-5x - [-3] = 13
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\(-5x-\left(-3\right)=13\)
\(-5x+3=13\)
\(-5x=13-3\)
\(-5x=10\)
\(x=10:\left(-5\right)\)
\(x=-2\)
-5x-(-3)=13
-5x+3=13
-5x=13-3
-5x=10
x=10:(-5)
x=-2
nha bạn ^_^
Kids Jonh\(\sqrt[3]{5x+7}+\sqrt[3]{5x-13}=1\)
☘ Đặt \(\sqrt[3]{5x+7}=a\text{ và }\sqrt[3]{5x-13}=b\), ta được hệ phương trình:
\(\left\{{}\begin{matrix}a+b=1\\a^3-b^3=20\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}a=1-b\\\left(1-b\right)^3-b^3=20\left(1\right)\end{matrix}\right.\)
\(\left(1\right)\Leftrightarrow\left(1-3b+3b^2-b^3\right)-b^3=20\)
\(\Leftrightarrow2b^3-3b^2+3b+19=0\)
⚠ Làm tiếp nhé.
-5x-(-3)=13
=> -5x+3=13
=> -5x = 13-3
=> -5x = 10
=> x=10:(-5)
=>x = -2
a) 6x - 3 = 8x + 9
6x = 8x + 9 + 3
6x = 8x + 12
6x - 6x = 8x - 6x + 12
0 = 2x + 12
0 - 12 = 2x
-12 = 2x
2x = -12
x = -12 : 2
x = -6
b) 7x - 5 = 13 - 5x
7x = 13 - 5x + 5
7x = 13 + 5 - 5x
7x = 18 - 5x
7x + 5x = 18 - 5x + 5x
12x = 18 - (5x - 5x)
12x = 18
12x = 18
x = 18 : 12
x = \(\frac{3}{2}\)(hoặc = 1,5)
c) 2 - 3x = 5x + 10
3x = 2 - (5x + 10)
3x = 2 - 5x - 10
3x = 2 - 10 - 5x
3x = -8 - 5x
3x - 3x = -8 - 5x + 3x
0 = -8 - (5x + 3x)
0 = -8 - 8x
-8 - 8x = 0
8x = -8 - 0
8x = -8
x = -8 : 8
x = -1
a) \(x-2=-6\)
\(x=-6+2\)
\(x=-4\)
2) \(-5x-\left(-3\right)=13\)
\(-5x+3=13\)
\(-5x=13-3\)
\(-5x=10\)
\(x=-2\)
3) \(15-\left(x-7\right)=-21\)
\(15-x+7=-21\)
\(22-x=-21\)
\(x=22+21\)
\(x=43\)
b) \(2x-\left(-17\right)=15\)
\(2x+17=15\)
\(2x=15-17\)
\(2x=-2\)
\(x=-1\)
5) \(\left|x-3\right|-7=13\)
\(\left|x-3\right|=20\)
\(\Rightarrow\orbr{\begin{cases}x-3=20\\x-3=-20\end{cases}}\Rightarrow\orbr{\begin{cases}x=23\\x=-17\end{cases}}\)
\(a,\dfrac{2x-1}{3}-\dfrac{5x+2}{7}=x+13\\ \Rightarrow7.\left(2x-1\right)-3.\left(5x+2\right)=21.\left(x+13\right)\\ \Rightarrow14x-7-15x-6=21x+273\\\Rightarrow -x-21x=273+13\\ \Rightarrow-22x=286\\ \Rightarrow x=-13\\ b,\dfrac{3\left(x+3\right)}{4}+\dfrac{1}{2}=\dfrac{5x+9}{3}-\dfrac{7x-9}{4}=0\\ \Rightarrow9.\left(x+3\right)+6=4.\left(5x+9\right)-3.\left(7x-9\right)=0\\\Rightarrow 9x+27+6=20x+36-21x+27\\ \Rightarrow9x+33=-x+63\\ \Rightarrow10x=30\\ \Rightarrow x=3\)
\(a,\dfrac{2x-1}{3}-\dfrac{5x+2}{7}=x+13\)
\(\Rightarrow7\left(2x-1\right)-3\left(5x+2\right)-21x-273=0\)
\(\Rightarrow14x-7-15x-6-21x-273=0\)
\(\Rightarrow-22x=286\)
\(\Rightarrow x=-13\)
\(b,\dfrac{3\left(x+3\right)}{4}+\dfrac{1}{2}=\dfrac{5x+9}{3}-\dfrac{7x-9}{4}\)
\(\Rightarrow9\left(x+3\right)+6-4\left(5x+9\right)+3\left(7x-9\right)=0\)
\(\Rightarrow9x+27+6-20x-36+21x-27=0\)
\(\Rightarrow10x=30\Rightarrow x=3\)
\(-5x-\left[-3\right]=13\)
\(-5x+3=13\)
\(-5x=10\)
\(x=-2\)
-5x + 3=13
-5x = 13-3
-5x = 10
x = 10: -5
x = -2
Vậy x = -2