tính: √(√(2√6 +6 +2√2+2√3)-(√(5+2√6)))
làm ơn giúp mình với
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Đặt tổng trên = A
\(A=\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{98}+\frac{2}{192}\)
\(A.2=\frac{4}{3}+\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{98}\)
\(A.2-A=\left(\frac{4}{3}+\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{98}\right)-\left(\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{98}+\frac{2}{192}\right)\)
\(A=\frac{4}{3}-\frac{2}{192}\)
\(A=\frac{127}{96}\)
\(A=\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{98}+\frac{2}{192}\)
\(2A=\frac{4}{3}+\frac{2}{3}+\frac{2}{6}+\frac{2}{12}+\frac{2}{24}+\frac{2}{48}+\frac{2}{98}\)
\(2A-A=\frac{4}{3}-\frac{2}{192}\)
\(A=\frac{4}{3}-\frac{2}{192}=\frac{127}{96}\)
\(\frac{4}{5}.x-x-\frac{3}{2}.x+\frac{5}{6}=\frac{1}{2}-\frac{4}{3}\)đề nảy hả
\(\frac{4}{5}x-x-\frac{3}{2}x+\frac{5}{6}=\frac{1}{2}-\frac{4}{3}\)
\(-\frac{1}{5}x-\frac{3}{2}x=-\frac{5}{6}-\frac{5}{6}\)
\(-\frac{17}{10}x=-\frac{10}{6}\)
\(x=\frac{50}{51}\)
1) \(A=36x^2+12x+1=\left(6x+1\right)^2\ge0\)
\(minA=0\Leftrightarrow x=-\dfrac{1}{6}\)
2) \(B=9x^2+6x+1=\left(3x+1\right)^2\ge0\)
\(minB=0\Leftrightarrow x=-\dfrac{1}{3}\)
4) \(D=x^2-4x+y^2-8y+6=\left(x-2\right)^2+\left(y-4\right)^2-14\ge-14\)
\(minD=-14\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=4\end{matrix}\right.\)
3) \(C=\left(x+1\right)\left(x-2\right)\left(x-3\right)\left(x-6\right)=\left(x^2-5x-6\right)\left(x^2-5x+6\right)=\left(x^2-5x\right)^2-36\ge-36\)
\(minC\Leftrightarrow\left[{}\begin{matrix}x=0\\x=5\end{matrix}\right.\)
5) \(E=\left(x-8\right)^2+\left(x+7\right)^2=2x^2-2x+113=2\left(x-\dfrac{1}{2}\right)^2+\dfrac{225}{2}\ge\dfrac{225}{2}\)
\(minE=\dfrac{225}{2}\Leftrightarrow x=\dfrac{1}{2}\)
A= ( 6 - 2/3 + 1/2) -( 5 +5/3 - 3/2) - (3 - 1/3 + 5/2)
= 6 - 2/3 + 1/2 - 5 - 5/3 + 3/2 - 3 + 1/3 - 5/2
= (6-5-3) - (2/3 + 5/2 - 1/3) + (1/2 +3/2 -5/2)
= -2 - 2 + (-1/2)
= -4 -1/2
=-9/2
A = ( 6 - 1 ) - ( 5 + 1 / 6 ) - ( 3 + 13 / 6 )
A = 5 - 31 / 6 - 31 / 6
A = -16 / 3
a)\(\left(x-140\right)\)\(\div\)7=27-4-3 =20\(\Rightarrow\) \(\left(x-140\right)\) =20x7=140\(\Rightarrow\) x=0
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