M=(100-1)(100-2^2)(100-3^2)....(100-50^2)
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\(M=\left(100-1\right)\left(100-2^2\right)...\left(100-50^2\right)\)
\(M=\left(100-1\right)\left(100-2^2\right)...\left(100-10^2\right)...\left(100-50^2\right)\)
\(M=\left(100-1\right)\left(100-2^2\right)...\left(100-100\right)...\left(100-50^2\right)\)
\(M=\left(100-1\right)\left(100-2^2\right)...0...\left(100-50^2\right)\)
\(M=0\)
Ta có:
\(\begin{array}{l}M = \left( {{{10}^2} - 1} \right).\left( {{{10}^2} - {2^2}} \right).\left( {{{10}^2} - {3^2}} \right).\,\,...\left( {{{10}^2} - {{10}^2}} \right)..\,\,.\left( {100 - {{50}^2}} \right)\\ = \left( {{{10}^2} - 1} \right).\left( {{{10}^2} - {2^2}} \right).\left( {{{10}^2} - {3^2}} \right).... 0 ...\left( {100 - {{50}^2}} \right)\\ = 0\end{array}\)
a)( 100 - 1^2 ) * ( 100 - 2^2 ) * ( 100 - 3^2 ) * ...... * ( 100 -50^2 )=( 100 - 1^2 ) * ( 100 - 2^2 ) * ( 100 - 3^2 ) * ...... *(100-10^2)....* ( 100 -50^2 )=( 100 - 1^2 ) * ( 100 - 2^2 ) * ( 100 - 3^2 ) * ...... *(0)....* ( 100 -50^2 )=0
b)1^0 + 1^2 + 1^3+ 1^4 +..........+1^99=1+1+1+1+....+1+1+1(có 100 số 1)=100x1=100
\(M=\left(100-1\right)\left(100-2^2\right)\left(100-3^2\right)...\left(100-50^2\right)\\ =\left(100-1\right)\left(100-2^2\right)\left(100-3^2\right)...\left(100-10^2\right)...\left(100-50^2\right)\\ =\left(100-1\right)\left(100-2^2\right)\left(100-3^2\right)...\left(100-100\right)...\left(100-50^2\right)\)
\(=\left(100-1\right)\left(100-2^2\right)\left(100-3^2\right)...0...\left(100-50^2\right)\\ =0\)
M = (100 – 1).(100 – 22). (100 – 32)…(100 – 502)
M = (100 – 1).(100 – 22). (100 – 32)… (100 – 92) .(100 – 102) .(100 – 112) …(100 – 502)
M = (100 – 1).(100 – 22). (100 – 32)… (100 – 92). (100 – 100) .(100 – 112) …(100 – 502)
M = (100 – 1).(100 – 22). (100 – 32)… (100 – 92) .0.(100 – 112) …(100 – 502)
M = 0
Vậy M = 0