Question

[shi nit chi]

1) Tính nhanh:

 \(10\cdot\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)

Answer 1

[shi nit chi]

giúp mk với

bài này khó quá!

giúp nha

thanks

Answer 2

[✓ ℍɠŞ_ŦƦùM $₦G ✓]

Đầu tiên ta rút gọn \(\frac{4^{^6}.9^{^5}+6^{^9}.120}{8^{^4}.3^{^{12}}-6^{^{11}}}\)= \(\frac{2^{^{12}}.3^{^{10}}+2^{^9}.3^{^9}.2^{^3}.3.5}{2^{^{12}}.3^{^{12}}-2^{^{11}}-3^{^{11}}}\)= \(\frac{2^{^{12}}.3^{^{10}}+2^{^{12}}.3^{^{10}}.5}{2^{^{12}}.3^{^{12}}-2^{^{11}}.3^{^{11}}}\)= \(\frac{2^{^{12}}.3^{^{10}}.\left(1+5\right)}{2^{^{11}}.3^{^{11}}.\left(6-1\right)}\)= \(\frac{2.6}{3.5}\)= \(\frac{12}{15}\)= \(\frac{4}{5}\)

\(\Rightarrow\)10 . \(\frac{4}{5}\)= \(\frac{40}{5}\)= 8