24:[x+1]=2
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Khách
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22 tháng 2 2021
Ta có: \(\dfrac{x^{24}+x^{20}+x^{16}+...+x^4+1}{x^{26}+x^{24}+x^{22}+...+x^2+1}\)
\(=\dfrac{x^{24}+x^{20}+x^{16}+...+x^4+1}{\left(x^{26}+x^{22}+...+x^2\right)+\left(x^{24}+x^{20}+x^{16}+...+x^4+1\right)}\)
\(=\dfrac{x^{24}+x^{20}+x^{16}+...+x^4+1}{x^2\left(x^{24}+x^{20}+...+1\right)+\left(x^{24}+x^{20}+x^{16}+...+x^4+1\right)}\)
\(=\dfrac{x^{24}+x^{20}+x^{16}+...+x^4+1}{\left(x^{24}+x^{20}+x^{16}+...+1\right)\left(x^2+1\right)}\)
\(=\dfrac{1}{x^2+1}\)
OH
22 tháng 2 2021
x24+x20+x16+...+x4+1x26+x24+x22+...+x2+1x24+x20+x16+...+x4+1x26+x24+x22+...+x2+1
=x24+x20+x16+...+x4+1(x26+x22+...+x2)+(x24+x20+x16+...+x4+1)=x24+x20+x16+...+x4+1(x26+x22+...+x2)+(x24+x20+x16+...+x4+1)
=x24+x20+x16+...+x4+1x2(x24+x20+...+1)+(x24+x20+x16+...+x4+1)=x24+x20+x16+...+x4+1x2(x24+x20+...+1)+(x24+x20+x16+...+x4+1)
=x24+x20+x16+...+x4+1(x24+x20+x16+...+1)(x2+1)
A
2
7 tháng 10 2023
`#3107.101107`
\(48\div24-x=1\\ \Rightarrow2-x=1\\ \Rightarrow x=2-1\\ \Rightarrow x=1\)
Vậy, `x = 1`
____
\(124-2\times\left(x+3\right)=24\\ \Rightarrow2\left(x+3\right)=124-24\\ \Rightarrow2\left(x+3\right)=100\\ \Rightarrow x+3=100\div2\\ \Rightarrow x+3=50\\ \Rightarrow x=50-3\\ \Rightarrow x=47\)
Vậy, `x = 47.`
7 tháng 10 2023
1) 48 : 24 - x = 1 2) 123 - 2 x (x+3) = 24
2-x=1 2 x (x+3) = 123 - 24
x= 2-1 2 x (x+3) = 99
x= 1 x+3 = 99 : 2
x+3 = \(\dfrac{99}{2}\)
x = \(\dfrac{99}{2}\) -3
x = \(\dfrac{93}{2}\)
2 tháng 3 2022
\(a)x=\dfrac{1}{4}+\dfrac{5}{13}=\dfrac{33}{52}.\\ b)\dfrac{x}{3}=\dfrac{2}{3}+\dfrac{-1}{7}.\\ \Leftrightarrow\dfrac{x}{3}=\dfrac{11}{21}.\\ \Leftrightarrow\dfrac{7x}{21}=\dfrac{11}{21}.\\ \Rightarrow7x=11.\\ \Leftrightarrow x=\dfrac{11}{7}.\\ c)\dfrac{x}{3}=\dfrac{16}{24}+\dfrac{24}{36}=\dfrac{2}{3}+\dfrac{2}{3}=\dfrac{4}{3}.\\ \Rightarrow x=4.\\ d)\dfrac{x}{15}=\dfrac{1}{5}+\dfrac{2}{3}=\dfrac{13}{15}.\\ \Rightarrow x=13.\)
L
7 tháng 8 2017
\(\dfrac{24}{x}:\dfrac{8}{3}=\dfrac{3}{5}\)
