,1\left(mol\right)\)

Số nguyên tử copper: \(0,1.6.10^{23}=6.10^{22}\) (nguyên tử)

+) \(n_{aluminium}=\dfrac{9}{27}=\dfrac{1}{3}\left(mol\right)\)

Số nguyên tử aluminium: \(\dfrac{1}{3}.6.10^{23}=2.10^{23}\) (nguyên tử)

b)

+) \(m_{H_2}=2.2=4\left(g\right)\)

\(V_{H_2\left(đkc\right)}=2.24,79=49,58\left(l\right)\)

+) \(m_{O_2}=1,5.32=48\left(g\right)\)

\(V_{H_2\left(đkc\right)}=1,5.24,79=37,185\left(l\right)\)

+) \(m_{CO_2}=1,15.44=50,6\left(g\right)\)

\(V_{CO_2\left(đkc\right)}=1,15.24,79=28,5085\left(l\right)\)

+) \(m_{CH_4}=1,15.16=18,4\left(g\right)\)

\(V_{CH_4\left(đkc\right)}=1,15.24,79=28,5085\left(l\right)\)