Tìm số tự nhiên x, biết: 3.23x-1=96
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96 – 3(x + 1) = 42
3(x + 1) = 96 - 42
3(x + 1) = 54
x + 1 = 54:3
x + 1 = 18
x = 18 - 1
x = 17
Vậy x = 17
96 - 3 ( x + 1 ) = 42
3 ( x + 1 ) = 96 - 42
3 ( x + 1 ) = 54
x + 1 = 54 : 3
x + 1 = 18
x = 18 - 1
x = 17
\(96-3\left(x+1\right)=42\)
\(\Rightarrow3\left(x+1\right)=96-42=54\)
\(\Rightarrow x+1=54:3=18\)
\(\Rightarrow x=17\)
96 - 3(x - 1) = 42
3(x -1) = 96 - 42
3(x - 1) = 54
x - 1 = 54 :3
x - 1 = 18
x = 18 + 1
x = 19
`[ ( 2 xx x - 11 ) : 3 + 1 ] xx 5 = 20`
`( 2 xx x - 11 ) : 3 + 1=20:5`
`( 2 xx x - 11 ) : 3 + 1=4`
`( 2 xx x - 11 ) : 3 =4-1`
`( 2 xx x - 11 ) : 3 =3`
`2xx x -11=3xx3`
`2xx x -11=9`
`2xx x =9+11`
`2 xx x=20`
`x=20:2`
`x=10`
Vậy `x=10`
`b, x - 96 = ( 443 - x ) - 15`
`x-96=443-x-15`
` x+x=443-15+96`
`2x=524`
`x=524:2`
`x= 262`
Vậy `x=262`
\(#Nqoc\)
`a)`
\([ ( 2 \times x - 11 ) \div 3 + 1 ] \times 5 = 20\)
`(2 \times x - 11) \div 3 + 1 = 20 \div 5`
`(2 \times x - 11) \div 3 + 1 = 4`
`(2 \times x - 11) \div 3 = 4 - 1`
`(2 \times x - 11) \div 3 = 3`
`2 \times x - 11 = 3 \times 3`
`2 \times x - 11 = 9`
`2 \times x = 9 + 11`
`2 \times x = 20`
`x = 20 \div 2`
`x = 10`
Vậy, `x = 10`
`b)`
\(x - 96 = ( 443 - x ) - 15\)
`x - 96 = 443 - x - 15`
`x - 96 = 428 - x`
`x = 428 - x + 96`
`x = 524 - x`
`x - 524 + x = 0`
`(x + x) - 524 = 0`
`2x - 524 = 0`
`2x = 524`
`x = 524 \div 2`
`x = 262`
Vậy, `x = 262.`
3( x + 23 ) + 6 = 96
3 ( x + 23 ) = 96 - 6
3 ( x + 23 ) = 90
x + 23 = 90 : 3
x + 23 = 30
x = 30 - 23
x = 7
3( x + 23 ) + 6 = 96
3 ( x + 23 ) = 96 - 6
3 ( x + 23 ) = 90
x + 23 = 90 ÷ 3
x + 23 = 30
x = 30 - 23
x = 7
96 - 3( x + 1 ) = 42
3( x + 1 ) = 96 - 42
3( x + 1 ) = 54
x + 1 = 54 : 3 = 18
x = 18 - 1
x = 17
cau 1
96-3(x+1)=42
=> 3(x-1)=54
=> x-1=18
=> x=19
cau 2
12x-33=32.33
=> 12x-33=243
=> 12x=276
=> x=23
a) 12x - 33 = \(3^2.3^3\)
\(\Rightarrow12x-33=3^5\)
\(\Rightarrow12x-33=243\)
\(\Rightarrow12x=243+33\)
\(\Rightarrow12x=276\)
\(\Rightarrow x=276:12\)
\(\Rightarrow x=23\)
b 96 - 3 (x + 10) = 42
\(\Rightarrow3\left(x+10\right)=96-42\)
\(\Rightarrow3\left(x+10\right)=54\)
\(\Rightarrow x+10=54:3\)
\(=>x+10=17\)
\(\Rightarrow x=17-10\)
\(\Rightarrow x=7\)
3.23x-1=96
=>23x-1=96:3=32=25
=>3x-1=5
=>3x=5+1
=>x=6:3
=>x=2