2 mũ 2 . 85 + 40 . 2 mũ 2 - 2 mũ 3
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[(85 - 5) : 2³ + 5²] . 2 - 40
= (80 : 8 + 25) . 2 - 40
= (10 + 25) . 2 - 40
= 35 . 2 - 40
= 70 - 40
= 30
[(85 - 5) : 2³ + 5²] . 2 - 40
= (80 : 8 + 25) . 2 - 40
= (10 + 25) . 2 - 40
= 35 . 2 - 40
= 70 - 40
= 30
\(2^3-5^3:5^2+12\cdot2^2=8-5+48=51\\ 5\left[\left(85-35:7\right):8+90\right]-5\cdot2^2\\ =5\left(80:8+90\right)-20=5\cdot100-20=480\)
85+(-35)+(-12)+(-35)=50+(-12)+(-35)=38+(-35)=3
53.42+85.53-57:54=125.16+85.125-53=125.16+85.125-125
=125.16+85.125-125.1=(16+85-1).125=100.125=12500
b: \(5\cdot\left[\left(85-35:7\right):8+90\right]-5^2\cdot2\)
\(=5\cdot\left[\left(85-5\right):8+90\right]-25\cdot2\)
\(=5\cdot\left(10+90\right)-50\)
=450
\(5^{12}.7-5^{11}.10\)
\(=5^{11}.\left(5.7-10\right)\)
\(=5^{11}.25\)
\(=5^{11}.5^2\)
\(=5^{13}\)
\(2^{20}.15+2^{20}.85\)
\(=2^{20}.5\left(3+17\right)\)
\(=2^{20}.100\)
\(=104857600\)
\(125^3:25^4\)
\(=\left(5^3\right)^3:\left(5^2\right)^4\)
\(=5^9:5^8\)
\(=5\)
\(24^4:3^4-32^{12}:16^{12}\)
\(=\left(24:3\right)^4-\left(32:16\right)^{12}\)
\(=8^4-2^{12}\)
\(=0\)
\(4^{n+2}+4^{n+3}+4^{n+4}+4^{n+5}=85.\left(2^{2019}\div2^{2015}\right)\)
\(\Leftrightarrow4^{n+2}\left(1+4^1+4^2+4^3\right)=85.2^{2019-2015}\)
\(\Leftrightarrow4^{n+2}.85=85.2^4\)
\(\Leftrightarrow4^{n+2}=2^4=4^2\)
\(\Leftrightarrow n+2=2\)
\(\Leftrightarrow n=0\)
Bài 1:
29.(85-47)+85.(47-29)
=29.38+85.18
=1102+1530
=2632
BÀI 2
a, 15x = -75
x =( -75) : 15
x = -5
Vậy x= -5
b,-5x+8=-27
-5x = -27 - 8
-5x= -35
x =-35 : -5
x = 7
Vậy x = 7
c,3.(17 + x ) = - 42
17 + x = - 42 : 3
17 + x = -14
x = - 14 - 17
x = -31
Vậy x = - 31
d,-10 -( 2x -16) = 0
2x - 16 = 10-0
2x - 16 = 10
2x = 10 +16
2x = 26
x = 26 : 2
x = 13
Vậy x = 13
e,( mik ko bít làm)
f,( tự làm nghen bạn)
Lời giải:
$2^2.85+15.2^2-2020^0=4.85+15.4-1$
$=4(85+15)-1=4.100-1=400-1=399$
22.85+15.22−20200=4.85+15.4−122.85+15.22−20200=4.85+15.4−1
=4(85+15)−1=4.100−1=400−1=399
\(2^2.85+40.2^2-2^3\)
\(=2^2.85+40.2^2-2^2.2\)
\(=2^2.\left(85+40-2\right)\)
\(=2^2.123\)
\(=492\)
\(2^{2}.85+40.2^{2}-2^{3}\)
\(=2^{2}.85+40.2^{2}-2^{2+1}\)
\(=2^{2}.85+40.2^{2}-2^{2}.2^{1}\)
\(=2^{2}.(85+40-2)\)
\(=4.123\)
\(=492\)