Tìm x
(x - 12).105 = 0
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Ta có: \(-85-\left(x+12\right)+105=0\)
\(\Leftrightarrow20-x-12=0\)
\(\Leftrightarrow8-x=0\)
hay x=8
a, => x-12 = 0
=> x=12
b, => 27-x =1
=> x= 27-1 -26
c, => 2x = 69(4-2) =69.2
=> x=69
d, => x-12=0
=> x=12
a) (x - 12) . 105 = 0
=> x - 12 = 0
=> x = 12
b) 47 . (27 - x) = 47
=> 27 - x = 1
=> x = 27 - 1 = 26
c) 2x + 69 . 2 = 69 . 4
=> 2x = 69 . 4 - 69 . 2
=> 2x = 69 . (4 - 2) = 69 . 2
=> x = 69 . 2 : 2
=> x = 69
d) 2x - 12 - x = 0
=> x - 12 = 0
=> x = 12
P/s : làm từng phần sợ bn ko đợi đc :D
a) ( x - 12 ) x 105 = 0
mà 105 khác 0
=> x - 12 = 0
=> x = 12
b)
2 x x - 69 x 2 = 69 x 4
2 x ( x - 69 ) = 276
x - 69 = 138
x = 207
\(\left(x.7-7\right)\left(x.12+24\right)=0\)
=> \(\orbr{\begin{cases}x.7-7=0\\x.12+24=0\end{cases}}\)
=> \(\orbr{\begin{cases}7x=7\\12x=-24\end{cases}}\)
=> \(\orbr{\begin{cases}x=1\\x=-2\end{cases}}\)
\(170-\left(4+5x\right)=101\)
=> \(4+5x=170-101\)
=> \(4+5x=69\)
=> \(5x=69-4\)
=> \(5x=65\)
=> \(x=65:5=13\)
(x.7-7).(x.12+24)=0
* x.7-7=0 * x.12+24=0
x.7=7 x.12=24
x=7:7 x=24:12
x=1 x=2
vạy x=1 hoặc x=2
170-(4+5x)=101
4+5x=170-101
4+5x=69
5x=69-4
5x=65
x=65:5
x=13
vậy x=13
250:(2x-4)=145-120
250:(2x+4)=25
2x+4=250:25
2x+4=10
2x=10+4
2x=14
x=14:2
x=7
vậy x=7
6.x+3.x-4.x=105
x.(6+3-4)=105
x.(9-4)=105
x.5=105
x=105:5
x=21
vậy x=21
a) (x - 12).105= 0 b) 47. (27 - x) = 94 c) 2x + 69.2 = 69.5
--> x - 12 = 0: 105 --> 27 - x = 94 : 47 = 2 --> 2x + 138 = 345
--> x - 12 = 0 --> 27 - x = 2 --> 2x = 345 - 138
--> x = 0 + 12 --> x = 27 - 2 --> 2x = 207
--> x = 12 --> x = 25 --> x = 207 : 2
vậy x = 12 vậy x bằng 25 --> x = 103,5
vậy x = 103,5
d) (x - 7).(2x - 8)= 0 e) (x + 1)+(x + 2)+...+(x + 10)= 165
--> x - 7 = 0 hoặc 2x - 8 = 0 ( x + x + .... + x ) + ( 1 + 2 + 3 + ..... + 10 ) = 165
--> x = 0 + 7 hoặc 2x = 0 + 8 10x + 52 = 165
--> x = 7 hoặc x = 8 : 2 10x = 165 - 52
--> x = 7 hoặc x = 4 10x = 113
vậy x = 7 hoặc x = 4 x = 113 : 10
x = 11,3
vậy x = 11,3
a) Ta có x thuộc B(4)
=> B(4) = {0;4;8;12;16;20;24;28;32;36;40;44;48;52;56;60;...}
Mà 8 \(\le\)x \(\le\)57 => x \(\notin\){0;4;60}
Vậy x \(\in\){8;12;16;20;....;56}
