Đề bài : a. 2018x (\(\dfrac{1}{2}\)+ \(\dfrac{1212}{2424}\))=?
B. 15x \(\dfrac{2121}{4343}\)+ 15 x \(\dfrac{222222}{434343}\)
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\(a,=15\left(\dfrac{2121}{4343}+\dfrac{222222}{434343}\right)=15\left(\dfrac{21}{43}+\dfrac{22}{43}\right)=15\cdot1=15\)
15×2121/4343+15×222222/434343
= 15 x (21x101)/(101x43) + 15x(22x 10101)/(43x10101)
= 15 x 21/43 + 15 x 22/43
= 15x(21/43 + 22/43)
= 15x1 = 15
\(=15x\left(\dfrac{21}{43}+\dfrac{22}{43}\right)=15x1=15\)
=2018
Chi tiết
2018X(1/2+1212/2424)
Rút gon 1212/2424 còn 1/2
1/2+1/2=1
Vậy 2018x1=2018
b. 16×25+44×100/ 29×96+142×48
=400+4×11×100/29×96+71×2×48
=400+400×11/29×96+71×96
=400×(1+11)/96×(29+71)
=400×12/96×100=1/2
\(15x\frac{2121}{4343}+15x\frac{222222}{434343}\)
\(=15x\frac{21}{43}+15x\frac{22}{43}\)
\(=15x\left(\frac{21}{43}+\frac{22}{43}\right)\)
\(=15x1\)
\(=15\)
= 15 x 21/43 + 15x 22/43
= 15 x (21/43 + 22/43)
= 15 x 1 =15
`a)2018xx(1/2+1212/2424)`
`=2018xx(1/2+1/2)`
`=2018xx2/2=2018`
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`b)15xx2121/4343+15xx222222/434343`
`=15xx(2121/4343+222222/434343)`
`=15xx(21/43+22/43)`
`=15xx43/43=15`
a.2018x1=2018
b.15x(21/43+22/43)=15x1=15