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a)Ta có:
\(\dfrac{90}{160}=\dfrac{90:10}{160:10}=\dfrac{9}{16}=\dfrac{9\times7}{16\times7}=\dfrac{63}{112}\)
\(\dfrac{6}{7}=\dfrac{6\times16}{7\times16}=\dfrac{96}{112}\)
\(\Rightarrow\dfrac{90}{160}< \dfrac{6}{7}\)
b)Ta có:
\(\dfrac{18}{20}=\dfrac{18:2}{20:2}=\dfrac{9}{10}\)
\(\Rightarrow\dfrac{18}{20}>\dfrac{7}{10}\)
a: 90/126=5/7<6/7
b: 70/84=5/6
35/42=5/6
=>70/84=35/42
a)
\(\dfrac{6}{12}=\dfrac{6:6}{12:6}=\dfrac{1}{2}\)
\(\Rightarrow\dfrac{1}{2}=\dfrac{1\times2}{2\times2}=\dfrac{2}{4}\)
Mà \(\dfrac{2}{4}< \dfrac{3}{4}\)
Vậy \(\dfrac{6}{12}< \dfrac{3}{4}\).
b)
\(\dfrac{8}{10}=\dfrac{8:2}{10:2}=\dfrac{4}{5}\)
Mà \(\dfrac{2}{5}< \dfrac{4}{5}\)
Vậy \(\dfrac{2}{5}< \dfrac{8}{10}\).
c)
\(\dfrac{40}{35}=\dfrac{40:5}{35:5}=\dfrac{8}{7}\)
Mà \(\dfrac{8}{7}>\dfrac{6}{7}\)
Vậy \(\dfrac{40}{35}>\dfrac{6}{7}\).
d)
\(\dfrac{8}{16}=\dfrac{8:8}{16:8}=\dfrac{1}{2}\)
Mà \(\dfrac{1}{2}< \dfrac{5}{2}\)
Vậy \(\dfrac{8}{16}< \dfrac{5}{2}\).
Bài 1:
\(\frac{90}{126}=\frac{5}{7};\frac{6}{7}=\frac{6}{7}\)
\(\frac{90}{126}=\frac{5}{7};\frac{35}{49}=\frac{5}{7}\)
Bài 2:
ta có: 8/9 = 0,8888
19/20 = 0,95
10/11 = 0,9090
21/22 = 0,9595
=> 21/22 là phân số lớn nhất
\(\dfrac{5}{7}\)>\(\dfrac{6}{21}\)
\(\dfrac{18}{24}\)>\(\dfrac{15}{25}\)
\(\dfrac{12}{13}\)=\(\dfrac{1212}{1313}\)
\(\frac{5}{7}\)và\(\frac{6}{21}\)
\(\frac{6}{21}=\frac{2}{7}\)
\(\frac{5}{7}>\frac{2}{7}\)
\(\frac{5}{7}\) và \(\frac{6}{21}\)
\(\frac{6}{21}=\frac{2}{7}\)
\(\Rightarrow\frac{5}{7}>\frac{2}{7}\)
a) \(\dfrac{6}{14}=\dfrac{6:2}{14:2}=\dfrac{3}{7}\)
\(\dfrac{3}{7}< \dfrac{4}{7}\)
b) \(\dfrac{6}{15}=\dfrac{6:3}{15:3}=\dfrac{2}{5}\)
\(\dfrac{3}{5}>\dfrac{2}{5}\)
c) \(\dfrac{10}{18}=\dfrac{10:2}{18:2}=\dfrac{5}{9}\)
\(\dfrac{5}{9}>\dfrac{2}{9}\)
a) \(\frac{90}{120}\)=\(\frac{3}{4}\)còn \(\frac{6}{7}\)ta giữ nguyên vì không thể rút gọn
b)\(\frac{90}{126}\)=\(\frac{5}{7}\)còn \(\frac{35}{49}\)thì bằng \(\frac{5}{7}\)
so sánh
a) \(\frac{3}{4}\)<\(\frac{6}{7}\)
b)\(\frac{5}{7}\)=\(\frac{5}{7}\)