b) Vì x \(⋮\)12 nên x \(\in\)B(12) = {0; 12 ; 24;36;48;60;72;84;96;108;...}
Mà \(0< x\le105\)nên x \(\in\){12;24;...;96}
a, 38 x x = 12 958
x = 12958 : 38
x = 341
b, x : 255 = 105
x = 105 x 255
x = 26775
1) \(\left(x-273\right)\times38=0\)
\(\Rightarrow x-273=0:38\)
\(\Rightarrow x-273=0\)
\(\Rightarrow x=0+273\)
\(\Rightarrow x=273\)
Vậy x = 273
2) \(\left(179-x\right)-12=57\)
\(\Rightarrow179-x=57+12\)
\(\Rightarrow179-x=69\)
\(\Rightarrow x=179-69\)
\(\Rightarrow x=110\)
Vậy x = 110
3) \(x-105:21=15\)
\(\Rightarrow x-5=15\)
\(\Rightarrow x=15+5\)
\(\Rightarrow x=20\)
Vậy x = 20
4) \(\left(x-105\right):21=15\)
\(\Rightarrow x-105=15\times21\)
\(\Rightarrow x-105=315\)
\(\Rightarrow x=315+105\)
\(\Rightarrow x=420\)
Vậy x = 420
_Chúc bạn học tốt_
1) (x-17)*17=0
x-17=0
x=17
2) 32(x-11)=32
x-11=1
x=12
3) (x-25)-75=0
x-25=75
x=3
4) 575-(6*x+70)=445
6*x+70=130
6*x=60
x=10
5) 315+(125-x)=435
125-x=120
x=5
6) x-105:21=15
x-5=15
x=20
7) (x-105):21=15
x-105=315
x=420
8) (x-38):19=12
x-38=228
x=266
9) (x-15)*(x-19)=0
=>x-15=0 hoặc x-19=0
x=15 hoặc x=19
10) 96-3(x+1)=42
3(x+1)=54
x+1=18
x=17
a) ( x - 17 ) . 17 = 0
=> x - 17 = 0 : 17
=> x - 17 = 0
=> x = 0 + 17
=> x = 17
b) 32 . ( x - 11 ) = 32
=> x - 11 = 32 : 32
=> x - 11 = 1
=> x = 1 + 11
=> x = 12
c) ( x - 25 ) - 75 = 0
=> x - 25 = 0 + 75
=> x - 25 = 75
=> x = 75 + 25
=> x = 100
d) 575 - ( 6 . x + 70 ) = 445
=> 6 . x + 70 = 575 - 445
=> 6 . x + 70 = 130
=> 6 . x = 130 - 70
=> 6 . x = 60
=> x = 60 : 6
=> x = 10
e) 315 + ( 125 - x ) = 435
=> 125 - x = 435 - 315
=> 125 - x = 120
=> x = 125 - 120
=> x = 5
f) x - 105 : 21 = 15
=> x - 5 = 15
=> x = 15 + 5
=> x = 20
g) ( x - 105 ) : 21 = 15
=> x -105 = 15 . 21
=> x - 105 = 315
=> x = 315 + 105
=> x = 420
h) ( x - 38 ) : 19 = 12
=> x - 38 = 12 . 19
=> x - 38 = 228
=> x = 228 + 38
=> x = 266
i) ( x - 15 ) . ( x - 19 ) = 0
=> x - 15 = 0 => x = 0 + 15 => x = 15
x - 19 = 0 => x = 0 + 19 = x = 19
=> x = 15 ; 19
j) 96 - 3( x + 1 ) = 42
=> 3( x + 1 ) = 96 - 42
=> 3( x + 1 ) = 54
=> x + 1 = 54 : 3
=> x + 1 = 18
=> x = 18 - 1
=> x = 17
Ta có :
( x - 12 ) . 105 = 0
=> x - 12 = 0
=> x = 12
(x-12) = 0 : 105
x-12 = 0
x = 0 + 12
x = 12