2404+540:[x-6]=4040
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2404+540:(x-6)=4040
540:(x-6)=4040-2404
540:(x-6)=1636
x-6=540:1636
x-6=\(\frac{135}{409}\)
x=\(\frac{135}{409}\)+6
x=\(6\frac{135}{409}\)
tick dung nha
\(|x^{2018}+|x+1||=x^{2018}+2404\)
\(\Rightarrow x^{2018}+\left|x+1\right|=x^{2018}+2404\)
\(\Rightarrow\left|x+1\right|=2404\)
\(\Rightarrow\orbr{\begin{cases}x+1=2404\\x+1=-2404\end{cases}\Rightarrow}\orbr{\begin{cases}x=2403\\x=-2405\end{cases}}\)
\(\left|x^{2018}+|x-1|\right|=x^{2018}+2404\)
\(\Leftrightarrow x^{2018}+\left|x-1\right|=x^{2018}+2404\)
\(\Leftrightarrow\left|x-1\right|=2404\)
\(\Leftrightarrow\orbr{\begin{cases}x-1=2404\\x-1=-2404\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2405\\x=-2403\end{cases}}}\)
\(|x^{2018}+|x-1||=x^{2018}+2404\)
\(\Leftrightarrow\orbr{\begin{cases}x^{2018}+|x-1|=-x^{2018}-2404\\x^{2018}+|x-1|=x^{2018}+2404\end{cases}\Leftrightarrow\orbr{\begin{cases}|x-1|=-\left(2x^{2018}+2404\right)\left(l\right)\\|x-1|=2404\left(n\right)\end{cases}}}\)
\(\Leftrightarrow\orbr{\begin{cases}x-1=-2404\\x-1=2404\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-2403\\x=2405\end{cases}}}\)
V...
\(\left|x^{2018}+\left|x-1\right|\right|=x^{2018}+2404\)
Ta thấy: \(x^{2018}\ge0\);\(\left|x-1\right|\ge0\)\(\Rightarrow x^{2018}+\left|x-1\right|\ge0\)
\(\Rightarrow\left|x^{2018}+\left|x-1\right|\right|=x^{2018}+2404\)
\(\Leftrightarrow x^{2018}+\left|x-1\right|=x^{2018}+2404\)
\(\left|x-1\right|=2404\)
\(\Rightarrow\orbr{\begin{cases}x-1=2404\\x-1=-2404\end{cases}}\Rightarrow\orbr{\begin{cases}x=2405\\x=-2403\end{cases}}\)
Vậy \(x\in\left\{2405;-2403\right\}\)
\(5x\left(x-2020\right)-2x+4040=0\)
\(\Rightarrow5x\left(x-2020\right)-2\left(x-2020\right)=0\)
\(\Rightarrow\left(x-2020\right)\left(5x-2\right)=0\)
\(\Rightarrow\left\{{}\begin{matrix}x-2020=0\\5x-2=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=2020\\x=\dfrac{2}{5}\end{matrix}\right.\)
Vậy....
2404 + 540 : x - 540: 6 = 4040
2404+ 540 : x - 90 = 4040
2404 + 540 : x = 4040 +90 = 4130
540 : x = 4130 - 2404=2726
ủa sao kỳ vậy nè làm sao mà 540 : 2726 được