RÚT GỌN PHÂN SỐ:
A, 18.34+(-18) . 124
-36.17 + 9 . -52
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\(\dfrac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\) =\(\dfrac{18.34-18.124}{9.\left(-4\right).17+9.\left(-52\right)}=\dfrac{18.\left(34-124\right)}{9.\left(-68\right)+9.\left(-52\right)}\) =\(\dfrac{18.\left(-90\right)}{9.\left(-68-52\right)}=\dfrac{18.\left(-90\right)}{9.\left(-120\right)}=\dfrac{3}{2}\)
\(\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}=\frac{18.34-18.124}{9.\left(-4\right)+17+9.\left(-52\right)}=\frac{18.\left(34-124\right)}{9.\left(17-52\right).\left(-4\right)}\)
\(\frac{18.\left(-90\right)}{9.\left(-35\right).\left(-4\right)}=\frac{18.\left(-90\right)}{9.140}=\frac{9.2.\left(-9\right).10}{9.7.2.10}=\frac{-9}{7}\)
\(C=\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}=\frac{18.\left(34-124\right)}{9.\left(-4.17-52\right)}=\frac{18.\left(-90\right)}{9.\left(-120\right)}=\frac{3}{2}\)
\(c=\frac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\)
\(=\frac{18.34+18.\left(-124\right)}{9.-3.17+9.\left(-52\right)}\)
\(=\frac{18.\left(34+\left(-124\right)\right)}{9.\left(-3+17\right).\left(52\right)}\)
tk ủng hộ mk nha!!!!!!!!!!
a)\(\dfrac{3.7.13.37.39-10101}{505050-70707}\)=\(\dfrac{10101.39-10101}{10101.50-10101.7}\)=\(\dfrac{10101.\left(39-1\right)}{10101.\left(50-7\right)}\)=\(\dfrac{39-1}{50-7}\)=\(\dfrac{38}{43}\)
b)\(\dfrac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}\)=\(\dfrac{36.17+36.\left(-62\right)}{36.\left(-17\right)+36.\left(-13\right)}\)=
\(\dfrac{36.\left[17+\left(-62\right)\right]}{36.\left[\left(-17\right)+\left(-13\right)\right]}\)=\(\dfrac{36.\left(-45\right)}{36.\left(-20\right)}\)=\(\dfrac{45}{20}\)=\(\dfrac{9}{4}\)=2\(\dfrac{1}{4}\)
a) \(\dfrac{18.34-18.124}{-36.17+9.\left(-4\right).13}=\dfrac{18.\left(34-124\right)}{-36.\left(17+13\right)}=\dfrac{18.\left(-90\right)}{36.\left(-30\right)}=\dfrac{1.\left(-3\right)}{2.\cdot\left(-1\right)}=\dfrac{3}{2}\)
b) \(\dfrac{393939-10101}{505050-70707}=\dfrac{10101.39-10101}{10101.50-10101.7}=\dfrac{10101.\left(39-1\right)}{10101.\left(50-7\right)}=\dfrac{38}{43}\)
a) \(\dfrac{18.34+\left(-18\right).124}{-36.17+9.\left(-52\right)}=\dfrac{36.17+36.\left(-62\right)}{36.\left(-17\right)+35.\left(-13\right)}=\dfrac{36\left[17+\left(-62\right)\right]}{36\left[\left(-17\right)+\left(-13\right)\right]}=\dfrac{45}{20}=\dfrac{9}{4}\)
b) \(\dfrac{3.7.13.37.39-10101}{505050-70707}=\dfrac{10101.39-10101}{10101.50-10101.7}=\dfrac{10101\left(39-1\right)}{10101\left(50-7\right)}=\dfrac{38}{43}\)
18,34+(-18)x124=18,34+-2232
=2213,66
-36,17+9 x-52= -36,17+468
=431,83