\(\dfrac{24}{x}=\dfrac{3}{5}.\dfrac{8}{3}\)
\(\dfrac{24}{x}=\dfrac{8}{5}\)
\(\dfrac{24}{x}=\dfrac{24}{15}\)
=>x=5
Vậy x=5
L
7 tháng 8 2017
\(x+3\dfrac{1}{2}+x=24\dfrac{1}{4}\)
\(\left(x+x\right)+3\dfrac{1}{2}=24\dfrac{1}{4}\)
\(x.2+\dfrac{7}{2}=\dfrac{97}{4}\)
\(x.2=\dfrac{97}{4}-\dfrac{7}{2}\)
\(x.2=\dfrac{97}{4}-\dfrac{14}{4}\)
\(x.2=\dfrac{83}{4}\)
\(x=\dfrac{83}{4}:2\)
\(x=\dfrac{83}{4}.\dfrac{1}{2}\)
\(x=\dfrac{83}{8}\)
\(x=10\dfrac{3}{8}\)
9 tháng 1 2018
1, 54 : x - 1 = 5
54 : x = 5+1 = 6
x = 54 : 6 = 9
2, 42 : x + 0 = 8
x = 42 : 8 = 21/4
3, 24 : x - 8 = 0
24 : x = 0 + 8 = 8
x = 24 : 8 = 3
Tk mk nha
14 tháng 4 2023
a: x=-5/11+2/11=-3/11
b: =>x=-3/24+20/24+1/24=18/24=3/4
c: =>5/8-x=1/9+5/4=4/36+45/36=49/36
=>x=5/8-49/36=-53/72
d: =>2/3-x=1/3
=>x=1/3
e: =>1/5:x=12/35
=>x=7/12
PN
1
8 tháng 7 2016
Bài 2: Tìm x:
a. (x + 1) + (x + 2) + (x + 3) = 24 (x + x + x) + (1 +2 + 3) = 24 x × 3 + 6 = 24 x × 3 = 24 - 6 x × 3 = 18 x = 18 : 3 x = 6 | b. x + x + 8 = 24 2 × x + 8 = 24 2 × x = 24 - 8 2 × x = 16 x = 16 : 2 x = 8 |
T
30 tháng 12 2018
\(\frac{x^{24}+x^{20}+...+x^4+1}{x^{26}+x^{24}+...+x^2+1}=\frac{x^{24}+x^{20}+...+x^4+1}{\left(x^{24}+x^{20}+...+x^4+1\right)+\left(x^{26}+x^{22}+...+x^2\right)}\)
\(=1-\frac{x^2\left(x^{24}+x^{20}+...+x^4+x^1\right)}{\left(1+x^2\right)\left(x^{24}+2^{20}+...+x^4+1\right)}=1-\frac{x^2}{1+x^2}\)
\(=\frac{1+x^2-x^2}{1+x^2}=\frac{1}{1+x^2}\)
T
30 tháng 12 2018
Hoặc cách khác:
\(\frac{x^{24}+x^{20}+...+x^4+1}{x^{26}+x^{24}+...+x^2+1}=\frac{x^{24}+x^{20}+...+x^4+1}{\left(x^{24}+x^{20}+...+x^4+1\right)+x^2\left(x^4+x^{20}+...+x^4+1\right)}\)
\(=\frac{x^{24}+x^{20}+...+x^4+1}{\left(x^2+1\right)\left(x^{24}+x^{20}+...+x^4+1\right)}=\frac{1}{x^2+1}\)
7 tháng 8 2017
a) \(\frac{24}{x}:\frac{8}{3}=\frac{3}{5}\) \(\frac{24}{x}=\frac{3}{5}.\frac{8}{3}\) \(\frac{24}{x}=\frac{8}{5}\) \(x=24.5:8\) \(x=15\)
b) Đề bài sai rồi
24 : ( x + 1 ) = 2
x + 1 = 24 : 2
x + 1 = 12
x = 12 - 1
x= 11
tk nha
24 : ( x + 1 ) = 2
x + 1= 24 : 2
x + 1 = 12
x = 12 - 1
x = 11