Tính
\(a,\frac{5}{6}+6\frac{5}{6}.\left(11\frac{94}{1591}-6\frac{38}{1517}\right):8\frac{11}{43}\)
\(b,1\frac{1}{6}+6\frac{5}{6}.\left(10\frac{133}{2173}-5\frac{23}{1643}\right):41\frac{12}{31}\)
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\(8\frac{1}{5}\)X \(\left(11\frac{94}{1592}-6\frac{38}{1517}\right):8\frac{11}{43}\)
= \(\frac{41}{5}\)X \(\left(\frac{17606}{1592}-\frac{9140}{1517}\right):\frac{355}{43}\)
= \(\frac{41}{5}\)X \(\left(\frac{26708302}{2415064}-\frac{14550880}{2415064}\right):\frac{355}{43}\)
= \(\frac{41}{5}\)X \(\frac{12157422}{2415064}:\frac{355}{43}\)
= \(\frac{49845430200000006}{12075320}:\frac{355}{43}\)
= \(\frac{5358383746500001}{1071684650}\)
\(8\frac{1}{5}.\left(11\frac{94}{1591}-6\frac{38}{1517}\right):8\frac{11}{43}\\ =8\frac{1}{5}.5\frac{60}{1763}:8\frac{11}{43}\\ =41\frac{12}{43}:8\frac{11}{43}\\ =5\)
Trả lời
b)(1/3+12/67+13/41)-(79/67-28/41)
=1/3+12/67+13/41-79/67+28/41
=1/3+(12/67-79/67)+(13/41+28/41)
=1/3+(-67/67)+41/41
=1/3+(-1)+1
=1/3+0
=1/3.
\(A=\left[\frac{1\frac{11}{31}\cdot4\frac{3}{7}-\left(15-6\frac{1}{3}\cdot\frac{2}{19}\right)}{4\frac{5}{6}+\frac{1}{6}\left(12-5\frac{1}{3}\right)}\cdot\left(-1\frac{14}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\left[\frac{\frac{42}{31}\cdot\frac{31}{7}-\left(15-\frac{19}{3}\cdot\frac{2}{19}\right)}{4\frac{5}{6}+\frac{1}{6}\left(12-\frac{16}{3}\right)}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\left[\frac{6-\left(15-\frac{2}{3}\right)}{\frac{29}{6}+\frac{10}{9}}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\left[\frac{6-\frac{43}{3}}{\frac{107}{18}}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\left[\frac{-\frac{25}{3}}{\frac{107}{18}}\cdot\left(-\frac{107}{93}\right)\right]\cdot\frac{31}{50}\)
\(A=\frac{50}{31}\cdot\frac{31}{50}=1\)
ai tính song là banh não
Tớ ko bít phải làm sao bây giờ ?
tô ? ko ? bít ?
-_-! ai thick tích cu !