(2x-3).(x^2-5+1) Nhân đa thức với đa thức
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a) (x-1)*(x+2)-(x-3)*(-x+4)=19
\(\Leftrightarrow x^2+2x-x-2-\left(-x^2+4x+3-12\right)=19\)
\(\Leftrightarrow x^2+2x-x-2+x^2-4x-3+12=19\)
\(\Leftrightarrow2x^2-3x+7-19=0\)
\(\Leftrightarrow2x^2-3x-12=0\)
Đề sai??
b) (2x -1)*(3x+5)-(6x-1)*(6x+1)=(-17)
\(\Leftrightarrow6x^2+10x-3x-5-\left(36x^2+6x-6x-1\right)=-17\)
\(\Leftrightarrow6x^2+10x-3x-5-36x^2-6x+6x+1=-17\)
\(\Leftrightarrow-30x^2+7x-4+17=0\)
\(\Leftrightarrow-30x^2+7x+13=0\)
???
(x3 - 2x2 + x - 1)(5 - x) = (x3 - 2x2 + x - 1).5 - [ (x3 - 2x2 + x - 1).x ] = 5x3 - 10x2 + 5x - 5 - (x4 - 2x3 + x2 - x)
= 5x3 - 10x2 + 5x - 5 - x4 + 2x3 - x2 + x = x4 + (5x3 + 2x3) + (-10x2 - x2) + (5x + x) - 5 = x4 + 7x3 - 11x2+ 6x - 5
a. 2x^2 ( 5x^3 - 4x^2 - 7xy + 1 )
= 10x^5 - 8x^4 - 14x^3y + 1
b. ( x - 5 ) ( x + 3 )
= x^2 + 3x - 5x - 15
= x^2 - 2x - 15
c. ( x - 1 ) ( x + 2 )
= x^2 + 2x - x - 2
= x^2 - x - 2
d. ( 2x + y ) ( 2x - y )
= 4x^2 - 2xy + 2xy - y^2
= 4x^2 - y^2
a) \(2x^2\left(5x^3-4x^2.g-7xy+1\right)\)
\(=10x^5-8x^4.g-14x^3y+2x^2\)
b) \(\left(x-5\right)\left(x+3\right)\)
\(=x^2+3x-5x-15\)
\(=x^2-2x-15\)
c) \(\left(x-1\right)\left(x+2\right)\)
\(=x^2+2x-x-2\)
\(=x^2+x-2\)
d) \(\left(2x+y\right)\left(2x-y\right)\)
\(=4x^2-y^2\)
(3 - 2x)(x2 - 2xy + 1) = 3x2 - 6xy + 3 - 2x3 + 4x2y - 2x
Với x = 0
\(\Rightarrow A=\left(0-3\right)\left(0+7\right)-\left(2.0-5\right)\left(0-1\right)\)
\(A=\left(-3\right).7-\left(-5\right)\left(-1\right)\)
\(A=-21+5=-16\)
Với x = 1
\(\Rightarrow A=\left(1-3\right)\left(1+7\right)-\left(2.1-5\right)\left(1-1\right)\)
\(\Rightarrow A=-2.8=-16\)
Với x = -1
\(\Rightarrow A=\left(-1-3\right)\left(-1+7\right)-\left(2.-1-1\right)\)
\(\Rightarrow A=-4.6+3\)
\(\Rightarrow A=-21\)
Với \(x=0\)
\(\Rightarrow A=\left(0-3\right)\left(0+7\right)-\left(2.0-5\right)\left(0-1\right)\)
\(A=\left(-3\right).7-\left(-5\right)\left(-1\right)\)
\(A=-21+5=-16\)
Với \(x=1\)
\(\Rightarrow A=\left(1-3\right)\left(1+7\right)-\left(2.1-5\right)\left(1-1\right)\)
\(\Rightarrow A=-2.8=-16\)
Với \(x=-1\)
\(\Rightarrow A=\left(-1-3\right)\left(-1+7\right)-\left(2.-1-1\right)\)
\(\Rightarrow A=-4.6+3\)
\(\Rightarrow A=-21\)
Bài 1:
b: \(3x-6=x^2-16\)
\(\Leftrightarrow x^2-3x-10=0\)
\(\Leftrightarrow\left(x-5\right)\left(x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=5\\x=-2\end{matrix}\right.\)
Ta có:
(2x – 3) . (x2 – 5x + 1)
= 2x. (x2 – 5x + 1) + (-3). (x2 – 5x + 1)
= 2x . x2 + 2x . (-5x) + 2x . 1 + (-3).x2 + (-3).(-5x) + (-3). 1
= 2x3 + (-10x2 ) + 2x + (-3x2) + 15x + (-3)
= 2x3 + (-10x2 + -3x2) + (2x + 15x) + (-3)
\(A\cdot B=\left(2x^2+3x+5\right)\left(x^2-x+3\right)=2x^4-2x^3+6x^2+3x^3-3x^2+9x+5x^2-5x+15\)
\(A\cdot B=2x^4+x^3+8x^2+4x+15\)
A.B = (2x2 + 3x + 5).(x2 - x + 3)
= 2x2.x2 - 2x2.x + 2x2.3 + 3x.x2 - 3x.x +3x.3 + 5.x2 - 5.x + 5.3
= 2x4 - 2x3 + 6x2 + 3x3 - 3x2 + 9x + 5x2 - 5x + 15
= 2x4 - (2x3 - 3x3) + (6x2 - 3x2 + 5x2) + (9x - 5x) +15
= 2x4 + x3 + 8x2 + 4x +15
`(2x-3)(x^2-5+1)`
`=2x(x^2-5+1)-3(x^2-5+1)`
`= 2x*x^2+2x*(-5)+2x-[3*x^2+3*(-5)+3]`
`= 2x^3-10x+2x-(3x^2-15+3)`
`= 2x^3-10x+2x-3x^2+15-3`
`= 2x^3-3x^2-8x+12`