5x-16=-46
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- 5x = 46 - 16 - ( - 60 )
=> - 5x = 30 + 60
=> - 5x = 90
=> x = - 18
\(-5x=46-16-\left(-60\right)\)
\(-5x=30+60\)
\(-5x=90\)
\(x=90:\left(-5\right)\)
\(x=-18\)
Học tốt
3:
a: -5x-16=-46
=>-5x=-46+16=-30
=>5x=30
=>\(x=\dfrac{30}{5}=6\)
b: -80-(-16-x)=20
=>\(-x-16=-80-20=-100\)
=>x+16=100
=>x=100-16=84
2:
a: \(\left(45-3456\right)+3456\)
\(=45+3456-3456\)
=45
b: \(\left(77+22-75\right)-\left(-25-78-13\right)\)
\(=77+13+22+78-75+25\)
\(=90+100-50\)
=140
c: \(-25\cdot63-25\cdot37\)
\(=-25\left(63+37\right)\)
\(=-25\cdot100=-2500\)
\(\frac{x+3}{12}+\frac{2x+46}{16}=\frac{3x+9}{36}+\frac{5x+81}{6}\Leftrightarrow\frac{2\left(x+3\right)}{24}+\frac{\frac{3}{2}\left(2x+46\right)}{\frac{3}{2}.16}=\frac{\frac{2}{3}\left(3x+9\right)}{\frac{2}{3}.36}+\frac{4\left(5x+81\right)}{4.6}\)
\(\Leftrightarrow\frac{2\left(x+3\right)}{24}+\frac{3x+69}{24}=\frac{2x+6}{24}+\frac{20x+324}{24}\)\(\Leftrightarrow2x+6+3x+69=2x+6+20x+324\Leftrightarrow17x=-255\Leftrightarrow x=-\frac{255}{17}\)Vậy \(x=-\frac{255}{17}\)
Ta có : \(\dfrac{5x-150}{50}+\dfrac{5x-102}{49}+\dfrac{5x-56}{48}+\dfrac{5x-12}{47}+\dfrac{5x-660}{46}=0\)
\(\Leftrightarrow\dfrac{5x-150}{50}-1+\dfrac{5x-102}{49}-2+\dfrac{5x-56}{48}-3+\dfrac{5x-12}{47}-4+\dfrac{5x-660}{46}+10=0\)
\(\Leftrightarrow\dfrac{5x-200}{50}+\dfrac{5x-200}{49}+\dfrac{5x-200}{48}+\dfrac{5x-200}{47}+\dfrac{5x-200}{46}=0\)
\(\Leftrightarrow\left(5x-200\right)\left(\dfrac{1}{50}+\dfrac{1}{49}+\dfrac{1}{48}+\dfrac{1}{47}+\dfrac{1}{46}\right)=0\)
\(\Leftrightarrow5x-200=0\)
\(\Leftrightarrow x=40\)
Vậy ...
Ta có: \(\dfrac{5x-150}{50}+\dfrac{5x-102}{49}+\dfrac{5x-56}{48}+\dfrac{5x-12}{47}+\dfrac{5x-660}{46}=0\)
\(\Leftrightarrow\dfrac{5x-150}{50}-1+\dfrac{5x-102}{49}-2+\dfrac{5x-56}{48}-3+\dfrac{5x-12}{47}-4+\dfrac{5x-660}{46}+10=0\)
\(\Leftrightarrow\dfrac{5x-200}{50}+\dfrac{5x-200}{49}+\dfrac{5x-200}{48}+\dfrac{5x-200}{47}+\dfrac{5x-200}{46}=0\)
\(\Leftrightarrow\left(5x-200\right)\left(\dfrac{1}{50}+\dfrac{1}{49}+\dfrac{1}{48}+\dfrac{1}{47}+\dfrac{1}{46}\right)=0\)
mà \(\dfrac{1}{50}+\dfrac{1}{49}+\dfrac{1}{48}+\dfrac{1}{47}+\dfrac{1}{46}>0\)
nên 5x-200=0
\(\Leftrightarrow5x=200\)
hay x=40
Vậy: S={40}
a)| x - 3|= 16
Ta có x-3=16 hoặc -16
TH1 TH2
x-3=16 x-3=-16
x = 16+3 x = -16+3
x = 19 x= -13
Vậy x = {19; -13}
b) |x - 3|=39
Ta có : x-3= 39 hoặc - 39
TH1 TH2
x-3=39 x-3=-39
x= 39+3 x= -39 + 3
x= 42 x= -36
Vậy x={42;-36}
a) 125-(-75)+32-(48+32) = 125 + 75 + 32 - 48 - 32 = 200 - 48 = 152
b) 47.347+347.(-47) = 347.( 14 - 47 ) = 347 . 0 = 0
c) x-10=-14
x = -14 +10
x = -4
d) 15 + x = 13
x = 13 - 15
x = -2
e) 25 . x = -75
x = -75/25
x = -3
g) 5x - 16 = -46
5x = -46 + 16
5x = - 30
x = -6
i) 3x - (-11) = -4
3x + 11 = -4
3x = -4 - 11
3x = -15
x = -5
hok tốt!!
(46 - 98)-(46 - 16)-16
= -52 - 30 - 16
= -82 - 16
- -98
_HT_
5x - 16 = -46
5x = -46 + 16
5x = -30
x = -30 : 6
x = -6
lam on h cho minh nha
5x-16=-46
5x=-46+16
5x=-30
x=-6