x - \(\frac{26}{11.13}-\frac{26}{13.15}-...-\frac{26}{53.55}=\frac{3}{11}\)
K
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C
11 tháng 1 2020
\(x-\frac{20}{11\cdot13}-\frac{20}{13\cdot15}-\frac{20}{15\cdot17}-......-\frac{20}{53\cdot55}=\frac{3}{11}\)
\(\Leftrightarrow x-10\left(\frac{2}{11\cdot13}-\frac{2}{13\cdot15}-\frac{2}{15\cdot17}-.....-\frac{2}{53\cdot55}\right)=\frac{3}{11}\)
\(\Leftrightarrow x-10\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+....+\frac{1}{53}-\frac{1}{55}\right)=\frac{3}{11}\)
\(\Leftrightarrow x-10\left(\frac{1}{11}-\frac{1}{55}\right)=\frac{3}{11}\)
\(\Rightarrow x=1\)
G6
1
29 tháng 7 2018
\(x-\frac{20}{11.13}-\frac{20}{13.15}-\frac{20}{15.17}-...-\frac{20}{53.55}=\frac{3}{11}\)
\(\Rightarrow x-\left(\frac{20}{11.13}+\frac{20}{13.15}+\frac{20}{15.17}+...+\frac{20}{53.55}\right)=\frac{3}{11}\)
\(\Rightarrow x-\left[10\left(\frac{2}{11.13}+\frac{2}{13.15}+\frac{2}{15.17}+...+\frac{20}{53.55}\right)\right]=\frac{3}{11}\)
\(\Rightarrow x-\left[10\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+...+\frac{1}{53}-\frac{1}{55}\right)\right]=\frac{3}{11}\)
\(\Rightarrow x-\left[10\left(\frac{1}{11}-\frac{1}{55}\right)\right]=\frac{3}{11}\)
\(\Rightarrow x-\left[10.\frac{4}{55}\right]=\frac{3}{11}\)
\(\Rightarrow x-\frac{8}{11}=\frac{3}{11}\)
\(\Rightarrow x=\frac{3}{11}+\frac{8}{11}\)
\(\Rightarrow x=1\)
Vậy x = 1
_Chúc bạn học tốt_
G6
2
18 tháng 8 2018
\(x-\left(\frac{20}{11.13}+\frac{20}{13.15}+....+\frac{20}{53.55}\right)=\frac{3}{11}\)
\(x-10\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{53}-\frac{1}{55}\right)=\frac{3}{11}\)
\(x-10\left(\frac{1}{11}-\frac{1}{55}\right)=\frac{3}{11}\)
\(x-10.\frac{4}{55}=\frac{3}{11}\)
\(x-\frac{8}{11}=\frac{3}{11}\Rightarrow x=\frac{3}{11}+\frac{8}{11}=\frac{11}{11}=1\)
18 tháng 8 2018
\(x-\left(\frac{20}{11\cdot13}+\frac{20}{13\cdot15}+...+\frac{20}{53\cdot55}\right)=\frac{3}{11}\)
Đặt \(x-A=\frac{3}{11}\)
\(\frac{A}{10}=\frac{2}{11\cdot13}+\frac{2}{13\cdot15}+...+\frac{2}{53\cdot55}\)
\(\frac{A}{10}=\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{53}-\frac{1}{55}\)
\(\frac{A}{10}=\frac{1}{11}-\frac{1}{55}\)
\(\frac{A}{10}=\frac{4}{55}\)
\(A=\frac{8}{11}\)
\(\Rightarrow x-\frac{8}{11}=\frac{3}{11}\)
\(\Rightarrow x=\frac{3}{11}+\frac{8}{11}\)
\(\Rightarrow x=1\)
NT
3
HP
21 tháng 2 2016
x-20/11.13-20/13.15-...-20/53.55=3/11
=>x-(20/11.13+20/13.15+...+20/53.55)=3/11
Rồi tính tổng trong ngoặc là OK
D
21 tháng 2 2016
ta có: x-\(\left(\frac{20}{11.13}-\frac{20}{13.15}-...-\frac{20}{53.55}\right)=\frac{3}{11}\)
\(x-\left[20\left(\frac{1}{11.13}-\frac{1}{13.15}-...-\frac{1}{53.55}\right)\right]=\frac{3}{11}\)
\(x-\left[20\left(\frac{2}{11.13}-\frac{2}{13.15}-...-\frac{2}{53.55}\right)\right]=\frac{3}{11}\)
\(x-\left[20\left(\frac{1}{11}+\frac{1}{13}-\frac{1}{13}+...-\frac{1}{53}+\frac{1}{55}\right)\right]=\frac{3}{11}\)
\(x-\left[20\left(\frac{1}{11}+\frac{1}{55}\right)\right]=\frac{3}{11}\)
\(x-\left(\frac{20.6}{55}\right)=\frac{3}{11}\)
\(x-\frac{24}{11}=\frac{3}{11}\)
\(x=\frac{3}{11}+\frac{24}{11}\)
\(x=\frac{27}{11}\)
NT
0
DT
1 tháng 4 2017
x-10( 2/11.13+2/13.15+...+2/53.55)=3/11
x-10(1/11-1/55)=3/11
x-10.4/55=3/11
x-40/55=3/11
x=3/11+40/55
x= 1
10 tháng 4 2018
x-10.(2/11.13+2/13.15+....+2/53.55)=3/11
x-10.(1/11-1/13+...+1/53-1/55)=3/11
x-10.(1/11-1/55)=3/11
x-10.4/55=3/11
x-8/11=3/11
x=1
Nhớ k cho mình nhé
LP
3
21 tháng 3 2016
2x=1/11-1/13.........................-1/53-1/55+3/11
2x=1/11-1/55+3/11
2x=19/55
x=19/55 chia 2
x=19/110