a - 1,4 x 2 + 7,7
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\(1,0,75-\dfrac{2}{3}-0,5=\dfrac{3}{4}-\dfrac{2}{3}-\dfrac{1}{2}=\dfrac{9}{12}-\dfrac{8}{12}-\dfrac{1}{2}=\dfrac{1}{12}-\dfrac{1}{2}\)
\(=\dfrac{2}{24}-\dfrac{12}{24}=\dfrac{-10}{24}=\dfrac{-5}{12}\)
\(2,\dfrac{1}{5}-0,125-\dfrac{5}{4}=\dfrac{1}{5}-\dfrac{1}{8}-\dfrac{5}{4}=\dfrac{8}{40}-\dfrac{5}{40}-\dfrac{5}{4}=\dfrac{3}{40}-\dfrac{5}{4}\)
\(=\dfrac{3}{40}-\dfrac{50}{40}=\dfrac{-47}{40}\)
\(3,1,25-\dfrac{3}{4}+\dfrac{4}{3}=\dfrac{5}{4}-\dfrac{3}{4}+\dfrac{4}{3}=\dfrac{2}{4}+\dfrac{4}{3}=\dfrac{6}{12}+\dfrac{16}{12}=\dfrac{22}{12}=\dfrac{11}{6}\)
\(4,0,15-\dfrac{1}{4}+\dfrac{2}{5}=\dfrac{3}{20}-\dfrac{1}{4}+\dfrac{2}{5}=\dfrac{3}{20}-\dfrac{5}{20}+\dfrac{2}{5}=\dfrac{-2}{20}+\dfrac{2}{5}\)
\(=\dfrac{-2}{20}+\dfrac{8}{20}=\dfrac{6}{20}=\dfrac{3}{10}\)
\(5,5-3,4+\dfrac{1}{5}=\dfrac{5}{1}-\dfrac{17}{5}+\dfrac{1}{5}=\dfrac{25}{5}-\dfrac{17}{5}+\dfrac{1}{5}=\dfrac{25-17+1}{5}=\dfrac{9}{5}\)
\(6,\dfrac{1}{4}-0,3+\dfrac{4}{3}=\dfrac{1}{4}-\dfrac{3}{10}+\dfrac{4}{3}=\dfrac{10}{40}-\dfrac{12}{40}+\dfrac{4}{3}=\dfrac{-2}{40}+\dfrac{4}{3}\)
\(=\dfrac{-1}{20}+\dfrac{4}{3}=\dfrac{-3}{60}+\dfrac{80}{60}=\dfrac{77}{60}\)
\(7,0,2-3,25+4,7=\dfrac{1}{5}-\dfrac{13}{4}+\dfrac{47}{10}=\dfrac{4}{20}-\dfrac{65}{20}+\dfrac{47}{10}=\dfrac{-61}{20}+\dfrac{47}{10}\)
\(=\dfrac{-61}{20}+\dfrac{94}{20}=\dfrac{33}{20}=1,65\)
\(8,5,4+\dfrac{-7}{3}-\dfrac{-5}{7}=\dfrac{27}{5}+\dfrac{-7}{3}-\dfrac{-5}{7}=\dfrac{81}{15}+\dfrac{-35}{15}-\dfrac{-5}{7}\)
\(=\dfrac{46}{15}-\dfrac{-5}{7}=\dfrac{322}{105}-\dfrac{-75}{105}=\dfrac{397}{105}\)
\(9,\dfrac{-4}{2}+\dfrac{1}{3}-\dfrac{1}{4}=\dfrac{-12}{6}+\dfrac{2}{6}-\dfrac{1}{4}=\dfrac{-10}{6}-\dfrac{1}{4}=\dfrac{-5}{3}-\dfrac{1}{4}\)
\(=\dfrac{-20}{12}-\dfrac{3}{12}=\text{ }\dfrac{-23}{12}\)
\(10,5,4-1,5-\left(7,2-1\right)=3,9-6,2=-2,3\)
\(11,4,9-\left(1,5-7,7+3\right)=4,9-\left(-3,2\right)=8,1\)
\(12,7,8-4,7+\left(5,3-1,4\right)=3,1+3,9=7\)
\(14,\dfrac{1}{2}-0,4+\dfrac{1}{5}\text{=}0,5-0,4+0,2=0,3\)
\(15,4,2-\dfrac{4}{5}+\dfrac{1}{2}=4,2-0,8+0,5=3,9\)
a)\(x\times17,7-7,7\times x=177\)
\(x\times\left(17,7-7,7\right)=177\)
\(x\times10=177\)
\(x=177\div10\)
\(x=17,7\)
b) \(9\times\left(12-2\times x\right)=54\)
\(12-2\times x=54\div9\)
\(12-2\times x=6\)
\(2\times x=12-6\)
\(2\times x=6\)
\(x=6\div2\)
\(x=3\)
c) \(x\times3,9+x\times0,1=16\)
\(x\times\left(3,9+0,1\right)=16\)
\(x\times4=16\)
\(x=16\div4\)
\(x=4\)
a) \(x\times17,7-7,7\times x=177\)
\(x\times\left(17,7-7,7\right)=177\)
\(x\times10=177\)
\(x=177:10\)
\(x=17,7\)
b) \(9\times\left(12-2\times x\right)=54\)
\(12-2\times x=54:9\)
\(12-2\times x=6\)
\(2\times x=12-6\)
\(2\times x=6\)
\(x=6:2\)
\(x=4\)
c) \(x\times3,9+x\times0,1=16\)
\(x\times\left(3,9+0,1\right)=16\)
\(x\times4=16\)
\(x=16:4\)
\(x=4\)
\(#Nulc`\)
`#Ya`
\(a ) ( x + 3 , 5 ) : 7 , 7 = 137 , 7 : 4 , 5\)
\(( x + 3 , 5 ) : 7 , 7 = 30 , 6\)
\(x + 3 , 5 = 30 , 6 × 7 , 7\)
\(x + 3 , 5 = 235 , 62\)
\(x = 235 , 62 − 3 , 5\)
\(x = 232 , 12\)
\(− − − − − − − − − − − − \)
\(x : ( 30 × 4 ) = 7 , 8\)
\(x : 120 = 7 , 8\)
\(x = 7 , 8 × 120\)
\(x = 936\)
a) x . 17,7 - 7,7 . x = 177
\(\Rightarrow\) x . ( 17,7 - 7,7 ) = 177
\(\Rightarrow\) x . 10 = 177
x = 177 : 10
x = 17,7
b) 9 . ( 12 - 2 . x ) = 54
\(\Rightarrow\) 9 . ( 10 . x ) = 54
10 . x = 54 : 9
10 . x = 6
x = 6 . 10
x = 60
\(x.17,7-7,7.x=177\)
\(\Rightarrow x.\left(17,7-7,7\right)=177\)
\(\Rightarrow x.10=177\)
\(\Rightarrow x=177:10=17,7\)
Theo đề a - 2,8 = 7,7
=> a = 7,7 + 2,8 = 10,5
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