Tính bằng cách thuận tiện nhất:7/19×1/3+7/9×2/3
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\(\dfrac{2}{3}+\dfrac{7}{13}-\dfrac{17}{9}+\dfrac{19}{13}-\dfrac{1}{9}+\dfrac{7}{3}\)
\(=\left(\dfrac{2}{3}+\dfrac{7}{3}\right)+\left(\dfrac{7}{13}+\dfrac{19}{13}\right)-\left(\dfrac{17}{9}+\dfrac{1}{9}\right)\)
\(=\dfrac{9}{3}+\dfrac{26}{13}-\dfrac{18}{9}\)
\(=3+2-2\)
\(=3\)
a) \(19\times\left(52+38\right)-9\times\left(52+38\right)=\)
\(=\) \(19\times90-9\times90\)
\(=90\times\left(19-9\right)\)
\(=90\times10\)
\(=900\)
b) \(\dfrac{2}{5}\div\dfrac{3}{7}\times\dfrac{3}{7}\div\dfrac{2}{5}+2019=\)
\(=\left(\dfrac{2}{5}\div\dfrac{2}{5}\right)\times\left(\dfrac{3}{7}\div\dfrac{3}{7}\right)+2019\)
\(=1\times1+2019\)
\(=2019\)
\(\dfrac{7}{19}\times\dfrac{1}{3}+\dfrac{7}{13}\times\dfrac{2}{3}\)
\(=\dfrac{7}{19}\times\left(\dfrac{1}{3}+\dfrac{2}{3}\right)\)
\(=\dfrac{7}{19}\times1\)
\(=\dfrac{7}{19}\)
19/37+1-19/37
=(19/37-19/37)+1
=0+1
=1
9/8-(17/7-3/7)+7/8
=(9/8+7/8)-(17/7-3/7)
=2-2
=0
1/2+3/4+1/2
=(1/2+1/2)+3/4
=1+3/4
=7/4
\(\dfrac{3}{11}\text{×}\dfrac{7}{19}+\dfrac{3}{11}\text{×}\dfrac{10}{19}+\dfrac{3}{11}\text{×}\dfrac{1}{19}=\dfrac{3}{11}\text{×}\left(\dfrac{7}{19}+\dfrac{10}{19}+\dfrac{2}{19}\right)=\dfrac{3}{11}\text{×}1=\dfrac{3}{11}\)
\(\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\left(\dfrac{3}{5}+\dfrac{2}{5}\right)+\left(\dfrac{3}{8}+\dfrac{4}{8}+\dfrac{1}{8}\right)+\left(\dfrac{1}{9}+\dfrac{8}{9}\right)=1+1+1+1=4\)
\(\left(a\right)\frac{3}{5}\cdot\frac{8}{21}\cdot\frac{5}{3}=\left(\frac{3}{5}\cdot\frac{5}{3}\right)\cdot\frac{8}{21}=1\cdot\frac{8}{21}=\frac{8}{21}\)
(b) sai đề
\(\left(c\right)x\cdot\frac{1}{2}=\frac{1}{3}\)
\(x=\frac{\frac{1}{3}}{\frac{1}{2}}=\frac{2}{3}\)
\(\left(d\right)\frac{x}{\frac{4}{5}}=\frac{5}{2}\)
\(x=\frac{5}{2}\cdot\frac{4}{5}=2\)
\(\left(e\right)\frac{\frac{2}{9}}{x}=\frac{2}{3}\)
\(x=\frac{\frac{2}{9}}{\frac{2}{3}}=\frac{1}{3}\)
7/19x(1/3+2/3)
=7/19x1
=7/19
NHỚ K CHO MÌNH NẾU ĐÚNG NHÉ
= 7/19x(1/3+2/3)
= 7/19x1
= 7/19
:)))))))