TÌM X BIẾT:
\(\frac{x}{21}\)-\(\frac{2}{3}\)=\(\frac{21}{5}\)
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1.
A=\(\frac{-5x+-5y+-5z}{21}=\frac{-5\left(x+y+z\right)}{21}=\frac{-5}{21}.x+y+z\)
A= -z+z=0
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a)\(\frac{5}{21}\)+\(\frac{-3}{7}\)<\(\frac{x}{21}\)<\(\frac{-2}{7}\)+\(\frac{8}{21}\)
\(\Rightarrow\)\(\frac{-4}{21}\)<\(\frac{x}{21}\)<\(\frac{2}{21}\)
\(\Rightarrow\)\(\frac{x}{21}\)\(\in\)\(\left\{\frac{-3}{21};\frac{-2}{21};\frac{-1}{21};\frac{0}{21};\frac{1}{21}\right\}\)
vậy x\(\in\)\(\left\{-3;-2;-1;0;1\right\}\)
\(\frac{x}{y}=\frac{2}{3}\Rightarrow\frac{x}{2}=\frac{y}{3}\Rightarrow\frac{x}{6}=\frac{y}{9}\)
\(\frac{x}{z}=\frac{3}{5}\Rightarrow\frac{x}{3}=\frac{z}{5}\Rightarrow\frac{x}{6}=\frac{z}{10}\)
\(\Rightarrow\frac{x}{6}=\frac{y}{9}=\frac{z}{10}\)
\(\Rightarrow\frac{x^2}{36}=\frac{y^2}{81}=\frac{z^2}{100}\)
Áp dụng tính chất của dãy tỉ số bằng nhau ta có :
\(\frac{x^2}{36}=\frac{y^2}{81}=\frac{z^2}{100}=\frac{x^2+y^2+z^2}{36+81+100}=\frac{21}{217}=\frac{3}{31}\)
\(\Rightarrow\hept{\begin{cases}\frac{x^2}{36}=\frac{3}{31}\\\frac{y^2}{81}=\frac{3}{31}\\\frac{z^2}{100}=\frac{3}{31}\end{cases}\Rightarrow\hept{\begin{cases}x^2=\frac{108}{31}\\y^2=\frac{243}{31}\\z^2=\frac{300}{31}\end{cases}\Rightarrow}\hept{\begin{cases}x=\left\{\pm\sqrt{\frac{108}{31}}\right\}\\y=\left\{\pm\sqrt{\frac{243}{31}}\right\}\\z=\left\{\pm\sqrt{\frac{300}{31}}\right\}\end{cases}}}\)
Vậy........
Có:\(\frac{x}{y}=\frac{2}{3}\Rightarrow3x=2y\Rightarrow\frac{3x}{12}=\frac{2y}{12}=\frac{x}{4}=\frac{y}{6}\Rightarrow\frac{x}{12}=\frac{y}{18}\left(1\right)\)
Có:\(\frac{x}{z}=\frac{3}{5}\Rightarrow5x=3z\Rightarrow\frac{5x}{15}=\frac{3z}{15}=\frac{x}{3}=\frac{z}{5}\Rightarrow\frac{x}{12}=\frac{z}{20}\left(2\right)\)
Từ (1)(2)\(\Rightarrow\frac{x}{12}=\frac{y}{18}=\frac{z}{20}\)
\(\Rightarrow\frac{x^2}{144}=\frac{y^2}{324}=\frac{z^2}{400}\)
Áp dụng tính chất dãy ti số bằng nhau ta có:
\(\frac{x^2}{144}=\frac{y^2}{324}=\frac{z^2}{400}=\frac{x^2+y^2+z^2}{144+324+400}=\frac{21}{868}=\frac{3}{124}\)
Suy ra: \(\frac{x^2}{144}=\frac{3}{124}\Rightarrow x=...\)
Tương tự tìm x,y,z.
