4 * 5 = ? ai nhanh m t
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2
a,\(\left(-5\right)^2-\left(5x-3\right)=4^3\)
=>25-5x+3=64
=>25+3-64=5x
=>-36=5x
=>x=-36:5
=>x=-7,2
b,3x-17=x+3
=>3x-x=17+3
=>2x=20
=>x=20:2
=>x=10
\(\dfrac{1}{2}-\dfrac{2}{3}+\dfrac{3}{4}-\dfrac{4}{5}+\dfrac{5}{6}-\dfrac{6}{7}+\dfrac{7}{8}+\dfrac{6}{7}-\dfrac{5}{6}+\dfrac{4}{5}-\dfrac{3}{4}+\dfrac{2}{3}-\dfrac{1}{2}\)
\(=\left(\dfrac{1}{2}-\dfrac{1}{2}\right)+\left(-\dfrac{2}{3}+\dfrac{2}{3}\right)+....+\left(-\dfrac{6}{7}+\dfrac{6}{7}\right)+\dfrac{7}{8}\)
\(=\dfrac{7}{8}\)
Chúc bạn học tốt!!!
\(\dfrac{1}{2}-\dfrac{2}{3}+\dfrac{3}{4}-\dfrac{4}{5}+\dfrac{5}{6}-\dfrac{6}{7}+\dfrac{7}{8}+\dfrac{6}{7}-\dfrac{5}{6}+\dfrac{4}{5}-\dfrac{3}{4}+\dfrac{2}{3}-\dfrac{1}{2}\)
= \((\dfrac{1}{2}-\dfrac{1}{2})+(-\dfrac{2}{3}+\dfrac{2}{3})+...+(-\dfrac{6}{7}+\dfrac{6}{7})+\dfrac{7}{8}\)
=\(\dfrac{7}{8}\)
a) \(15\cdot5+75\cdot5+5\cdot3+5\cdot7\)
\(=5\left(15+75\right)+5\left(3+7\right)\)
\(=5\cdot90+5\cdot10=5\left(90+10\right)=5\cdot100=500\)
b) \(2\cdot200+4\cdot200+4\cdot50+125\cdot8\)
\(=2.2.100+4\cdot200+4\cdot50+125\cdot2\cdot4\)
\(=4\left(100+200+50+250\right)\)
\(=4\cdot600=2400\)
c) \(125\cdot20\cdot80\cdot2\cdot100\cdot5\)
\(=\left(125\cdot8\right)\cdot\left(2\cdot5\right)\cdot100\cdot20\)
\(=1000\cdot10\cdot100\cdot20\)
\(=20000000\)
\(\left(x-2\right)\left(2x+1\right)-5\left(x+3\right)=2x\left(x-3\right)+4\left(1+2x\right)-2\left(1+x\right)\)
\(2x^2+x-4x-2-5x-15=2x^2-6x+4+8x-2-2x\)
\(x-4x-2-5x-15=-6x+4+8x-2-2x\)
\(\Rightarrow-8x-17=2\)
\(-8x=19\Rightarrow x=-\dfrac{19}{8}\)
Vậy \(x=-\dfrac{19}{8}\)
dễ lắm bạn ơi bọn mình học rùi
bn lấy tử số của từng mỗi rồi chia cho mẫu của từng cái rồi rút gọn lafd ra
\(\dfrac{\dfrac{5}{7}+\dfrac{5}{9}+\dfrac{5}{11}}{\dfrac{25}{7}+\dfrac{25}{9}+\dfrac{25}{11}}\cdot\dfrac{4+\dfrac{4}{73}-\dfrac{4}{115}}{5+\dfrac{5}{73}-\dfrac{1}{23}}\)
=\(\dfrac{5\cdot\left(\dfrac{1}{7}+\dfrac{1}{9}+\dfrac{1}{11}\right)}{25\left(\dfrac{1}{7}+\dfrac{1}{9}+\dfrac{1}{11}\right)}\cdot\dfrac{4\left(1+\dfrac{1}{73}+\dfrac{1}{115}\right)}{5+\dfrac{5}{73}-\dfrac{5}{115}}\)
=\(\dfrac{5}{25}\cdot\dfrac{4\left(1+\dfrac{1}{73}-\dfrac{1}{115}\right)}{5\left(1+\dfrac{1}{73}-\dfrac{1}{115}\right)}\)
=\(\dfrac{1}{5}\cdot\dfrac{4}{5}\)=\(\dfrac{4}{25}\)
6a + 5 ⋮ 3a-1
=> 6a - 2 + 7 ⋮ 3a-1
=> 2. (3a - 1) + 7 ⋮ 3a-1
Có: 2. (3a - 1) ⋮ 3a - 1 => Để 6a + 5 ⋮ 3a-1 thì:
7 ⋮ 3a - 1
=> 3a - 1 ∈ Ư(7)
=> 3a - 1 ∈ {1; -1; 7; -7}
=> 3a ∈ {2; 0; 8; -6}
Mà: 3a ⋮ 3 => 3a ∈ {0; -6}
=> a ∈ {0; -2}
Vậy: ................
6a+5⋮3a-1
=>6a-3+8⋮3a-1
=>2(3a-1)+8⋮3a-1
=>8⋮3a-1[vì 3a-1⋮3a-1 nên 2(3a-1)⋮3a-1]
=>3a-1∈Ư(8)={1;2;4;8;-1;-2;-4;-8}
Đến đây làm tiếp đc hơm ??
Làm đc thì tự làm nốt nhé bae
4*5 = 20
tk mk nha mk nhanh nhất đó
4*5=20