Giải giúp mình bài toán này với ạ .
Thực hiện phép tính:
a) 2/67 - (3/7+2/67)
b) 3/4×5/2+5/4×5/2
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\(\frac{3}{5}.\left(\frac{5}{3}-\frac{2}{7}\right)-\left(\frac{7}{3}-\frac{3}{7}\right).\frac{3}{5}\)
\(=\frac{3}{5}.\text{[}\left(\frac{5}{3}-\frac{2}{7}\right)-\left(\frac{7}{3}-\frac{3}{7}\right)\text{]}\)
\(=\frac{3}{5}.\text{[}\frac{5}{3}-\frac{2}{7}-\frac{7}{3}+\frac{3}{7}\text{]}\)
\(=\frac{3}{5}.\text{[}\left(\frac{5}{3}-\frac{7}{3}\right)-\left(\frac{2}{7}-\frac{3}{7}\right)\text{]}\)
\(=\frac{3}{5}.\text{[}\frac{-2}{3}-\frac{-1}{7}\text{]}\)
\(=\frac{3}{5}.\left(\frac{-2}{3}+\frac{1}{7}\right)\)
\(=\frac{3}{5}.\left(\frac{-14}{21}+\frac{3}{21}\right)\)
\(=\frac{3}{5}.\frac{-11}{21}\)
\(=\frac{3.\left(-11\right)}{5.21}\)
\(=\frac{-11}{5.7}=\frac{-11}{35}\)
Chúc bạn học tốt
a) 3/13 - 3/2 + 10/13
= (3/13 + 10/13) - 3/2
= 1 - 3/2
= -1/2
b) 4/7 - (-2/7) - 7/3
= 4/7 + 2/7 - 7/3
= 6/7 - 7/3
= -31/21
c) 2/3 - (-1/6) + 5/4
= 2/3 + 1/6 + 5/4
= 8/12 + 2/12 + 15/12
= 25/12
a, 3/13 - 3/2 + 10/13
= 3/13 + 10/13
= 1 - 3/2 = -1/2
b,4/7 - (-2/7) - 7/3
= 4/7 + 2/7 - 7/3
= 6/7 - 7/3
= 18/21 - 14/21
= 4/21
c, 2/3 - -1/6 +5/4
= 2/3 + 1/16 +5/4
= 128/192 + 12/192 + 240/192
= 380/192
= 95/4
không hiểu chỗ nào hỏi tui
a, \(\left(-17\right)+5+8+17+\left(-3\right)\)
\(=\left(-17+17\right)+\left[5+\left(-3\right)\right]+8\)
\(=0+8+8=8+8=16\)
b, \(\left(5^{19}:5^{17}+3\right):7=\left(5^2+3\right):7\)
\(=\left(25+3\right):7=28:7=4\)
c, \(|-8|+\left(-5\right)+9+\left(-7\right)+|-4|\)
\(=8-5+9-7+4=3+2+4=5+4=9\)
ý d mk ko biết nha.
thông cảm cho mk nha.
k mk nha.
#mon
1: \(\dfrac{4}{23}+\dfrac{5}{21}+\dfrac{1}{2}-\dfrac{4}{23}+\dfrac{16}{21}\)
\(=1+\dfrac{1}{2}\)
\(=\dfrac{3}{2}\)
2: \(\left(\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}\right)-\left(\dfrac{79}{67}-\dfrac{28}{41}\right)\)
\(=\dfrac{1}{3}+\dfrac{12}{67}+\dfrac{13}{41}-\dfrac{79}{67}+\dfrac{28}{41}\)
\(=\dfrac{1}{3}\)
Ta có :
\(A=\frac{3}{4.5}+\frac{3}{5.6}+\frac{3}{6.7}+...+\frac{3}{99.100}\)
\(A=3\left(\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+...+\frac{1}{99.100}\right)\)
\(A=3\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+...+\frac{1}{99}-\frac{1}{100}\right)\)
\(A=3\left(\frac{1}{4}-\frac{1}{100}\right)\)
\(A=3.\frac{6}{25}\)
\(A=\frac{18}{25}\)
Vậy \(A=\frac{18}{25}\)
Chúc bạn học tốt ~
\(A=\frac{3}{4.5}+\frac{3}{5.6}+\frac{3}{6.7}+...+\frac{3}{99.100}\)
\(\Rightarrow A=3.\left(\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+...+\frac{1}{99.100}\right)\)
\(\Rightarrow A=3.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+...+\frac{1}{99}-\frac{1}{100}\right)\)
\(\Rightarrow A=3.\left(\frac{1}{4}-\frac{1}{100}\right)=\frac{3.24}{100}\)
\(=\frac{3.4.6}{25.4}\)
\(\Rightarrow A=\frac{18}{25}\)
\(\dfrac{2}{67}-\left(\dfrac{3}{7}+\dfrac{2}{67}\right)\\ =\dfrac{2}{67}-\dfrac{215}{469}\\ =\dfrac{-3}{7}\)
\(\dfrac{3}{4}.\dfrac{5}{2}+\dfrac{5}{4}.\dfrac{5}{2}\\ =\left(\dfrac{3}{4}+\dfrac{5}{4}\right).\dfrac{5}{2}\\ =2.\dfrac{5}{2}\\ =\dfrac{5}{1}\)