_Học tốt_
\(\left(\frac{1}{2}+\frac{3}{4}-\frac{1}{3}\right):\frac{-5}{6}< x< \frac{4}{21}.\frac{4}{7}\)
\(\Rightarrow\left(\frac{6}{12}+\frac{9}{12}-\frac{4}{12}\right):\frac{-10}{12}< x< \frac{16}{147}\)
\(\Rightarrow\frac{11}{12}.\frac{-12}{10}< x< \frac{16}{147}\)
\(\Rightarrow\frac{-11}{10}< x< \frac{16}{147}\)
\(\Rightarrow\frac{-1617}{1470}< x< \frac{16}{1470}\)
\(x=\left\{-1;0\right\}\)
\(\frac{x}{2}=\frac{y}{3}\Rightarrow\frac{x}{10}=\frac{y}{15}\)
\(\frac{y}{5}=\frac{z}{4}\Rightarrow\frac{y}{15}=\frac{z}{12}\)
\(\Rightarrow\frac{x}{10}=\frac{y}{15}=\frac{z}{12}\)
\(\Rightarrow\frac{x-y+z}{10-15+12}=\frac{x}{10}=\frac{y}{15}=\frac{z}{12}\) mà x - y + z = -21
\(\Rightarrow\frac{-21}{7}=\frac{x}{10}=\frac{y}{15}=\frac{z}{12}\)
\(\Rightarrow-3=\frac{x}{10}=\frac{y}{15}=\frac{z}{12}\)
\(\Rightarrow\hept{\begin{cases}x=-3\cdot10=-30\\y=-3\cdot15=-45\\z=-3\cdot12=-36\end{cases}}\)
\(a/\frac{7}{9}-\frac{x}{3}=\frac{1}{9}\)
\(\Rightarrow\frac{x}{3}=\frac{7}{9}-\frac{1}{9}\)
\(\Rightarrow\frac{x}{3}=\frac{2}{3}\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
\(b/\frac{1}{x}-\frac{-2}{15}=\frac{7}{15}\)
\(\Rightarrow\frac{1}{x}=\frac{7}{15}+\frac{-2}{15}\)
\(\Rightarrow\frac{1}{x}=\frac{1}{3}\)
\(\Rightarrow x=3\)
Vậy \(x=3\)
\(c/\frac{-11}{14}-\frac{-4}{x}=\frac{-3}{14}\)
\(\Rightarrow\frac{-4}{x}=\frac{-11}{14}-\frac{-3}{14}\)
\(\Rightarrow\frac{-4}{x}=\frac{-4}{7}\)
\(\Rightarrow x=7\)
Vậy \(x=7\)
\(d/\frac{x}{21}-\frac{2}{3}=\frac{5}{21}\)
\(\Rightarrow\frac{x}{21}=\frac{5}{21}+\frac{2}{3}\)
\(\Rightarrow\frac{x}{21}=\frac{19}{21}\)
\(\Rightarrow x=19\)
Vậy \(x=19\)
#Mạt Mạt#
a,
x.2/7.3/4=5/21
x.3/14=5/21
x=5/21:3/14
x=10/9
b,
x.1/2=1/3
x=1/3:1/2
x=2/3
c,
x:4/5=25/8:5/4
x:4/5=5/2
x=5/2.4/5=2
A, x= 5/25 : 3/4 : 2/7 = 14/15
B, x=1/3 : 1/2 = 2/3
C, x=(25/8 : 5/4)x4/5 = 5/2 x 4/5 = 2
\(\frac{x}{21}-\frac{2}{3}=\frac{21}{5}\)
=>\(\frac{x}{21}=\frac{21}{5}+\frac{2}{3}\)
=>\(\frac{x}{21}=\frac{73}{15}\)
=>\(x.15=73.21\)
=>\(x.15=1533\)
=>\(x=102,2\)
Vậy x = 102,2
Thực hiện như phép tính bình thường:
21/5 + 2/3 = 53/15.
x = 53