{-15}+{-11}
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\(=\dfrac{-15}{4}.\dfrac{9}{11}+\dfrac{15}{4}.\dfrac{15}{11}-\dfrac{15}{4}.\dfrac{6}{11}\)
= \(\dfrac{15}{4}.\dfrac{-9}{11}+\dfrac{15}{4}.\dfrac{15}{11}-\dfrac{15}{4}.\dfrac{6}{11}\)
= \(\dfrac{15}{4}.\left(\dfrac{-9}{11}+\dfrac{15}{11}-\dfrac{6}{11}\right)\)
= \(\dfrac{15}{4}.\left(\dfrac{6}{11}-\dfrac{6}{11}\right)\)
= \(\dfrac{15}{4}.\left(\dfrac{0}{11}\right)\)
= \(\dfrac{15}{4}.0\)
= 0
= \(\dfrac{11}{15}\). \(\left(\dfrac{4}{11}+\dfrac{5}{11}+\dfrac{2}{11}\right)\)
= \(\dfrac{11}{15}\). 1
=\(\dfrac{11}{15}\)
\(\frac{17}{8}+\frac{28}{15}-\frac{8}{15}=\frac{17}{8}+\frac{4}{3}=\frac{83}{24}=3\frac{11}{24}\)
=> chọn a
\(=\dfrac{12}{15}\times\left(\dfrac{26}{11}-\dfrac{9}{11}-\dfrac{6}{11}\right)=\dfrac{12}{15}\times\dfrac{11}{11}=\dfrac{12}{15}=\dfrac{4}{5}\)
4
tk mk nha bn
sai thì ai thèm k