( x - 78) . 26 =0
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32.(x-10)=32
=>x-10=32:32
=>x-10=1
=>x=11
(x-78).26=0
=>x-78=0:26
=>x-78=0
=>x=78
(x-14):2=3
=>x-14=3.2
=>x-14=6
=>x=14+6
=>x=20
a) 32.(x-10)=32
x-10=1
x=11
b) (x-78).26=0
x-78=0
x=78
c) (x-14):2=3
x-14=6
x=20
Sửa đề: \(\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}=-5\)Ta có: \(\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}=-5\)
\(\Leftrightarrow\dfrac{74-x}{26}+1+\dfrac{75-x}{25}+1+\dfrac{76-x}{24}+1+\dfrac{77-x}{23}+1+\dfrac{78-x}{22}+1=0\)
\(\Leftrightarrow\dfrac{100-x}{26}+\dfrac{100-x}{25}+\dfrac{100-x}{24}+\dfrac{100-x}{23}+\dfrac{100-x}{22}=0\)
\(\Leftrightarrow\left(100-x\right)\left(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}\right)=0\)
mà \(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}>0\)
nên 100-x=0
hay x=100
Vậy: S={100}
Ta có : \(\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}=-5\)
\(\Leftrightarrow\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}+5=0\)
\(\Leftrightarrow\dfrac{74-x}{26}+1+\dfrac{75-x}{25}+1+\dfrac{76-x}{24}+1+\dfrac{77-x}{23}+1+\dfrac{78-x}{22}+1=0\)
\(\Leftrightarrow\dfrac{100-x}{26}+\dfrac{100-x}{25}+\dfrac{100-x}{24}+\dfrac{100-x}{23}+\dfrac{100-x}{22}=0\)
\(\Leftrightarrow\left(100-x\right)\left(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}\right)=0\)
Thấy : \(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}\ne0\)
\(\Rightarrow100-x=0\)
\(\Leftrightarrow x=100\)
Vậy ...
a) (x - 78) .26 = 0 => x - 78 = 0 => x = 78
b) 39 (x - 5) = 39 => x - 5 = 1 => x = 6
c) (x - 14) : 2 = 3 => x - 14 = 6 => x = 20
d) (30 - x) . 4 = 92
=> 30 - x = 92 : 4
=> 30 - x = 23
=> x = 30 - 23 = 7
e) 45(91 - x) = 90
=> 91 - x = 90 : 45
=> 91 - x = 2
=> x = 91 - 2 = 89
f) (2x - 6)(3x - 18) = 0
=> \(\orbr{\begin{cases}2x-6=0\\3x-18=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=6\end{cases}}\)
g) 5x + 73.21 = 73.26
=> 5x = 73.26 - 73.21
=> 5x = 73(26 - 21) = 73.5
=> x = \(\frac{73\cdot5}{5}=73\)
h) 2x - 12 - x = 0
=> 2x - x - 12 = 0
=> x - 12 = 0
=> x = 12
a: =100x26=2600
b: =78x10=780
c: =67x100=6700
d: =1000x575=575000
\(4\times26\times25=\left(4\times25\right)\times26=100\times26=2600\\ 63\times78-53\times78=\left(63-53\right)\times78=10\times78=780\\ 67\times92+67\times8=67\times\left(92+8\right)=67\times100=6700\\ 8\times23\times25\times125=\left(8\times125\right)\times\left(23\times25\right)=1000\times575=57500\)
cái đoạn
Ta thấy:
156 chia hết cho 26
78 chia hết cho 26
Nên ƯCLN(156,78,26) = 26
vậy ƯCLN(156,78,26) = 26
bn nên tìm UCLN rồi suy ra giá trị của x
a/
\(\Leftrightarrow x^2-2xy+y^2+2x^2+10x+26=0\)
\(\Leftrightarrow\left(x-y\right)^2+2\left(x-\frac{5}{2}\right)^2+\frac{27}{2}=0\)
\(VT>0\Rightarrow\) ko tồn tại x; y thỏa mãn
b/
\(\Leftrightarrow4x^2-4x+1+3\left(y^2+10y+25\right)+2=0\)
\(\Leftrightarrow\left(2x-1\right)^2+3\left(y+5\right)^2+2=0\)
\(\Rightarrow\) Không tồn tại x; y thỏa mãn
c/
\(3\left(x^2-4x+4\right)+6\left(y^2-\frac{10}{3}y+\frac{25}{9}\right)+\frac{34}{3}=0\)
\(\Leftrightarrow3\left(x-2\right)+6\left(y-\frac{5}{3}\right)^2+\frac{34}{3}=0\)
Không tồn tại x; y thỏa mãn
bạn c/m cho nó lớn hơn hoặc nhỏ hơn 0 đi mk ngại làm vì hơi nhìu ^.^ sory
bài này chỉ có hsg như tui, alibaba nguyễn, hoàng lê bảo ngọc ..... làm dc
a,\(2,5.16,27.4+7,3=16,27.10+7,3=162,7+7,3=170\)
b,\(8.6.10+4.25.12+3.16.31+2.34.24=48.10+48.25+48.31+48.34\)
\(=48.\left(10+25+31+34\right)=48.100=4800\)
c,\(78.31+78.24+78.17+22.72=78\left(31+24+17\right)+22.72=78.72+22.72\)
\(=72.\left(78+22\right)=72.100=7200\)
d,\(102.67-34.51=102.67-17.102=102.\left(67-17\right)=102.50=5100\)
đéo hiểu thì cút nhé đéo ai khiến m trả lời cả . ngu thì nói ngu đi đừng bày đặt t ghét nhất là cái loại như m đấy ạ
Bài 2
a, \(1-\left(12,5+x-4,25\right):21,75=0\)
\(=>21,75-12,5-x+4,25=0\)
\(=>13,5-x=0=>x=13,5\)
b,\(x.101-x+72.99+72=21050\)
\(=>100x+72.100=21050\)
\(=>100\left(x+72\right)=21050\)
\(=>x+72=210,5\)\(=>x=138,5\)
c,\(151-2\left(x-6\right)=2227:17\)
\(=>151-2\left(x-6\right)=131\)
\(=>2\left(x-6\right)=20\)
\(=>2x=32=>x=16\)
d,\(\left(x+4\right)+\left(x+6\right)+\left(x+8\right)+...+\left(x+26\right)=210\)\(=>12x+\left(4+6+8+...+26\right)=210\)
\(=>12x+180=210=>12x=30\)
\(=>x=\frac{30}{12}=\frac{15}{6}=\frac{5}{2}\)
(x-78).26=0
=>x-78=0
=>x=78