35:x
x:25 & x<100
15:x
x+16:a+1
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=0,25 x X +0,75 x X +X x1=35
=X x (0,25 +0,75 +1)=35
=X x 2=35
X = 35:2
X = 17,5
Bài 1:
Ta có: \(x-35\%\cdot x=\dfrac{1}{25}\)
\(\Leftrightarrow65\%\cdot x=\dfrac{1}{25}\)
\(\Leftrightarrow x=\dfrac{1}{25}:\dfrac{13}{20}=\dfrac{1}{25}\cdot\dfrac{20}{13}=\dfrac{4}{65}\)
Vậy: \(x=\dfrac{4}{65}\)
Bài 2:
a) Ta có: \(17\dfrac{2}{31}-\left(\dfrac{15}{17}+6\dfrac{2}{31}\right)\)
\(=17\dfrac{2}{31}-\dfrac{15}{17}-6\dfrac{2}{31}\)
\(=11+\dfrac{2}{31}-\dfrac{15}{17}\)
\(=\dfrac{5366}{527}\)
\(\dfrac{-12}{25}.\left(\dfrac{3}{4}-x+\dfrac{6}{-11}-\dfrac{5}{6}\right)=0\)
\(\dfrac{3}{4}-x+\dfrac{-6}{11}-\dfrac{5}{6}=0\)
\(\dfrac{3}{4}-x+\dfrac{-91}{66}=0\)
\(\dfrac{3}{4}-x=0-\left(\dfrac{-91}{66}\right)\)
\(\dfrac{3}{4}-x=\dfrac{91}{66}\)
\(x=\dfrac{-83}{132}\)
\(xxx-xx-x-25=443\)\(0\)
\(xxx-xx-x=4430-\)\(25\)
\(xxx-xx-x=4405\)
\(x=4405:5\)
\(x=881\)
\(Thử\)\(lại\)\(:\)
\(881.881.881\)\(-881.881\)\(-881-25\)
\(=683797841\)\(-776161\)\(-881-25\)
\(=683021680-881\)\(-25\)